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#1
posted to rec.boats.electronics
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On Sat, 3 Mar 2007 16:36:19 -0000, JohnDW
wrote: Peter Bennett, in article 0inhu2helpvoua2dr1h3ekkopfsr67qjp1 , says... On Fri, 2 Mar 2007 16:05:36 -0800, "Lynn Coffelt" wrote: A good deal of modern boat electronics wiring is connected to terminal blocks by sticking the end of the wire into a hole where a screw-down clamp holds the wire in place. It always looked like a not too smart idea to me, but they neglected to ask me when the equipment was being designed. My question is: How do you experts treat the wire ends that go into the terminal block holes? Europeans frequently use these compression terminals (Phoenix, Weidmuller and other make nice terminal block systems using them), and use ferrules (sp?) on the wires - metal sleeves, possibly with a plastic part to go over the wire insulation - the ferrules are crimped on the wire, before inserting the wire in the terminal, and make a very neat installation. The normal ferrules do make it difficult to get two wires in a terminal, but there are ferrules designed specifically to handle two wires (I've never used them myself.) These ferrules and crimp tools are available from Digikey, Newark and others. These European terminal block systems make really nice assemblies - much nicer than our usual barrier blocks. With the optional parts that allow you to bridge terminals, you can make quite fancy distribution systems. See http://members.shaw.ca/peterbb/dinblock.html As a European of the British variety I would never use (European designed) DIN rails on a boat - or anywhere subject to moisture. They are intended for power wiring in enclosed locations ONLY. OK, if you enclose them in a waterproof box but not otherwise. I think I'm agreeing with Larry - Use crimped ring terminals on screw connectors. At least, with these, if the screw does loosen due to vibration, the wire doesn't become disconnected and go walkabouts. As an alternative, I'll use screw connectors with the wire crimped into a bootlace ferrule or, preferably, one with a hook on the end so the wire won't come out in the event of the screw vibrating loose. (similar to this: http://tinyurl.com/32pmmu) And, yes, keep the metalwork the same so you don't get electrolytic corrosion. Ring terminals, hooked blades, bootlace ferrule or spade connectors, IMHO if the terminal comes a bit loose you have probably got a burn out on the connector and wire end anyway! If you are considering Din rail mount terminals then take a look at WAGO spring loaded terminals, no screws to come loose at all! -- Richard Nb "Pound Eater" Parkend G+S "Governments are like Nappies, they should be changed often." (For the same reason) |
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#2
posted to rec.boats.electronics
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Why would it burn out? Burn outs happen from high current. You don't get high
current from loose connection, you get low current. "Electricky Dicky" wrote in message ... Ring terminals, hooked blades, bootlace ferrule or spade connectors, IMHO if the terminal comes a bit loose you have probably got a burn out on the connector and wire end anyway! |
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#3
posted to rec.boats.electronics
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Chuck Tribolet wrote:
Why would it burn out? Burn outs happen from high current. You don't get high current from loose connection, you get low current. "Electricky Dicky" wrote in message ... Ring terminals, hooked blades, bootlace ferrule or spade connectors, IMHO if the terminal comes a bit loose you have probably got a burn out on the connector and wire end anyway! Loose connection gives you high resistance, so ALL the voltage drop is across your 'bad' connection. So even though the the current will reduce because of the higher resistance, most of the power will be in the joint. So if the current falls to say 2 amps and 12 volts drop is at the connection then using W=IV we will have 24W. This is more than my mini soldering iron. |
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#4
posted to rec.boats.electronics
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On Sun, 04 Mar 2007 10:12:13 GMT, Bozo wrote:
Chuck Tribolet wrote: Why would it burn out? Burn outs happen from high current. You don't get high current from loose connection, you get low current. "Electricky Dicky" wrote in message ... Ring terminals, hooked blades, bootlace ferrule or spade connectors, IMHO if the terminal comes a bit loose you have probably got a burn out on the connector and wire end anyway! Loose connection gives you high resistance, so ALL the voltage drop is across your 'bad' connection. So even though the the current will reduce because of the higher resistance, most of the power will be in the joint. So if the current falls to say 2 amps and 12 volts drop is at the connection then using W=IV we will have 24W. This is more than my mini soldering iron. And JohnW wrote Arcing/sparking or otherwise generating heat due to a higher than normal connection resistance. Thank you gentlemen, you beat me to it. On the subject of "tight screws" IMHO the European metric "relatively fine thread" allows tighter terminals (of any sort) than the US threads! Stand by for flack! ;-) -- Richard Nb "Pound Eater" Parkend G+S "Governments are like Nappies, they should be changed often." (For the same reason) |
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#5
posted to rec.boats.electronics
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Electricky Dicky wrote in
: On the subject of "tight screws" IMHO the European metric "relatively fine thread" allows tighter terminals (of any sort) than the US threads! Stand by for flack! ;-) 100% true.... We still haven't learned which standards are the best. Compare the US' new HDTV picture to the new HDTV picture in Europe. Ours sucks in comparison. Larry -- If the damned government isn't going to enforce immigration laws, can they at LEAST park an ICE paddy wagon in front of WalMart so I can find a parking place and make the checkout line SHORTER?! |
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#6
posted to rec.boats.electronics
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Bozo wrote in
: Chuck Tribolet wrote: Why would it burn out? Burn outs happen from high current. You don't get high current from loose connection, you get low current. "Electricky Dicky" wrote in message ... Ring terminals, hooked blades, bootlace ferrule or spade connectors, IMHO if the terminal comes a bit loose you have probably got a burn out on the connector and wire end anyway! Loose connection gives you high resistance, so ALL the voltage drop is across your 'bad' connection. So even though the the current will reduce because of the higher resistance, most of the power will be in the joint. http://www.youtube.com/watch?v=1jPZL...elated&search= Not necessarily.....(c; Even the power company guys were impressed! Larry -- If the damned government isn't going to enforce immigration laws, can they at LEAST park an ICE paddy wagon in front of WalMart so I can find a parking place and make the checkout line SHORTER?! |
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#7
posted to rec.boats.electronics
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http://www.youtube.com/watch?v=1jPZL...elated&search=
Not necessarily.....(c; Even the power company guys were impressed! Larry Heck, even I was impressed. Old Chief Lynn |
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#8
posted to rec.boats.electronics
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Lynn Coffelt wrote:
http://www.youtube.com/watch?v=1jPZL...elated&search= Not necessarily.....(c; Even the power company guys were impressed! Larry Heck, even I was impressed. Old Chief Lynn Hopefully this does not happen very often in a boat with 12VDC... I wonder what my chart display would think of that!!!! Daniel |
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