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#1
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![]() wrote in message oups.com... Martin Baxter wrote Now there's a guy I miss, Jax that is. It was great fun let him present himself as an expert and then tear him to shreds. Mundo wrote: Yeah he was pretty easy. Well, I dunno about easy but he was often pretty funny. I used to think that he was actually an attempt by some twisted grad students somewhere to code a usenet chat AI... a spew-bot. If you like to stroll down memory lane, his day-glo words are still hanging in the cyber-air, writ large and full of signs & portents. Actually, a collected edition of his various exchanges here and over on rec.boats.cruising would probably be a million seller. -signed- Injun Ear (formerly known as Eagle Eye) I particularly enjoyed his efforts to convince us that he could prove by trigonometry that a piston travelled further on the upstroke than the downstroke (or maybe it was vice versa) |
#2
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Edgar wrote:
I particularly enjoyed his efforts to convince us that he could prove by trigonometry that a piston travelled further on the upstroke than the downstroke (or maybe it was vice versa) Edgar, sorry to burst your bubble, but this was one case where jaxie was right! The piston travel from 90 degrees to 270 degrees is different from 270 to 90 degrees. This is one of the "bar puzzles" that is counter-intuitive, since we would normally think in terms of upstroke versus downstroke, or 0-180 versus 180-0, which is quite different from "top of cycle" versus "bottom of cycle." (I suppose it depends on which bar you hang out in...) Actually, IIRC the discussion should have had to do with piston velocity, but jaxie lured Nav into this trap. Jaxie had a few of these, a few of them correct, like catenaries, and most bogus, like his understanding of Einstein. |
#3
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Jeff wrote:
Edgar wrote: I particularly enjoyed his efforts to convince us that he could prove by trigonometry that a piston travelled further on the upstroke than the downstroke (or maybe it was vice versa) Edgar, sorry to burst your bubble, but this was one case where jaxie was right! The piston travel from 90 degrees to 270 degrees is different from 270 to 90 degrees. This is one of the "bar puzzles" that is counter-intuitive, since we would normally think in terms of upstroke versus downstroke, or 0-180 versus 180-0, which is quite different from "top of cycle" versus "bottom of cycle." (I suppose it depends on which bar you hang out in...) Actually, IIRC the discussion should have had to do with piston velocity, but jaxie lured Nav into this trap. Jaxie had a few of these, a few of them correct, like catenaries, and most bogus, like his understanding of Einstein. ...and his fictitional dates that he picked up at "21".... |
#4
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![]() "Jeff" wrote in message ... Edgar wrote: I particularly enjoyed his efforts to convince us that he could prove by trigonometry that a piston travelled further on the upstroke than the downstroke (or maybe it was vice versa) Edgar, sorry to burst your bubble, but this was one case where jaxie was right! The piston travel from 90 degrees to 270 degrees is different from 270 to 90 degrees. This is one of the "bar puzzles" that is counter-intuitive, since we would normally think in terms of upstroke versus downstroke, or 0-180 versus 180-0, which is quite different from "top of cycle" versus "bottom of cycle." (I suppose it depends on which bar you hang out in...) At the risk of starting this thread again I do not think you are correct. The geometry of 90-270 is identical to that of 270-90 and so is 0-180 and 180-0. |
#5
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Edgar wrote:
"Jeff" wrote in message ... Edgar wrote: I particularly enjoyed his efforts to convince us that he could prove by trigonometry that a piston travelled further on the upstroke than the downstroke (or maybe it was vice versa) Edgar, sorry to burst your bubble, but this was one case where jaxie was right! The piston travel from 90 degrees to 270 degrees is different from 270 to 90 degrees. This is one of the "bar puzzles" that is counter-intuitive, since we would normally think in terms of upstroke versus downstroke, or 0-180 versus 180-0, which is quite different from "top of cycle" versus "bottom of cycle." (I suppose it depends on which bar you hang out in...) At the risk of starting this thread again I do not think you are correct. The geometry of 90-270 is identical to that of 270-90 and so is 0-180 and 180-0. Oh My! Jaxie hasn't posted here in over 2 years and he's still catching people with this one! The geometry is clearly not the same for the top and bottom parts of the cycle. Draw it out - its just a matter of trig. The piston moves slightly more than half its travel going from 0 (TDC) to 90 degrees. As an interesting degenerate case, consider when the connecting rod is the same length as the crank offset (I forget what that is really called). In that case, the piston will reach the center of the crank at 90 degrees and stay stationary for the entire bottom half of the cycle. |
#6
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![]() "Jeff" wrote in message . .. Edgar wrote: "Jeff" wrote in message ... Edgar wrote: I particularly enjoyed his efforts to convince us that he could prove by trigonometry that a piston travelled further on the upstroke than the downstroke (or maybe it was vice versa) Edgar, sorry to burst your bubble, but this was one case where jaxie was right! The piston travel from 90 degrees to 270 degrees is different from 270 to 90 degrees. This is one of the "bar puzzles" that is counter-intuitive, since we would normally think in terms of upstroke versus downstroke, or 0-180 versus 180-0, which is quite different from "top of cycle" versus "bottom of cycle." (I suppose it depends on which bar you hang out in...) At the risk of starting this thread again I do not think you are correct. The geometry of 90-270 is identical to that of 270-90 and so is 0-180 and 180-0. Oh My! Jaxie hasn't posted here in over 2 years and he's still catching people with this one! The geometry is clearly not the same for the top and bottom parts of the cycle. Draw it out - its just a matter of trig. The piston moves slightly more than half its travel going from 0 (TDC) to 90 degrees. As an interesting degenerate case, consider when the connecting rod is the same length as the crank offset (I forget what that is really called). In that case, the piston will reach the center of the crank at 90 degrees and stay stationary for the entire bottom half of the cycle. That is a situation impossible in practice. If you just draw it out with lines on paper you will find that the piston does not move at all once it is at the centre since everything would just revolve around it. I am beginning to think that you invented Jaxx just to have a bit of fun with us... |
#7
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Edgar wrote:
I particularly enjoyed his efforts to convince us that he could prove by trigonometry that a piston travelled further on the upstroke than the downstroke (or maybe it was vice versa) Edgar, sorry to burst your bubble, but this was one case where jaxie was right! The piston travel from 90 degrees to 270 degrees is different from 270 to 90 degrees. This is one of the "bar puzzles" that is counter-intuitive, since we would normally think in terms of upstroke versus downstroke, or 0-180 versus 180-0, which is quite different from "top of cycle" versus "bottom of cycle." (I suppose it depends on which bar you hang out in...) At the risk of starting this thread again I do not think you are correct. The geometry of 90-270 is identical to that of 270-90 and so is 0-180 and 180-0. Oh My! Jaxie hasn't posted here in over 2 years and he's still catching people with this one! The geometry is clearly not the same for the top and bottom parts of the cycle. Draw it out - its just a matter of trig. The piston moves slightly more than half its travel going from 0 (TDC) to 90 degrees. As an interesting degenerate case, consider when the connecting rod is the same length as the crank offset (I forget what that is really called). In that case, the piston will reach the center of the crank at 90 degrees and stay stationary for the entire bottom half of the cycle. That is a situation impossible in practice. Hmmm. Is it really impossible? I think you might be able to. But it really doesn't matter, its just a degenerate case to show clearly that the geometry is not symmetrical. If you just draw it out with lines on paper you will find that the piston does not move at all once it is at the centre since everything would just revolve around it. The problem in this case is that on the upstroke there is no force that raises the piston. If, however, you made the con-rod a tad longer then it would clearly show almost all of the travel in the top half of the stroke. I am beginning to think that you invented Jaxx just to have a bit of fun with us... I think we all play the game of inventing a "straw man" to argue with. Republicans do it all the time by casting the typical Democrat as an ultraliberal that in truth was only found with a few hundred yards of Harvard or Berkeley for a few milliseconds about 40 years ago. (Actually, every now and then I go to party where I encounter people like that, but then I live only a few miles from Harvard Square.) Jaxie was a living, breathing straw man that gave us all the opportunity to know that we are at least smarter than one person. |
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