Home |
Search |
Today's Posts |
#1
![]() |
|||
|
|||
![]()
Hi,
I have a question that someone might be able to assist with - a formula for - or an idea. I have a 12 inch x 10 inch 3 blade kaplan prop for a bow thruster and I am trying to work out in rough handfuls what power the prop will absorb at say 1500rpm. So far I have worked out the volume of water displaced per rev/sec/min - allowing for prop slip and the loss of area at the centre caused by the boss and also the speed advance of the prop per rev/sec/min. This gives a mass of water in kg moving at a velocity of metres/sec. Somehow, I think I should be able to relate this force required to achieve the movement into the torque and hence power required to turn the prop, but have not yet achieved the linkage. Wondered if anyone has any thoughts??? TVMIA |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
What does MIT say about ionization and lightning?? | ASA | |||
Power cost of idle electric water heater | Cruising | |||
How to use a simple SWR meter and what it means to your VHF | Electronics | |||
Using a generator for AC power in absence of shore power | Electronics |