yes I know, that is the point (no pun intended)
Scout

"JAXAshby" wrote in message
...
a dot is not a vector.

that's what I was thinking but didn't want to assume anything : )
Scout

"Remco Moedt" wrote in message
.. .
On Sun, 04 Jul 2004 04:53:15 GMT, "Bart Senior"
wrote:

You sail directly East for 14 hours,
then South for 14 hours,
and then West for 14 hours,
and then North again for 14 hours.

Now if you draw a vector between your starting
position and your final position. What would you
call that vector?

A dot. :-)


Cheers!


Remco

Bart Senior wrote:

Now if you draw a vector between your starting
position and your final position. What would you
call that vector?

Track made good.


--
Wally
www.artbywally.com
www.wally.myby.co.uk

Capt. Mooron wrote:

To be accurate you would need the start and end coordinates. The
vector between the 2 if any could be calculated.... but the point is
moot. If all speeds and bearings [no leeway] were constant you would
be at your starting point.

Speeds haven't been stated, so they can't be assumed to be constant.


I believe Bart is having some fun! ;-)

The spanner in the works is idea that it's a round trip.


--
Wally
www.artbywally.com
www.wally.myby.co.uk

"Wally" wrote in message
...
| Capt. Mooron wrote:
|
| To be accurate you would need the start and end coordinates. The
| vector between the 2 if any could be calculated.... but the point is
| moot. If all speeds and bearings [no leeway] were constant you would
| be at your starting point.
|
| Speeds haven't been stated, so they can't be assumed to be constant.

Without the speeds you have no position to calc a vector... thus constant
speed must be assumed.

|
|
| I believe Bart is having some fun! ;-)
|
| The spanner in the works is idea that it's a round trip.

Without the speeds that determination can neither be assumed nor denied.

Of course the vector could be 0 degrees T. ;-)

CM

Capt. Mooron wrote:

Speeds haven't been stated, so they can't be assumed to be constant.

Without the speeds you have no position to calc a vector... thus
constant speed must be assumed.

ISTM that speed is unknown, so no assumption can be made.


I believe Bart is having some fun! ;-)
The spanner in the works is idea that it's a round trip.

Without the speeds that determination can neither be assumed nor
denied.

I meant that the wording of the question is such that the unwary might
assume that it is a round trip - which it could be - but it might not be.
The vector can be anything, IOW, so I think he's looking for the name of the
resultant vector, and not its magnitude.


--
Wally
www.artbywally.com
www.wally.myby.co.uk

our physics professor used to smack our knuckles for saying speed and not
velocity. What a grump.
Scout

"Capt. Mooron" wrote in message
...

"Wally" wrote in message
...
| Capt. Mooron wrote:
|
| To be accurate you would need the start and end coordinates. The
| vector between the 2 if any could be calculated.... but the point is
| moot. If all speeds and bearings [no leeway] were constant you would
| be at your starting point.
|
| Speeds haven't been stated, so they can't be assumed to be constant.

Without the speeds you have no position to calc a vector... thus constant
speed must be assumed.

|
|
| I believe Bart is having some fun! ;-)
|
| The spanner in the works is idea that it's a round trip.

Without the speeds that determination can neither be assumed nor denied.

Of course the vector could be 0 degrees T. ;-)

CM

"Wally" wrote in message

| I meant that the wording of the question is such that the unwary might
| assume that it is a round trip - which it could be - but it might not be.
| The vector can be anything, IOW, so I think he's looking for the name of
the
| resultant vector, and not its magnitude.


Astute.... but COG has been deprived of SOG and my ETA is now as dubious as
my DR ... now I need a drink of Rhumb! :-)

CM

btw - I've used my saved sailing gps tracks in the classroom - the physics
teacher projected them onto the board and had the students work out vectors
and so forth.
Scout

"Bart Senior" wrote in message
. ..
You sail directly East for 14 hours,
then South for 14 hours,
and then West for 14 hours,
and then North again for 14 hours.

Now if you draw a vector between your starting
position and your final position. What would you
call that vector?

So what did your Prof refer to the vector between your departure coordinates
and your arrival coordinates?

CM

"Scout" wrote in message
...
| btw - I've used my saved sailing gps tracks in the classroom - the physics
| teacher projected them onto the board and had the students work out
vectors
| and so forth.
| Scout
|
| "Bart Senior" wrote in message
| . ..
| You sail directly East for 14 hours,
| then South for 14 hours,
| and then West for 14 hours,
| and then North again for 14 hours.
|
| Now if you draw a vector between your starting
| position and your final position. What would you
| call that vector?
|
|
|
|

Capt. Mooron wrote:

Astute.... but COG has been deprived of SOG and my ETA is now as
dubious as my DR ... now I need a drink of Rhumb! :-)

I now realise that the whole journey is a red herring - he never said
anything about the final position being worked out as a DR. It could just as
easly be observed or GPS. He might as well have said...

You start at X, sail about for a bit, and finish at Y.
What's the vector from X to Y called?


--
Wally
www.artbywally.com
www.wally.myby.co.uk