"iBoaterer" wrote in message
...


You are totally and conveniently forgetting the laws of physics. When
the car loads the two outside tires, thus transferring most of the
force
to half of the contact area (since the two inside tires are doing
virtually no work) that in fact does right the opposite, less contact
area, less traction. The motorcycle, on the other hand because of fact
that it's CG is in line with the vector only causes more friction by
force. And while there is more friction by force on the car's two
outside wheels, there is also less friction by force on the inside
wheels. So, you now have a car with 4 times the mass using about the
same tire contact area as the motorcycle.

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You are talking two different things here. Stiction/Friction
(traction) is one thing. Centrifugal forces due to the turn is
another.
In the case of high speed motorcycle cornering the latter is the
governing issue, traction is secondary (until both the car and the
motorcycle exceeds the limit). The gyroscopic effect of the
motorcycle cannot be overcome by a weight shift by the rider
sufficiently to make a high speed turn as quickly as the car.
Granted, at parking lot speeds a motorcycle can turn faster than a
car, but that's due to it's much shorter turn radius and the absence
of any significant centrifugal force. But at high speeds,
centrifugal force becomes the deciding factor.