Home |
Search |
Today's Posts |
|
#1
|
|||
|
|||
Math help - cubic feet
OK, I need some help from the rbp math whizzes. I'm trying to figure
out the cubic feet volume to a triangular enclosure in the shape of a traditional A-frame tent (but a bit shorter). Dimensions are 7' wide at the base, 7' from the base to the peak and 4 1/2" long. How many cubic feet is that? I'm stumped. |
#2
|
|||
|
|||
|
#3
|
|||
|
|||
Dave Filpus wrote in message
if feet then 4.5' * ( 7' * 7' / 2 ) = 110.25 cu ft Thanks Dave, That was all in feet (7x7x4.5). I filled a bit less than half of the available space in our new A-frame woodhshed last weekend with firewood and wondered how close to a cord (128 cu ft) I came. Look like the shed will hold 2 cords if filled completly. |
#4
|
|||
|
|||
Since you are dealing with a triangle, the easy way is to drop a line
from the apex, cut it in half, and turn one half upside down and flop it over the otherside. You now have a rectangle 3 1/2*7 or 24.5 square feet for the area of the end. Then multiply that by the length in feet and you have the volume. if the length is 4.5 inches = 4.5/12 or .375 foot, the volume is 24.5x.375=9.1875 cu ft. Or if you really meant 4.5 feet, 110.25 cu ft. B=triangle base length * = times H=height of triangle L=length of object V=1/2*B*H*L Dan On Mon, 08 Nov 2004 14:06:59 GMT, Dave Filpus wrote: In article , (Mike McCrea) wrote: OK, I need some help from the rbp math whizzes. I'm trying to figure out the cubic feet volume to a triangular enclosure in the shape of a traditional A-frame tent (but a bit shorter). Dimensions are 7' wide at the base, 7' from the base to the peak and 4 1/2" long. How many cubic feet is that? I'm stumped. Did you mean 4 1/2 inches or feet? volume = length * (width * height / 2) if feet then 4.5' * ( 7' * 7' / 2 ) = 110.25 cu ft if inches then 0.375' ( 7' * 7' / 2 ) = 9.1875 cu ft |
#6
|
|||
|
|||
7x7/2*4.5=110.25
"Mike McCrea" wrote in message om... OK, I need some help from the rbp math whizzes. I'm trying to figure out the cubic feet volume to a triangular enclosure in the shape of a traditional A-frame tent (but a bit shorter). Dimensions are 7' wide at the base, 7' from the base to the peak and 4 1/2" long. How many cubic feet is that? I'm stumped. |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|
Similar Threads | ||||
Thread | Forum | |||
22 Feet 1949 Chris Craft Sportsman 22-U | General | |||
Bought a Reinel 26' | ASA | |||
Angle of prop shaft - theoretical question. | General | |||
Is sailing becoming extinct? | General | |||
boat shoes for fat feet | Cruising |