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The following was given to me by a Trojan application engineer who at the time was older than dirt and had been at his trade for a long time. 1) Every 100 AH consumed from a wet cell battery requires 125 AH to replace it. 2) From a design stand point, a battery bank will absorb on average, about 15% of the total AH capacity, from the alternator over an extended period. Want to supply 150A from the alternator, you need a 1,000 AH bank to accept it. If you consume 500 AH and then want to replace them, you must supply 500*125%=625 AH which will require 625AH/150A=4.18 hours. No matter how you cut it, wet cell batteries are not efficient, but they are convenient. Having myself been involved in the low voltage DC business for a while, thought he gave me pretty good advice. Lew |
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