jeff the *real* problem was what kind of counter-current was needed to change a
boat's course by a large amount.

That question was answered within minutes by the very first repsonder (me).
After that, the posts got playful as to what precision -- not accuracy -- that
a "little over 7 knots" could be.

you, on the other hand, concerned yourself with precision calculations on
imprecise -- and unknowably precise -- assumptions.

in other words, you didn't understand the question, only the need for
complexity.

The simple and original answer was understood by everyone -- but you -- without
regard to their understanding of, let alone the capability of calculating, the
lengths of non-square triangles.

Yes, if you can't solve the real problem you can make an approximation.
What's
your point? You don't know how to solve the real problem? We already know
that.


"JAXAshby" wrote in message
...
the square root of 50 was in fact important to the discussion, but it seems
you
still don't know why.

go back and re-read the post again and again and again and again until you
see
why. (hint: 5^2 + 5^2 = 50)





Hey Jax, how come you didn't get the right answer to the question? I did.
I
then provided the appropriate formulae. All you did was babble about
"components" and then give the wrong answer. You went on for 4 posts
about
the
"square root of 50" which isn't relevant to the problem.

You're right, you can't have a "rational discussion" with me, or with
anyone
else.

BTW, one doesn't describe a current by which direction is comes from, one
describes it by which direction its going. Take the Power Squadron
course,
really.






"JAXAshby" wrote in message
...
jeffies, it is near impossible to have a rational discussion with you,
as
you
once AGAIN show you have zero understanding of either the issue or the
resultant answer.

you really, really, really don't understand the question, i.e. how much
current
and from which direction would be needed to cause a boat to change
course
by
some large angle.

you, you blithering idiot, are rambling on and on and on and on hoping
against
all hope that newbies will forget that you motor training wheels while
Walter
Mittying yourself to be Shackleton.

Yes I know you "think" you answered the question, just like you "think"
you're a
member of Mensa, and you "think" you graduated high school.

But saying that the answer is something that has a collection of
components
is
NOT showing that you actually know how to compute such a collection.
The
fact
that you keep insisting you solved it proves you don't really know how
to
do
it.
And being able to guess within 15% isn't bad, but doesn't show you know
how
to
navigate.



"JAXAshby" wrote in message
...
I know that *you* don't understand, jeffies, but the problem really
was
answered comprehensively within a few minutes of the question being
posted.

jeffie, rational discussion with you is near to impossible, for you
are
not
only much lacking in mental candlepower you are also so lacking in
such
you
are
not even capable of understanding just how lacking.

don't buy an EPIRB, jeffie. Let Darwin help you sail, if you ever do
decide
to
sail in lieu motoring.

I think I gave the answer to the "math problem."

As to whether this current can e











Hey Jax, how come you didn't get the right answer to the question? I did.
I
then provided the appropriate formulae. All you did was babble about
"components" and then give the wrong answer. You went on for 4 posts
about
the
"square root of 50" which isn't relevant to the problem.

You're right, you can't have a "rational discussion" with me, or with
anyone
else.

BTW, one doesn't describe a current by which direction is comes from, one
describes it by which direction its going. Take the Power Squadron
course,
really.






"JAXAshby" wrote in message
...
jeffies, it is near impossible to have a rational discussion with you,
as
you
once AGAIN show you have zero understanding of either the issue or the
resultant answer.

you really, really, really don't understand the question, i.e. how much
current
and from which direction would be needed to cause a boat to change
course
by
some large angle.

you, you blithering idiot, are rambling on and on and on and on hoping
against
all hope that newbies will forget that you motor training wheels while
Walter
Mittying yourself to be Shackleton.

Yes I know you "think" you answered the question, just like you "think"
you're a
member of Mensa, and you "think" you graduated high school.

But saying that the answer is something that has a collection of
components
is
NOT showing that you actually know how to compute such a collection.
The
fact
that you keep insisting you solved it proves you don't really know how
to
do
it.
And being able to guess within 15% isn't bad, but doesn't show you know
how
to
navigate.



"JAXAshby" wrote in message
...
I know that *you* don't understand, jeffies, but the problem really
was
answered comprehensively within a few minutes of the question being
posted.

jeffie, rational discussion with you is near to impossible, for you
are
not
only much lacking in mental candlepower you are also so lacking in
such
you
are
not even capable of understanding just how lacking.

don't buy an EPIRB, jeffie. Let Darwin help you sail, if you ever do
decide
to
sail in lieu motoring.

I think I gave the answer to the "math problem."

As to whether this current can e