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Steven Shelikoff
 
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Default Angle of prop shaft - theoretical question.

On 4 Jun 2004 04:17:35 -0700, (basskisser) wrote:

(Steven Shelikoff) wrote in message ...
On Thu, 3 Jun 2004 12:06:33 -0700, "Gordon" wrote:


"Gary Warner" wrote in message
...

We have an inboard and, of course, the prop shaft exits the hull at an
angle. I just drove by a similar (but different brand) of boat and it
appears it's prop shaft comes out at less of an angle. My first though it
that a angle that gives a more push forward and less push "up" would be

more
efficient. Is that about right??



Yes but the real gain in effiency comes from the fact that the pitch on
the blade on one side now more closely equals the pitch on the opposite
side. This also means it takes less rudder to maintain a straight line and
therefore less drag.


You'll also get less propwalk when reversing the boat with the lesser
shaft angle from horizontal.


Why?


My theory is that , all else being equal, a boat with a greater shaft
angle will have less thrust in the horizontal direction to counteract
the sideways force from the prop paddle-wheeling and at the same time
will increase the sideways "spinning" component of the rotational force
from the prop.

Think of it this way: If you have the shaft completely vertical and
spin the prop, the main motive force will be straight up and not push
the boat anywhere. You've minimized the "paddle-wheel" sideways effect
but that total force is very small. However, you've also maximized the
torque rotational force that will try and spin the boat in the same way
as putting a single mixer blade in a bowl of batter will try and spin
the bowl and that force is huge compared to the paddle-wheel force.

As you lessen the angle of the shaft, you start to increase the sideways
paddle-wheel force but again, that's a very small force. The direction
of the "mixing bowl" rotational force changes from trying to spin the
boat to trying to list the boat. Also, you get more motive force in the
proper direction to allow you to counteract both the "paddle-wheel"
force and the "mixing bowl" force.

When the shaft is completely horizontal, the rotational force is all in
the direction that creates list as you apply power and none is trying to
rotate the boat. I believe this has the greatest effect on reducing prop
walk since the rotational force can be very large. While a small change
in shaft angle has a small effect on the ratio of the vector components
of that force, the total force is so great that a small change in the
ratio of the vectors can have a large effect on the handling of the
boat.

Also, you have the maximum amount of thrust in the proper direction to
help handle the remaining sideways paddle-wheel force, which is the
least of all of them.

That's my theory and I'm sticking with it. lol

Steve
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basskisser
 
Posts: n/a
Default Angle of prop shaft - theoretical question.

(Steven Shelikoff) wrote in message ...
On 4 Jun 2004 04:17:35 -0700,
(basskisser) wrote:

(Steven Shelikoff) wrote in message ...
On Thu, 3 Jun 2004 12:06:33 -0700, "Gordon" wrote:


"Gary Warner" wrote in message
...

We have an inboard and, of course, the prop shaft exits the hull at an
angle. I just drove by a similar (but different brand) of boat and it
appears it's prop shaft comes out at less of an angle. My first though it
that a angle that gives a more push forward and less push "up" would be

more
efficient. Is that about right??



Yes but the real gain in effiency comes from the fact that the pitch on
the blade on one side now more closely equals the pitch on the opposite
side. This also means it takes less rudder to maintain a straight line and
therefore less drag.

You'll also get less propwalk when reversing the boat with the lesser
shaft angle from horizontal.


Why?


My theory is that , all else being equal, a boat with a greater shaft
angle will have less thrust in the horizontal direction to counteract
the sideways force from the prop paddle-wheeling and at the same time
will increase the sideways "spinning" component of the rotational force
from the prop.

Think of it this way: If you have the shaft completely vertical and
spin the prop, the main motive force will be straight up and not push
the boat anywhere. You've minimized the "paddle-wheel" sideways effect
but that total force is very small. However, you've also maximized the
torque rotational force that will try and spin the boat in the same way
as putting a single mixer blade in a bowl of batter will try and spin
the bowl and that force is huge compared to the paddle-wheel force.

As you lessen the angle of the shaft, you start to increase the sideways
paddle-wheel force but again, that's a very small force. The direction
of the "mixing bowl" rotational force changes from trying to spin the
boat to trying to list the boat. Also, you get more motive force in the
proper direction to allow you to counteract both the "paddle-wheel"
force and the "mixing bowl" force.

When the shaft is completely horizontal, the rotational force is all in
the direction that creates list as you apply power and none is trying to
rotate the boat. I believe this has the greatest effect on reducing prop
walk since the rotational force can be very large. While a small change
in shaft angle has a small effect on the ratio of the vector components
of that force, the total force is so great that a small change in the
ratio of the vectors can have a large effect on the handling of the
boat.

Also, you have the maximum amount of thrust in the proper direction to
help handle the remaining sideways paddle-wheel force, which is the
least of all of them.

That's my theory and I'm sticking with it. lol

Steve


I don't agree. If the direction of the prop and shaft, relative to the
centerline of the boat never changes, and the cause of the "prop walk"
is from the rotational force, it would make no difference what the
angle of the prop is relative to the horizon. It could be anywhere
from horizontal, through 90 degrees to horizontal, and the rotational
force would remain the same.
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Steven Shelikoff
 
Posts: n/a
Default Angle of prop shaft - theoretical question.

On 4 Jun 2004 11:32:26 -0700, (basskisser) wrote:

(Steven Shelikoff) wrote in message ...
On 4 Jun 2004 04:17:35 -0700,
(basskisser) wrote:

(Steven Shelikoff) wrote in message ...
On Thu, 3 Jun 2004 12:06:33 -0700, "Gordon" wrote:


"Gary Warner" wrote in message
...

We have an inboard and, of course, the prop shaft exits the hull at an
angle. I just drove by a similar (but different brand) of boat and it
appears it's prop shaft comes out at less of an angle. My first though it
that a angle that gives a more push forward and less push "up" would be

more
efficient. Is that about right??



Yes but the real gain in effiency comes from the fact that the pitch on
the blade on one side now more closely equals the pitch on the opposite
side. This also means it takes less rudder to maintain a straight line and
therefore less drag.

You'll also get less propwalk when reversing the boat with the lesser
shaft angle from horizontal.

Why?


My theory is that , all else being equal, a boat with a greater shaft
angle will have less thrust in the horizontal direction to counteract
the sideways force from the prop paddle-wheeling and at the same time
will increase the sideways "spinning" component of the rotational force
from the prop.

Think of it this way: If you have the shaft completely vertical and
spin the prop, the main motive force will be straight up and not push
the boat anywhere. You've minimized the "paddle-wheel" sideways effect
but that total force is very small. However, you've also maximized the
torque rotational force that will try and spin the boat in the same way
as putting a single mixer blade in a bowl of batter will try and spin
the bowl and that force is huge compared to the paddle-wheel force.

As you lessen the angle of the shaft, you start to increase the sideways
paddle-wheel force but again, that's a very small force. The direction
of the "mixing bowl" rotational force changes from trying to spin the
boat to trying to list the boat. Also, you get more motive force in the
proper direction to allow you to counteract both the "paddle-wheel"
force and the "mixing bowl" force.

When the shaft is completely horizontal, the rotational force is all in
the direction that creates list as you apply power and none is trying to
rotate the boat. I believe this has the greatest effect on reducing prop
walk since the rotational force can be very large. While a small change
in shaft angle has a small effect on the ratio of the vector components
of that force, the total force is so great that a small change in the
ratio of the vectors can have a large effect on the handling of the
boat.

Also, you have the maximum amount of thrust in the proper direction to
help handle the remaining sideways paddle-wheel force, which is the
least of all of them.

That's my theory and I'm sticking with it. lol

Steve


I don't agree. If the direction of the prop and shaft, relative to the
centerline of the boat never changes, and the cause of the "prop walk"


But it is changing. That's the variable we're changing, the angle of
the shaft. I.e., as the shaft angle gets closer and closer to coming
straight out of the boat with no downward angle, the prop walk gets less
and less. Or stated another way, the greater the angle of the shaft the
greater the prop walk. And that's due to the torque of the shaft, which
is applied more and more as a force to rotate the boat as the downward
angle of the shaft is increased. When the shaft is straight back with
no downward angle, the torque force from the shaft causes the boat to
list but doesn't rotate it in the water.

is from the rotational force, it would make no difference what the
angle of the prop is relative to the horizon. It could be anywhere
from horizontal, through 90 degrees to horizontal, and the rotational
force would remain the same.


The rotational force from the prop remains the same. But what it does
to the boat depends on the angle of the shaft relative to the boat. If
the shaft is vertical, it will try and rotate the boat in the horizontal
plane, i.e., prop walk. If the shaft is horizontal, it will try and
rotate the boat in the vertical plane, i.e., list. Anywhere in between
vertical and horizontal and some of the force will try and rotate the
boat while some will cause list with the list increasing and the prop
walk decreasing the closer to horizontal you get.

Steve
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trainfan1
 
Posts: n/a
Default Angle of prop shaft - theoretical question.

Steven Shelikoff wrote:


But it is changing. That's the variable we're changing, the angle of
the shaft. I.e., as the shaft angle gets closer and closer to coming
straight out of the boat with no downward angle, the prop walk gets less
and less. Or stated another way, the greater the angle of the shaft the
greater the prop walk. And that's due to the torque of the shaft, which
is applied more and more as a force to rotate the boat as the downward
angle of the shaft is increased. When the shaft is straight back with
no downward angle, the torque force from the shaft causes the boat to
list but doesn't rotate it in the water.



The rotational force from the prop remains the same. But what it does
to the boat depends on the angle of the shaft relative to the boat. If
the shaft is vertical, it will try and rotate the boat in the horizontal
plane, i.e., prop walk. If the shaft is horizontal, it will try and
rotate the boat in the vertical plane, i.e., list. Anywhere in between
vertical and horizontal and some of the force will try and rotate the
boat while some will cause list with the list increasing and the prop
walk decreasing the closer to horizontal you get.

Steve


Using your theory, Steve, the stern would walk the same way whether the
prop was a left hand or right hand wheel... and this is not the case.

I have always been under the impression, on straight inboards, that the
lower half of the propellor, the arc furthest from the boat/hull
surface, is the one that does the most work/thrust (eg. surface piercing
drives, etc.). The prop has better "bite" in the less turbulent water
away from the hull. This has been my experience too...

Correct Craft & Century inboards: RH prop, walks to port in reverse,
favors left turns in forward... (the opposite of your explanation if
taken to the extreme of a 90 degree propshaft angle).

Mastercraft inboard: LH prop, walks to starboard in reverse, favors
right turns in forward. (again, the opposite of your explanation if
taken to the extreme of a 90 degree propshaft angle).

The rotational force of the shaft/prop is transferred primarily to the
attitude of the boat on a single screw craft.

Rob
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Steven Shelikoff
 
Posts: n/a
Default Angle of prop shaft - theoretical question.

On Sat, 05 Jun 2004 11:06:08 -0400, trainfan1
wrote:

Steven Shelikoff wrote:


But it is changing. That's the variable we're changing, the angle of
the shaft. I.e., as the shaft angle gets closer and closer to coming
straight out of the boat with no downward angle, the prop walk gets less
and less. Or stated another way, the greater the angle of the shaft the
greater the prop walk. And that's due to the torque of the shaft, which
is applied more and more as a force to rotate the boat as the downward
angle of the shaft is increased. When the shaft is straight back with
no downward angle, the torque force from the shaft causes the boat to
list but doesn't rotate it in the water.



The rotational force from the prop remains the same. But what it does
to the boat depends on the angle of the shaft relative to the boat. If
the shaft is vertical, it will try and rotate the boat in the horizontal
plane, i.e., prop walk. If the shaft is horizontal, it will try and
rotate the boat in the vertical plane, i.e., list. Anywhere in between
vertical and horizontal and some of the force will try and rotate the
boat while some will cause list with the list increasing and the prop
walk decreasing the closer to horizontal you get.

Steve


Using your theory, Steve, the stern would walk the same way whether the
prop was a left hand or right hand wheel... and this is not the case.


Actually, no it wouldn't. The torque is in a different direction
depending on whether the prop is right or left handed so the boat would
turn in a different direction.

I have always been under the impression, on straight inboards, that the
lower half of the propellor, the arc furthest from the boat/hull
surface, is the one that does the most work/thrust (eg. surface piercing
drives, etc.). The prop has better "bite" in the less turbulent water
away from the hull. This has been my experience too...


This is true. That's one of the causes of prop walk, not the only one
though. That's why a boat with the prop further from the hull will have
less prop walk. But that's not what the question was. The question is
why a small change in the shaft angle (say only 10 or 20 degrees) will
have a dramatic effect on the amount of prop walk. To have that large
an effect with such a small change you have to have a large total force
and the one you mentioned above creates a very small force. But when
the shaft is completely horizontal, it's the main propellor related
force causing prop walk. Tilt the shaft down a little and it becomes
overwhelmed by the torque force.

Correct Craft & Century inboards: RH prop, walks to port in reverse,
favors left turns in forward... (the opposite of your explanation if
taken to the extreme of a 90 degree propshaft angle).


But the prop shaft is not 90 degrees. If it were, the boat would turn
opposite the direction of the prop since it's the only prop related
force being applied. Also, not all boats with a RH prop will walk the
same way. It depends on the specific configuration of the boat
including shaft angle, type of prop, how far the prop is from the hull,
etc. My boat is a single screw inboard with a right hand prop and it
backs to starboard with a pretty severe case of prop walk.

Mastercraft inboard: LH prop, walks to starboard in reverse, favors
right turns in forward. (again, the opposite of your explanation if
taken to the extreme of a 90 degree propshaft angle).


Same comments as above.

The rotational force of the shaft/prop is transferred primarily to the
attitude of the boat on a single screw craft.


Exactly what I said. i.e., the torque from the prop will primarily
cause the boat to list when the shaft is at or near horizontal. As you
increase the downward angle (or upward angle for that matter although I
don't know of many boats with an upward pointing shaft) the rotation
force from the shaft/prop will more and more cause the boat to rotate
and less and less cause the attitude (list) to change.

You can realize just how much rotational force from the shaft/prop there
is since it's big enough to cause a noticable list. Apply the same size
force from the paddle wheel affect in the direction to cause list and
you probably won't notice a thing.

I'll agree that on most boats, the rotational force from the torque of
the prop/shaft is not the main contributor to prop walk and is a much
greater contributor to list. But what we're talking about here is what
forces that contribute to prop walk change as the shaft angle changes.
And the torque effect certainly does.

Steve


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Steven Shelikoff
 
Posts: n/a
Default Angle of prop shaft - theoretical question.


Another P.S.

The change in direction of applied force from the torque of the
prop/shaft is only one part of the theory. The rest is the change in
the amout of paddle wheel effect as the angle changes as well as a
change in the amout of available thrust in the proper direction to
counteract the prop walk as the shaft angle changes.

I'm always willing to adjust the theory.

Steve
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JAXAshby
 
Posts: n/a
Default Angle of prop shaft - theoretical question.

steve, bone up on "P-torque" or "P-thrust" or more accurately "asymetrical
thrust". It is a common problem for aircraft with "conventional" landing gear
(meaning two wheels up front and one on the tail), and has been fully
understood since the early days of WWII.

Another P.S.

The change in direction of applied force from the torque of the
prop/shaft is only one part of the theory. The rest is the change in
the amout of paddle wheel effect as the angle changes as well as a
change in the amout of available thrust in the proper direction to
counteract the prop walk as the shaft angle changes.

I'm always willing to adjust the theory.

Steve








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JAXAshby
 
Posts: n/a
Default Angle of prop shaft - theoretical question.

gene, you are one horse**** pilot, if you are any pilot at all, for not being
able to tell the difference between conventional gear and trikes.

Let me inform you a tad. when the aircraft is rolling with the tail down, the
angle of attack one side of the prop circle is greater than on the other side,
because of the forward movement of the craft. The side of the prop with great
a of a developes more thrust and pulls the aircraft forward faster than the
other side of the prop. than means the aircraft pulls to one side. This is
often (erroneously) referred to a P-Torque, because it feels like the engine is
torqueing the aircraft to the side. In fact, it is P-Thrust, or asymetrical
thrust that is causing the aircraft to veer.

be carefull, gene. Remember what the FAA taught you, "Safety is no accident".

You need to do some boning up on your pilot skills, gene, or maybe hang up your
googles.

(JAXAshby) wrote:

steve, bone up on "P-torque" or "P-thrust" or more accurately "asymetrical
thrust". It is a common problem for aircraft with "conventional" landing

gear
(meaning two wheels up front and one on the tail), and has been fully
understood since the early days of WWII.


So..... what conundrum of JaxWorld prevents this from affecting
tricycle gear aircraft, as well?? (Sure takes a lot of right rudder
to keep every aircraft, conventional or tricycle, I have flown on the
center line.) You *do* realize, of course, that most of the forces
felt in this regard are from propeller swirl impinging upon the
vertical stabilizer?

And, that said, given the arm of a 16" boat screw vs a 8 foot or
better aircraft propeller, it makes the effect of P-factor minimal, at
best, in a nautical scenario (unless, of course, you would like to
include things like WWII battleship propellers, just to prove the
laboratory experience in deference to real life).
--
23' Grady White, out of Southport, NC.

http://myworkshop.idleplay.net/cavern/ Homepage
http://www.southharbourvillageinn.com/directions.asp Where Southport,NC is
located.
http://southharbourvillageinn.linksysnet.com Real Time
Pictures at My Marina
http://www.thebayguide.com/rec.boats Rec.boats at
Lee Yeaton's Bayguide









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