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#1
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![]() "JAXAshby" wrote in message ... don't understand your question, but will try to explain what _may_ have been your question. I don't understand you explanation..... An a/c unit will use about 1,400 watts electricity input to remove every 1,000 watts of heat. The Mermaid Marine a/c in question here is rated at 6500 BTU, and draws 6.4 amps at 120 volts. That is 768 watts of input power. The a/c is rated at "6500 BTU", which is really 6500 BTU per hour (manufactuers tend to leave off the "per hour" part of the specification). This unit has an EER (energy efficiency ratio) of 6500/768= 8.5, which is comparable to a typical window mounted A/C. |
#2
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![]() Oh. And I thought the a/c only drew 7 amps @ 8000 btu + 3/4 amp for the pump. At least that is what the user manual stated. -- Capt. Frank __c \ _ | \_ __\_| oooo \_____ ~~~~|______________/ ~~~~~ www.home.earthlink.net/~aartworks "JAXAshby" wrote in message ... don't understand your question, but will try to explain what _may_ have been your question. An a/c unit will use about 1,400 watts electricity input to remove every 1,000 watts of heat. 1,000 watts = 3,012 btu's(according to the figures used by th HVAC industry [I have family in the business long term]) A group 27 battery usually has aboout 100 amp-hour capacity, of which about 50% is usuable. 2 grp 27's will give about a total of 100 amps before going dead, as in unusable 100 amps at 12 volts = 1,200 watts = 3,600 btu's across 1-1/2 hours that makes for about 2,400 btu's per hour INPUT (about 800 watts, about 65 amps). Which makes for about 1,800 btu's of cooling. sorry I used the 1,000 btu figure as I was just doing the numbers quickly in my head. btw, 1,800 btu's is about the cooling capacity of 12# of ice melting. In other words, for drawing your 2 grp 27 batteries to their knees in an hour and a half you will get about the cooling capacity of throwing about 18 pounds of ice on your cabin sole. , my 2 group 27 house batteries will run the unit on the inverter for about one and a half hours. considering that 2 group 27's will put out about 100 amps in an hour and a half, or about 1,200 watts or about 3,600 btu's, you a/c unit ain't putting out but about 1,000 btu's per hour of cooling. not a hell of a lot. |
#3
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![]() I suppose that is why I chose a generator to run "the stuff" away from the dock. It just works better. The inverter is fine for running the microwave to heat up a cup of soup or somesuch, and even run the tv/dvd. But not much good for hi power consumption. Hot water heater on inverter? Forget it. -- Capt. Frank __c \ _ | \_ __\_| oooo \_____ ~~~~|______________/ ~~~~~ www.home.earthlink.net/~aartworks "JAXAshby" wrote in message ... don't understand your question, but will try to explain what _may_ have been your question. An a/c unit will use about 1,400 watts electricity input to remove every 1,000 watts of heat. 1,000 watts = 3,012 btu's(according to the figures used by th HVAC industry [I have family in the business long term]) A group 27 battery usually has aboout 100 amp-hour capacity, of which about 50% is usuable. 2 grp 27's will give about a total of 100 amps before going dead, as in unusable 100 amps at 12 volts = 1,200 watts = 3,600 btu's across 1-1/2 hours that makes for about 2,400 btu's per hour INPUT (about 800 watts, about 65 amps). Which makes for about 1,800 btu's of cooling. sorry I used the 1,000 btu figure as I was just doing the numbers quickly in my head. btw, 1,800 btu's is about the cooling capacity of 12# of ice melting. In other words, for drawing your 2 grp 27 batteries to their knees in an hour and a half you will get about the cooling capacity of throwing about 18 pounds of ice on your cabin sole. , my 2 group 27 house batteries will run the unit on the inverter for about one and a half hours. considering that 2 group 27's will put out about 100 amps in an hour and a half, or about 1,200 watts or about 3,600 btu's, you a/c unit ain't putting out but about 1,000 btu's per hour of cooling. not a hell of a lot. |
#4
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![]() BTW are you in Jacksonville? -- Capt. Frank __c \ _ | \_ __\_| oooo \_____ ~~~~|______________/ ~~~~~ www.home.earthlink.net/~aartworks "JAXAshby" wrote in message ... don't understand your question, but will try to explain what _may_ have been your question. An a/c unit will use about 1,400 watts electricity input to remove every 1,000 watts of heat. 1,000 watts = 3,012 btu's(according to the figures used by th HVAC industry [I have family in the business long term]) A group 27 battery usually has aboout 100 amp-hour capacity, of which about 50% is usuable. 2 grp 27's will give about a total of 100 amps before going dead, as in unusable 100 amps at 12 volts = 1,200 watts = 3,600 btu's across 1-1/2 hours that makes for about 2,400 btu's per hour INPUT (about 800 watts, about 65 amps). Which makes for about 1,800 btu's of cooling. sorry I used the 1,000 btu figure as I was just doing the numbers quickly in my head. btw, 1,800 btu's is about the cooling capacity of 12# of ice melting. In other words, for drawing your 2 grp 27 batteries to their knees in an hour and a half you will get about the cooling capacity of throwing about 18 pounds of ice on your cabin sole. , my 2 group 27 house batteries will run the unit on the inverter for about one and a half hours. considering that 2 group 27's will put out about 100 amps in an hour and a half, or about 1,200 watts or about 3,600 btu's, you a/c unit ain't putting out but about 1,000 btu's per hour of cooling. not a hell of a lot. |
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