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Edgar wrote:
"Jeff" wrote in message ... Edgar wrote: I particularly enjoyed his efforts to convince us that he could prove by trigonometry that a piston travelled further on the upstroke than the downstroke (or maybe it was vice versa) Edgar, sorry to burst your bubble, but this was one case where jaxie was right! The piston travel from 90 degrees to 270 degrees is different from 270 to 90 degrees. This is one of the "bar puzzles" that is counter-intuitive, since we would normally think in terms of upstroke versus downstroke, or 0-180 versus 180-0, which is quite different from "top of cycle" versus "bottom of cycle." (I suppose it depends on which bar you hang out in...) At the risk of starting this thread again I do not think you are correct. The geometry of 90-270 is identical to that of 270-90 and so is 0-180 and 180-0. Oh My! Jaxie hasn't posted here in over 2 years and he's still catching people with this one! The geometry is clearly not the same for the top and bottom parts of the cycle. Draw it out - its just a matter of trig. The piston moves slightly more than half its travel going from 0 (TDC) to 90 degrees. As an interesting degenerate case, consider when the connecting rod is the same length as the crank offset (I forget what that is really called). In that case, the piston will reach the center of the crank at 90 degrees and stay stationary for the entire bottom half of the cycle. |
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