Math Problem
 

Any fool can look at the numbers and guess the answer is around seven knots. In
fact, one did. The problem is to know how to solve it properly for the general
case, some you've shown you can't do, and have no interest in learning how.
This was posed as a "math problem," not a random guess problem. And there were
two problems, the second was obviously too complicated for you.

Perhaps Skitch, the OP, can tell us who had the proper answer?


"JAXAshby" wrote in message
...
jeff the *real* problem was what kind of counter-current was needed to change
a
boat's course by a large amount.

That question was answered within minutes by the very first repsonder (me).
After that, the posts got playful as to what precision -- not accuracy -- that
a "little over 7 knots" could be.

you, on the other hand, concerned yourself with precision calculations on
imprecise -- and unknowably precise -- assumptions.

in other words, you didn't understand the question, only the need for
complexity.

The simple and original answer was understood by everyone -- but you --
without
regard to their understanding of, let alone the capability of calculating, the
lengths of non-square triangles.

Yes, if you can't solve the real problem you can make an approximation.
What's
your point? You don't know how to solve the real problem? We already know
that.


"JAXAshby" wrote in message
...
the square root of 50 was in fact important to the discussion, but it seems
you
still don't know why.

go back and re-read the post again and again and again and again until you
see
why. (hint: 5^2 + 5^2 = 50)





Hey Jax, how come you didn't get the right answer to the question? I did.
I
then provided the appropriate formulae. All you did was babble about
"components" and then give the wrong answer. You went on for 4 posts
about
the
"square root of 50" which isn't relevant to the problem.

You're right, you can't have a "rational discussion" with me, or with
anyone
else.

BTW, one doesn't describe a current by which direction is comes from, one
describes it by which direction its going. Take the Power Squadron
course,
really.






"JAXAshby" wrote in message
...
jeffies, it is near impossible to have a rational discussion with you,
as
you
once AGAIN show you have zero understanding of either the issue or the
resultant answer.

you really, really, really don't understand the question, i.e. how much
current
and from which direction would be needed to cause a boat to change
course
by
some large angle.

you, you blithering idiot, are rambling on and on and on and on hoping
against
all hope that newbies will forget that you motor training wheels while
Walter
Mittying yourself to be Shackleton.

Yes I know you "think" you answered the question, just like you "think"
you're a
member of Mensa, and you "think" you graduated high school.

But saying that the answer is something that has a collection of
components
is
NOT showing that you actually know how to compute such a collection.
The
fact
that you keep insisting you solved it proves you don't really know how
to
do
it.
And being able to guess within 15% isn't bad, but doesn't show you know
how
to
navigate.



"JAXAshby" wrote in message
...
I know that *you* don't understand, jeffies, but the problem really
was
answered comprehensively within a few minutes of the question being
posted.

jeffie, rational discussion with you is near to impossible, for you
are
not
only much lacking in mental candlepower you are also so lacking in
such
you
are
not even capable of understanding just how lacking.

don't buy an EPIRB, jeffie. Let Darwin help you sail, if you ever do
decide
to
sail in lieu motoring.

I think I gave the answer to the "math problem."

As to whether this current can e











Hey Jax, how come you didn't get the right answer to the question? I did.
I
then provided the appropriate formulae. All you did was babble about
"components" and then give the wrong answer. You went on for 4 posts
about
the
"square root of 50" which isn't relevant to the problem.

You're right, you can't have a "rational discussion" with me, or with
anyone
else.

BTW, one doesn't describe a current by which direction is comes from, one
describes it by which direction its going. Take the Power Squadron
course,
really.






"JAXAshby" wrote in message
...
jeffies, it is near impossible to have a rational discussion with you,
as
you
once AGAIN show you have zero understanding of either the issue or the
resultant answer.

you really, really, really don't understand the question, i.e. how much
current
and from which direction would be needed to cause a boat to change
course
by
some large angle.

you, you blithering idiot, are rambling on and on and on and on hoping
against
all hope that newbies will forget that you motor training wheels while
Walter
Mittying yourself to be Shackleton.

Yes I know you "think" you answered the question, just like you "think"
you're a
member of Mensa, and you "think" you graduated high school.

But saying that the answer is something that has a collection of
components
is
NOT showing that you actually know how to compute such a collection.
The
fact
that you keep insisting you solved it proves you don't really know how
to
do
it.
And being able to guess within 15% isn't bad, but doesn't show you know
how
to
navigate.



"JAXAshby" wrote in message
...
I know that *you* don't understand, jeffies, but the problem really
was
answered comprehensively within a few minutes of the question being
posted.

jeffie, rational discussion with you is near to impossible, for you
are
not
only much lacking in mental candlepower you are also so lacking in
such
you
are
not even capable of understanding just how lacking.

don't buy an EPIRB, jeffie. Let Darwin help you sail, if you ever do
decide
to
sail in lieu motoring.

I think I gave the answer to the "math problem."

As to whether this current can e

Math Problem
 

"JAXAshby" wrote in message
...
As it happens, I don't have an opinion about the square root of 50.

opinion? how the hell can one had an **opinion** re sq rt 50????

You asked me what I thought the sq root of 50 was, didn't you? As your
question is totally irrelevant to the current discussion, I have no thoughts
on the matter.



Now, perhaps you could tell us why you think that my mathematical skills
are
lacking??

ah ..... maybe see above???

That just proves that your powers of deduction are lacking.


Now, can you explain why you think that my answer to the original question
was wrong?

Skitch asked-
Say you are sailing a course of 190 and making 5 kn. An adverse current
suddenly gets you and you are now making a COG of 90. Assume the new COG
is at
the same speed (5kn)

and I answered-

Current = 50*, 8kts

What is your answer, Jax?



Regards


Donal
--

Math Problem
 

"Jeff Morris" wrote in message
...
Since no one seems willing to do this probably, here are the answers:

Excuse me???

Define "properly"! I worked it out using a Breton plotter. That *is* the
proper way to do it.




Regards


Donal
--

Math Problem
 

rational thought is beyond you, isn't it.

Any fool can look at the numbers and guess the answer is around seven knots.
In
fact, one did. The problem is to know how to solve it properly for the
general
case, some you've shown you can't do, and have no interest in learning how.
This was posed as a "math problem," not a random guess problem. And there
were
two problems, the second was obviously too complicated for you.

Perhaps Skitch, the OP, can tell us who had the proper answer?


"JAXAshby" wrote in message
...
jeff the *real* problem was what kind of counter-current was needed to
change
a
boat's course by a large amount.

That question was answered within minutes by the very first repsonder (me).
After that, the posts got playful as to what precision -- not accuracy --
that
a "little over 7 knots" could be.

you, on the other hand, concerned yourself with precision calculations on
imprecise -- and unknowably precise -- assumptions.

in other words, you didn't understand the question, only the need for
complexity.

The simple and original answer was understood by everyone -- but you --
without
regard to their understanding of, let alone the capability of calculating,
the
lengths of non-square triangles.

Yes, if you can't solve the real problem you can make an approximation.
What's
your point? You don't know how to solve the real problem? We already
know
that.


"JAXAshby" wrote in message
...
the square root of 50 was in fact important to the discussion, but it
seems
you
still don't know why.

go back and re-read the post again and again and again and again until
you
see
why. (hint: 5^2 + 5^2 = 50)





Hey Jax, how come you didn't get the right answer to the question? I
did.
I
then provided the appropriate formulae. All you did was babble about
"components" and then give the wrong answer. You went on for 4 posts
about
the
"square root of 50" which isn't relevant to the problem.

You're right, you can't have a "rational discussion" with me, or with
anyone
else.

BTW, one doesn't describe a current by which direction is comes from,
one
describes it by which direction its going. Take the Power Squadron
course,
really.






"JAXAshby" wrote in message
...
jeffies, it is near impossible to have a rational discussion with
you,
as
you
once AGAIN show you have zero understanding of either the issue or
the
resultant answer.

you really, really, really don't understand the question, i.e. how
much
current
and from which direction would be needed to cause a boat to change
course
by
some large angle.

you, you blithering idiot, are rambling on and on and on and on
hoping
against
all hope that newbies will forget that you motor training wheels
while
Walter
Mittying yourself to be Shackleton.

Yes I know you "think" you answered the question, just like you
"think"
you're a
member of Mensa, and you "think" you graduated high school.

But saying that the answer is something that has a collection of
components
is
NOT showing that you actually know how to compute such a collection.
The
fact
that you keep insisting you solved it proves you don't really know
how
to
do
it.
And being able to guess within 15% isn't bad, but doesn't show you
know
how
to
navigate.



"JAXAshby" wrote in message
...
I know that *you* don't understand, jeffies, but the problem
really
was
answered comprehensively within a few minutes of the question
being
posted.

jeffie, rational discussion with you is near to impossible, for
you
are
not
only much lacking in mental candlepower you are also so lacking in
such
you
are
not even capable of understanding just how lacking.

don't buy an EPIRB, jeffie. Let Darwin help you sail, if you ever
do
decide
to
sail in lieu motoring.

I think I gave the answer to the "math problem."

As to whether this current can e











Hey Jax, how come you didn't get the right answer to the question? I
did.
I
then provided the appropriate formulae. All you did was babble about
"components" and then give the wrong answer. You went on for 4 posts
about
the
"square root of 50" which isn't relevant to the problem.

You're right, you can't have a "rational discussion" with me, or with
anyone
else.

BTW, one doesn't describe a current by which direction is comes from,
one
describes it by which direction its going. Take the Power Squadron
course,
really.






"JAXAshby" wrote in message
...
jeffies, it is near impossible to have a rational discussion with
you,
as
you
once AGAIN show you have zero understanding of either the issue or
the
resultant answer.

you really, really, really don't understand the question, i.e. how
much
current
and from which direction would be needed to cause a boat to change
course
by
some large angle.

you, you blithering idiot, are rambling on and on and on and on
hoping
against
all hope that newbies will forget that you motor training wheels
while
Walter
Mittying yourself to be Shackleton.

Yes I know you "think" you answered the question, just like you
"think"
you're a
member of Mensa, and you "think" you graduated high school.

But saying that the answer is something that has a collection of
components
is
NOT showing that you actually know how to compute such a collection.
The
fact
that you keep insisting you solved it proves you don't really know
how
to
do
it.
And being able to guess within 15% isn't bad, but doesn't show you
know
how
to
navigate.



"JAXAshby" wrote in message
...
I know that *you* don't understand, jeffies, but the problem
really
was
answered comprehensively within a few minutes of the question
being
posted.

jeffie, rational discussion with you is near to impossible, for
you
are
not
only much lacking in mental candlepower you are also so lacking in
such
you
are
not even capable of understanding just how lacking.

don't buy an EPIRB, jeffie. Let Darwin help you sail, if you ever
do
decide
to
sail in lieu motoring.

I think I gave the answer to the "math problem."

As to whether this current can e

Math Problem
 

donny, I don't saying your answer was wrong. it is jeffies who says every
answer given but his narrowly defined, case-specific answer is wrong.

however, you still can't have an "opinion" on the sq rt of 2.

opinion? how the hell can one had an **opinion** re sq rt 50????

You asked me what I thought the sq root of 50 was, didn't you? As your
question is totally irrelevant to the current discussion, I have no thoughts
on the matter.



Now, perhaps you could tell us why you think that my mathematical skills
are
lacking??

ah ..... maybe see above???

That just proves that your powers of deduction are lacking.


Now, can you explain why you think that my answer to the original question
was wrong?

Skitch asked-
Say you are sailing a course of 190 and making 5 kn. An adverse current
suddenly gets you and you are now making a COG of 90. Assume the new COG
is at
the same speed (5kn)

and I answered-

Current = 50*, 8kts

What is your answer, Jax?



Regards


Donal
--

Math Problem
 

donny, jeffies, you guys are arguing a case-specific, tightly defined issue.
Stand back a couple feet and deal with the concept. Gotta remember that the
original assumptions were nothing more than assumptions, therefore while
precision can be obtained accuracy can not.

Since no one seems willing to do this probably, here are the answers:

Excuse me???

Define "properly"! I worked it out using a Breton plotter. That *is* the
proper way to do it.




Regards


Donal
--

Math Problem
 

This was not a vague question, it was a well posed mathematical problem. You
ignored the complicating issue and solved a simpler case. You were 10% off in
the speed and 5 degrees off in the current direction. You the ignored the
second part because it required some actual math. Donal solved both problems
using a proper navigational method, though I think his accuracy could have been
better.

I simply provided the proper mathematical solution. I sorry if a bit of trig is
beyond you.

BTW, given the numbers you provided, why do you think this was "an eddy" and not
the Gulf Stream itself?





"JAXAshby" wrote in message
...
donny, jeffies, you guys are arguing a case-specific, tightly defined issue.
Stand back a couple feet and deal with the concept. Gotta remember that the
original assumptions were nothing more than assumptions, therefore while
precision can be obtained accuracy can not.

Since no one seems willing to do this probably, here are the answers:

Excuse me???

Define "properly"! I worked it out using a Breton plotter. That *is* the
proper way to do it.




Regards


Donal
--

Math Problem
 

Your accuracy was only slightly better than jaxie's guess. I would think you'd
aspire to better than that. Actually, that would probably not be good enough to
pass the USCG chartwork test.



"Donal" wrote in message
...

"Jeff Morris" wrote in message
...
Since no one seems willing to do this probably, here are the answers:

Excuse me???

Define "properly"! I worked it out using a Breton plotter. That *is* the
proper way to do it.




Regards


Donal
--

Math Problem
 

And Donal did it blindfolded.

SV

"Jeff Morris" wrote in message
...
This was not a vague question, it was a well posed mathematical problem.
You
ignored the complicating issue and solved a simpler case. You were 10%
off in
the speed and 5 degrees off in the current direction. You the ignored
the
second part because it required some actual math. Donal solved both
problems
using a proper navigational method, though I think his accuracy could have
been
better.

I simply provided the proper mathematical solution. I sorry if a bit of
trig is
beyond you.

BTW, given the numbers you provided, why do you think this was "an eddy"
and not
the Gulf Stream itself?





"JAXAshby" wrote in message
...
donny, jeffies, you guys are arguing a case-specific, tightly defined
issue.
Stand back a couple feet and deal with the concept. Gotta remember that
the
original assumptions were nothing more than assumptions, therefore while
precision can be obtained accuracy can not.

Since no one seems willing to do this probably, here are the answers:

Excuse me???

Define "properly"! I worked it out using a Breton plotter. That
*is* the
proper way to do it.




Regards


Donal
--

Math Problem
 

Just back form the boat; Couple of hrs fooling around. Felt Great.

Still have a Jammed shift cable on Pitolhouse control but temp was 62*F.
Sailed from cockpit.

Jax, you Math is screwed up. If you're using sin and Cosin you need to
be figuring on a right triangle. If a=b and you say angle sin c can't be
the diameter of the circle.

You're blowing smoke!!!

If you maintained your heading while making a 90 degree course, your
leeway wake would be obvious to any sailor. GPS be damned.

This is the second time you've tried to use the Stream Eddy and it
doesn't hold up.

Jax, it didn't happen. It didn't happen before and it won't happen.
You're only making yourself look stupid and your explaination are
nothing but double talk with no real meaning. Give it up.

Ole Thom