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Martin Baxter wrote:
Bart wrote: A load on the line is 1000 lbs. You have just lead a line through a block, around an angle of 180 degrees. What is the load on the sheave? [1 pt] 2000 lbs For an angle of 90 degrees, what would be the load on the sheave? [1 pt] 2000*sin(45)=1414 1bs @ 45 degrees. (Note: angle of line-block-line = 135 degrees) At what angle does the sheave load match the line load? [1 pt] arcsin(1000/2000)=30 degrees (actual angle of line-block-line= 150 degrees) Cheers Marty |
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