Why give an answer to 1000 places when it wrong in the second place? The point
of nav problems is to be able to get the correct answer, not something within
10%.



"JAXAshby" wrote in message
...
jeffie, the answer was posted three days ago. And it was posted out to 1,000
decimal places.

Earth to jeff, Earth to jeff ...


Since no one seems willing to do this probably, here are the answers:
Starting with heading of 190 and speed through water 5, to have a COG of 90
and
SOG of 5,
current must be 50 degrees, speed of 7.66

Starting with heading of 190 and speed through water 5, to have a COG of 90
and
SOG of 2.5,
current must be 34.37 degrees, speed of 5.96



For any oblique triangle with angles A, B, and C, and opposite sides a,b,
and, c
then:
the law of sines says:

a/ sinA = b / sinB = c / sinC = diameter of circumscribed circle

and the law of cosines says:
c^2 = a^2 + b^2 - 2*a*b* cos C



"SkitchNYC" wrote in message
...
Say you are sailing a course of 190 and making 5 kn. An adverse current
suddenly gets you and you are now making a COG of 90. Assume the new COG
is
at
the same speed (5kn) and again at 2.5 kn. What direction and speed must
the
current be to produce either of these results? Can such a current exist in
a
Gulf Stream eddie?

ah, it seems you didn't understand the ramifications of the question.

not surprising.


Why give an answer to 1000 places when it wrong in the second place? The
point
of nav problems is to be able to get the correct answer, not something within
10%.



"JAXAshby" wrote in message
...
jeffie, the answer was posted three days ago. And it was posted out to
1,000
decimal places.

Earth to jeff, Earth to jeff ...


Since no one seems willing to do this probably, here are the answers:
Starting with heading of 190 and speed through water 5, to have a COG of
90
and
SOG of 5,
current must be 50 degrees, speed of 7.66

Starting with heading of 190 and speed through water 5, to have a COG of
90
and
SOG of 2.5,
current must be 34.37 degrees, speed of 5.96



For any oblique triangle with angles A, B, and C, and opposite sides a,b,
and, c
then:
the law of sines says:

a/ sinA = b / sinB = c / sinC = diameter of circumscribed circle

and the law of cosines says:
c^2 = a^2 + b^2 - 2*a*b* cos C



"SkitchNYC" wrote in message
...
Say you are sailing a course of 190 and making 5 kn. An adverse current
suddenly gets you and you are now making a COG of 90. Assume the new
COG
is
at
the same speed (5kn) and again at 2.5 kn. What direction and speed must
the
current be to produce either of these results? Can such a current exist
in
a
Gulf Stream eddie?

Come off it Jax,

That's twice now that you've pull the eddy gambit; Both time with the
same 45* angles. Find a different solution for your Math. Not all Eddies
create 90 Deg course changes. Time to try something different.

Take your baggage away some the Gulf Stream. By the way Jax, if you were
200 miles offshore you were most like on the East side of the stream.

OT

if you were
200 miles offshore you were most like on the East side of the stream.

yes, and if we were 5,000 miles offshore we would have been in eastern Europe.

never said we were 200 miles offshore.