Since you are dealing with a triangle, the easy way is to drop a line
from the apex, cut it in half, and turn one half upside down and flop
it over the otherside. You now have a rectangle 3 1/2*7 or 24.5
square feet for the area of the end. Then multiply that by the length
in feet and you have the volume. if the length is 4.5 inches = 4.5/12
or .375 foot, the volume is 24.5x.375=9.1875 cu ft.
Or if you really meant 4.5 feet, 110.25 cu ft.
B=triangle base length * = times
H=height of triangle
L=length of object
V=1/2*B*H*L
Dan

On Mon, 08 Nov 2004 14:06:59 GMT, Dave Filpus
wrote:

In article ,
(Mike McCrea) wrote:

OK, I need some help from the rbp math whizzes. I'm trying to figure
out the cubic feet volume to a triangular enclosure in the shape of a
traditional A-frame tent (but a bit shorter).

Dimensions are 7' wide at the base, 7' from the base to the peak and 4
1/2" long.

How many cubic feet is that? I'm stumped.
Did you mean 4 1/2 inches or feet?

volume = length * (width * height / 2)

if feet then 4.5' * ( 7' * 7' / 2 ) = 110.25 cu ft
if inches then 0.375' ( 7' * 7' / 2 ) = 9.1875 cu ft