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#3
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On 3/18/14, 2:39 PM, Mr. Luddite wrote:
On 3/18/2014 2:12 PM, F*O*A*D wrote: On 3/18/14, 1:50 PM, wrote: On Tue, 18 Mar 2014 08:18:15 -0400, "Mr. Luddite" wrote: BTW, the answer to the question I asked is because the two "hot" legs are 180 degrees out of phase relative to each other, so the net current flowing through the neutral leg adds algebraically. The current through the neutral leg can never exceed 200 amperes. Algebra! Holy smoked salmon! ![]() and heavy duty algebra at that. You don't really get to algebra until you start talking about 3 phase and it is actually more like geometry. (vectors) The answer is usually the Sq/Rt of 3 tho. (where "208" comes from) I thought the square root of 3 was 1.7 something or other, though maybe you mean something different, because I don't recall an abbreviation of "Sq/Rt." I do recall sq.rt and sq rt. In three phase power circuits the total wattage is the average voltage of each leg x the average current of each leg x a power factor x the sq.rt of 3 (1.73) Eureka! Thanks. Never knew that. ![]() |
#4
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On 3/18/2014 2:46 PM, F*O*A*D wrote:
On 3/18/14, 2:39 PM, Mr. Luddite wrote: On 3/18/2014 2:12 PM, F*O*A*D wrote: On 3/18/14, 1:50 PM, wrote: On Tue, 18 Mar 2014 08:18:15 -0400, "Mr. Luddite" wrote: BTW, the answer to the question I asked is because the two "hot" legs are 180 degrees out of phase relative to each other, so the net current flowing through the neutral leg adds algebraically. The current through the neutral leg can never exceed 200 amperes. Algebra! Holy smoked salmon! ![]() and heavy duty algebra at that. You don't really get to algebra until you start talking about 3 phase and it is actually more like geometry. (vectors) The answer is usually the Sq/Rt of 3 tho. (where "208" comes from) I thought the square root of 3 was 1.7 something or other, though maybe you mean something different, because I don't recall an abbreviation of "Sq/Rt." I do recall sq.rt and sq rt. In three phase power circuits the total wattage is the average voltage of each leg x the average current of each leg x a power factor x the sq.rt of 3 (1.73) Eureka! Thanks. Never knew that. ![]() Write that down in the notes section of your pocket dictionary. |
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