I know that *you* don't understand, jeffies, but the problem really was
answered comprehensively within a few minutes of the question being posted.

jeffie, rational discussion with you is near to impossible, for you are not
only much lacking in mental candlepower you are also so lacking in such you are
not even capable of understanding just how lacking.

don't buy an EPIRB, jeffie. Let Darwin help you sail, if you ever do decide to
sail in lieu motoring.

I think I gave the answer to the "math problem."

As to whether this current can exist in the Gulf Stream or an Eddy, I'm
skeptical. However, I really don't know, and there are certainly many cases
of
current running substantially higher than what is "advertised."

Since Jax claims to have only been making 3 knots, and doesn't specify the
final
SOG, its actually possible that they were not in an eddy, but in the Gulf
Stream
itself. Given the obviously poor navigational skill onboard, I wouldn't
doubt
it!


"SkitchNYC" wrote in message
...
You've only answered one part of the question.

Since no one seems willing to do this probably, here are the answers:
Starting with heading of 190 and speed through water 5, to have a COG of
90
and
SOG of 5,
current must be 50 degrees, speed of 7.66

Starting with heading of 190 and speed through water 5, to have a COG of
90
and
SOG of 2.5,
current must be 34.37 degrees, speed of 5.96



For any oblique triangle with angles A, B, and C, and opposite sides a,b,
and, c
then:
the law of sines says:

a/ sinA = b / sinB = c / sinC = diameter of circumscribed circle

and the law of cosines says:
c^2 = a^2 + b^2 - 2*a*b* cos C



"SkitchNYC" wrote in message
...
Say you are sailing a course of 190 and making 5 kn. An adverse current
suddenly gets you and you are now making a COG of 90. Assume the new
COG
is
at
the same speed (5kn) and again at 2.5 kn. What direction and speed must
the
current be to produce either of these results? Can such a current exist
in
a
Gulf Stream eddie?