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Lew Hodgett
 
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The following was given to me by a Trojan application engineer who at
the time was older than dirt and had been at his trade for a long time.

1) Every 100 AH consumed from a wet cell battery requires 125 AH to
replace it.

2) From a design stand point, a battery bank will absorb on average,
about 15% of the total AH capacity, from the alternator over an extended
period.

Want to supply 150A from the alternator, you need a 1,000 AH bank to
accept it.
If you consume 500 AH and then want to replace them, you must supply
500*125%=625 AH which will require 625AH/150A=4.18 hours.

No matter how you cut it, wet cell batteries are not efficient, but they
are convenient.

Having myself been involved in the low voltage DC business for a while,
thought he gave me pretty good advice.

Lew



 
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