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Where is the catenary on a yo-yo hanging from a finger? It is a line
between 2 points. "JAXAshby" wrote in message ... clown, check the meaning of the word. Gene Kearns Date: 9/18/2004 7:22 PM Eastern Daylight Time Message-id: On 18 Sep 2004 20:49:57 GMT, (JAXAshby) wrote: spell it any way you want, you still do not have any idea what it is. yo-yo, a string strung between two points has, and always has, a catenary. go look it up. And a yo-yo is about the depth of your comprehension, here.... -- Grady-White Gulfstream, out of Southport, NC. http://myworkshop.idleplay.net/cavern/ Homepage http://www.southharbourvillageinn.com/directions.asp Where Southport,NC is located. http://www.thebayguide.com/rec.boats Rec.boats at Lee Yeaton's Bayguide |
On Sat, 18 Sep 2004 22:04:06 -0400, "NOYB" wrote:
"Short Wave Sportfishing" wrote in message .. . On Sat, 18 Sep 2004 19:46:04 -0400, Gene Kearns And your "simplified look" does not apply.... an anchor rode does not employ both ends at the same "Y" value.... therefore assumptions of Y=Y'=0 do not obtain and is, therefore, the root cause of your lack of understanding in this area. There isn't *anything* *attached* to the middle. Thanks for the link Gene, by the way, I missed that the first time around. But wouldn't the strain be equal at the arthimetical center and can be equated to weight? It's really just another to figure energy transfer, right? I'm not totaly familiar with this so if I mess this up, it's an electronic engineer with a math degree playing at mechanics, but catenary defined means the shape of the line (or in this case rode) as a curve. A funciton of strain would be weights at either end. Strain can be defined as stored energy which is, I would think, distributed evenly along the line to the end points. One way to define how much strain is being applied would be to add weight to the middle and measure the deflection. At that point, it becomes a trig function - yes/no? Yes, assuming the line itself has negligible mass compared to the weight pulling on it...which is not a practical assumption when comparing it to an anchor line and chain rode. I don't know why jackassby even used this example. Jackassby's example describes a straight line...not a catenary. It is not even close to replicating what is happening to an anchor line and chain rode. The only time that Jax's example *may* similate an anchor line is when the force of the wind is so great that the line and chain is perfectly straight...which *never* happens in a real world situation anyhow. If the wind pulled so hard that the line was perfectly straight, it wouldn't be a catenary any longer...it would be a straight line. And if it were a straight line, the vertical component of force exerted by the boat on the anchor would be so high that the anchor would pull loose. Go look at the website Gene posted: http://alain.fraysse.free.fr/sail/ro...ic/sta_hom.htm It explains it all. Well, yes, but the static load page is "under construction" and that's what I was looking for, but hey - at least I have a better picture of what's what. Interesting about that kellet thing - that makes a lot of sense. I knew the term, but I didn't know the term, know what I mean? Thanks. Later, Tom |
On Sun, 19 Sep 2004 02:24:40 GMT, "Calif Bill"
wrote: "Short Wave Sportfishing" wrote in message .. . On Sat, 18 Sep 2004 20:14:34 -0400, "NOYB" wrote: "Gene Kearns" wrote in message .. . On 18 Sep 2004 21:15:33 GMT, (JAXAshby) wrote: What happens during the interaction of forces on the rode would be most fascinating. a way to simplified look at it is to consider the chain/rode/line to have zero weight pulled between two points (say 100 feet apart), then hang a 1# weight in the center point and check how much strain it put on the end points when the weight hangs 20 feet, then 10 feet, then 5 feet, then 1 foot, then 1 inch, then 1/10th inch. Just use trig to figure the forces. So.... we just used intuitive trig to figure out why (1) we use scope with an anchor and (2) why we don't tie boats to the dock with chain. Now *that* is some real science...... And your "simplified look" does not apply.... an anchor rode does not employ both ends at the same "Y" value.... therefore assumptions of Y=Y'=0 do not obtain and is, therefore, the root cause of your lack of understanding in this area. There isn't *anything* *attached* to the middle. the forces get out of hand ********VERY******** quickly. Even worse, is that the weight in the middle (or chain) has momentum as the boat rocks, so the "natural" position of the weight overshoots and makes for seriously high g-loads. There is no weight "in the middle" (other than the weight of the rode) .... so you put two anchors on the same rode? Odd. Also, in jaxassby's example, the points can't always be 100' apart if the weight is hanging further and further down each time...unless he has an extremely elastic line and there's a large amount of stretch. I assume that jaxassby meant to say "using a 100' rope". The main definition of catenary is that of a curve formed by a perfectly flexible, uniformly dense, and inextensible cable suspended from its endpoints. It would look a lot like hyperbolic cosine if you graphed it out. Which, now that I think about it, wouldn't look a lot like an anchor rode as much as a tow line. I'm more curious about strain towards the middle of the curve. That would be fairly easy to measure at either end, but if you have two opposing forces of two different weights, say as in a barge tow, the center strain would constantly move towards one or the other depending on the weights. How would you determine that mathematically? The end points are not at the same elevation. True, but then a hyperbolic curve does not necessarily have to have equal level end points (in this case, height). It only has to have a 90º tangent at some point along the curve. I think I'm getting one of my headaches again. I retired to get away from all this stuff. :) Later, Tom ----------- "Angling may be said to be so like the mathematics that it can never be fully learnt..." Izaak Walton "The Compleat Angler", 1653 |
tom, you got it close enough. when the chain pulls tight the forces become
huge *********VERY********** quickly. But wouldn't the strain be equal at the arthimetical center and can be equated to weight? It's really just another to figure energy transfer, right? I'm not totaly familiar with this so if I mess this up, it's an electronic engineer with a math degree playing at mechanics, but catenary defined means the shape of the line (or in this case rode) as a curve. A funciton of strain would be weights at either end. Strain can be defined as stored energy which is, I would think, distributed evenly along the line to the end points. One way to define how much strain is being applied would be to add weight to the middle and measure the deflection. At that point, it becomes a trig function - yes/no? the forces get out of hand ********VERY******** quickly. Even worse, is that the weight in the middle (or chain) has momentum as the boat rocks, so the "natural" position of the weight overshoots and makes for seriously high g-loads. There is no weight "in the middle" (other than the weight of the rode) .... so you put two anchors on the same rode? Odd. Using that concept, most people use kellets and think it is a good and useful idea. What's a kellet? Later, Tom |
short bus, the example I gave is accurate, if understated. the forces on a
massless line with weight in center become huge **********VERY************ quickly at the line becomes tighter. The forces on a catenary are even more huge and become worse even faster. The math is easier on a massless line than a catenary, that is all. NOYB" Date: 9/18/2004 10:04 PM Eastern Daylight Time Message-id: "Short Wave Sportfishing" wrote in message .. . On Sat, 18 Sep 2004 19:46:04 -0400, Gene Kearns wrote: On 18 Sep 2004 21:15:33 GMT, (JAXAshby) wrote: What happens during the interaction of forces on the rode would be most fascinating. a way to simplified look at it is to consider the chain/rode/line to have zero weight pulled between two points (say 100 feet apart), then hang a 1# weight in the center point and check how much strain it put on the end points when the weight hangs 20 feet, then 10 feet, then 5 feet, then 1 foot, then 1 inch, then 1/10th inch. Just use trig to figure the forces. So.... we just used intuitive trig to figure out why (1) we use scope with an anchor and (2) why we don't tie boats to the dock with chain. Now *that* is some real science...... And your "simplified look" does not apply.... an anchor rode does not employ both ends at the same "Y" value.... therefore assumptions of Y=Y'=0 do not obtain and is, therefore, the root cause of your lack of understanding in this area. There isn't *anything* *attached* to the middle. But wouldn't the strain be equal at the arthimetical center and can be equated to weight? It's really just another to figure energy transfer, right? I'm not totaly familiar with this so if I mess this up, it's an electronic engineer with a math degree playing at mechanics, but catenary defined means the shape of the line (or in this case rode) as a curve. A funciton of strain would be weights at either end. Strain can be defined as stored energy which is, I would think, distributed evenly along the line to the end points. One way to define how much strain is being applied would be to add weight to the middle and measure the deflection. At that point, it becomes a trig function - yes/no? Yes, assuming the line itself has negligible mass compared to the weight pulling on it...which is not a practical assumption when comparing it to an anchor line and chain rode. I don't know why jackassby even used this example. Jackassby's example describes a straight line...not a catenary. It is not even close to replicating what is happening to an anchor line and chain rode. The only time that Jax's example *may* similate an anchor line is when the force of the wind is so great that the line and chain is perfectly straight...which *never* happens in a real world situation anyhow. If the wind pulled so hard that the line was perfectly straight, it wouldn't be a catenary any longer...it would be a straight line. And if it were a straight line, the vertical component of force exerted by the boat on the anchor would be so high that the anchor would pull loose. Go look at the website Gene posted: http://alain.fraysse.free.fr/sail/ro...ic/sta_hom.htm It explains it all. |
If the wind pulled so hard that the line was perfectly straight, it wouldn't
be a catenary any longer a chain (or nylon rode, or a piece of cord string) ALWAYS has a catenary. ALWAYS. to pull the line straight requires infinite effort. and to pull it "just a little bit more" when it is already stressed with a 1,000# pull is HUGELY more than 1000#. That is what breaks boats loose, or at least boats without 15 or 20 feet of stretch left in the rode. |
the vertical component of force exerted by the boat on the
anchor would be so high that the anchor would pull loose. no ****. why do you think boats pull loose. |
Thanks for the link Gene, by the way, I missed that the first time
around. don't thank him, Tom. The site is like a Texan fraud. "Big hat, no cattle." While the site uses a lot of math symbols, it is the work of someone who understands damned little about catenaries AND thinks boats anchor in lite winds always. if you wish to anchor on mostly or all chain in a blow, you MUST hang LARGE weights (plural) in the middle of the rode. otherwise, the forces on the anchor and deck chocks get huge very quickly as the chain goes tight, and you will break loose (which is not an Act of God, but rather the consequence of an act of neglegence). |
boy, you guys are stucking fupid. give you an example understandable by a
sophomore in high school and you STILL insist on anchoring in such a fashion as to injure boaters around you. Did you ever consider some district attorney might charge you with criminal neglegence if you hurt someone anchoring your silly, lazy ass way (which, in fact, is your justification as to why you -- utterly unwilling to pull up an anchor by hand -- install an electric anchor puller that works only with chain). catenaires, and they strains imposed on the end points, is a freshman physics discussion understood by tens of millions of 18 year old boys every year. From: "NOYB" Date: 9/18/2004 8:14 PM Eastern Daylight Time Message-id: "Gene Kearns" wrote in message .. . On 18 Sep 2004 21:15:33 GMT, (JAXAshby) wrote: What happens during the interaction of forces on the rode would be most fascinating. a way to simplified look at it is to consider the chain/rode/line to have zero weight pulled between two points (say 100 feet apart), then hang a 1# weight in the center point and check how much strain it put on the end points when the weight hangs 20 feet, then 10 feet, then 5 feet, then 1 foot, then 1 inch, then 1/10th inch. Just use trig to figure the forces. So.... we just used intuitive trig to figure out why (1) we use scope with an anchor and (2) why we don't tie boats to the dock with chain. Now *that* is some real science...... And your "simplified look" does not apply.... an anchor rode does not employ both ends at the same "Y" value.... therefore assumptions of Y=Y'=0 do not obtain and is, therefore, the root cause of your lack of understanding in this area. There isn't *anything* *attached* to the middle. the forces get out of hand ********VERY******** quickly. Even worse, is that the weight in the middle (or chain) has momentum as the boat rocks, so the "natural" position of the weight overshoots and makes for seriously high g-loads. There is no weight "in the middle" (other than the weight of the rode) .... so you put two anchors on the same rode? Odd. Also, in jaxassby's example, the points can't always be 100' apart if the weight is hanging further and further down each time...unless he has an extremely elastic line and there's a large amount of stretch. I assume that jaxassby meant to say "using a 100' rope". |
JAXAshby wrote:
catenaires, and they strains imposed on the end points, is a freshman physics discussion understood by tens of millions of 18 year old boys every year. Times sure have change...when I was an 18-year-old boy, my interests focused on the one-handed removal of bras. Chains came much later. -- Not dead, in jail, or a slave? Thank a liberal! And don't forget to pay your taxes so the rich don't have to! |
just used intuitive trig
there is no such thing as intuitive trig. |
How would you determine that mathematically?
Tom, it is tough math for a layman. that is why I used the geometric explanation. lots easier math, even if it understates the forces involved. |
bill, like gene, stay out of this discussion. difference if, you can ask
questions, gene can not. neither of you is allowed to make statements until you get up to speed on the subject. gene never will get up to speed, you might sometime next year. "Calif Bill" Date: 9/18/2004 10:24 PM Eastern Daylight Time Message-id: . net "Short Wave Sportfishing" wrote in message .. . On Sat, 18 Sep 2004 20:14:34 -0400, "NOYB" wrote: "Gene Kearns" wrote in message .. . On 18 Sep 2004 21:15:33 GMT, (JAXAshby) wrote: What happens during the interaction of forces on the rode would be most fascinating. a way to simplified look at it is to consider the chain/rode/line to have zero weight pulled between two points (say 100 feet apart), then hang a 1# weight in the center point and check how much strain it put on the end points when the weight hangs 20 feet, then 10 feet, then 5 feet, then 1 foot, then 1 inch, then 1/10th inch. Just use trig to figure the forces. So.... we just used intuitive trig to figure out why (1) we use scope with an anchor and (2) why we don't tie boats to the dock with chain. Now *that* is some real science...... And your "simplified look" does not apply.... an anchor rode does not employ both ends at the same "Y" value.... therefore assumptions of Y=Y'=0 do not obtain and is, therefore, the root cause of your lack of understanding in this area. There isn't *anything* *attached* to the middle. the forces get out of hand ********VERY******** quickly. Even worse, is that the weight in the middle (or chain) has momentum as the boat rocks, so the "natural" position of the weight overshoots and makes for seriously high g-loads. There is no weight "in the middle" (other than the weight of the rode) .... so you put two anchors on the same rode? Odd. Also, in jaxassby's example, the points can't always be 100' apart if the weight is hanging further and further down each time...unless he has an extremely elastic line and there's a large amount of stretch. I assume that jaxassby meant to say "using a 100' rope". The main definition of catenary is that of a curve formed by a perfectly flexible, uniformly dense, and inextensible cable suspended from its endpoints. It would look a lot like hyperbolic cosine if you graphed it out. Which, now that I think about it, wouldn't look a lot like an anchor rode as much as a tow line. I'm more curious about strain towards the middle of the curve. That would be fairly easy to measure at either end, but if you have two opposing forces of two different weights, say as in a barge tow, the center strain would constantly move towards one or the other depending on the weights. How would you determine that mathematically? Later, Tom The end points are not at the same elevation. |
JAXAshby wrote:
bill, like gene, stay out of this discussion. difference if, you can ask questions, gene can not. neither of you is allowed to make statements until you get up to speed on the subject. gene never will get up to speed, you might sometime next year. Ker-ripes, Jaxass. You should at all costs avoid the use of the word "speed" or its variation "speedo." -- Not dead, in jail, or a slave? Thank a liberal! And don't forget to pay your taxes so the rich don't have to! |
It only has to have a
90º tangent at some point along the curve. not sure what you are trying to say there, for no curve has a 90* tangent. |
yo-yo, the shock absorbing capability is dependent on how much sag is in the
(inelastic) chain. lots of sag, lots of shock absorbtion. less sag, a hell of a lot less absorbtion. little sag, almost no shock absorbtion. "NOYB" Date: 9/18/2004 10:11 PM Eastern Daylight Time Message-id: "JAXAshby" wrote in message ... genie, shut up. Subject: Why need anchor chain? From: Gene Kearns Date: 9/18/2004 7:46 PM Eastern Daylight Time Message-id: On 18 Sep 2004 21:15:33 GMT, (JAXAshby) wrote: What happens during the interaction of forces on the rode would be most fascinating. a way to simplified look at it is to consider the chain/rode/line to have zero weight pulled between two points (say 100 feet apart), then hang a 1# weight in the center point and check how much strain it put on the end points when the weight hangs 20 feet, then 10 feet, then 5 feet, then 1 foot, then 1 inch, then 1/10th inch. Just use trig to figure the forces. So.... we just used intuitive trig to figure out why (1) we use scope with an anchor and (2) why we don't tie boats to the dock with chain. Now *that* is some real science...... And your "simplified look" does not apply.... an anchor rode does not employ both ends at the same "Y" value.... therefore assumptions of Y=Y'=0 do not obtain and is, therefore, the root cause of your lack of understanding in this area. There isn't *anything* *attached* to the middle. the forces get out of hand ********VERY******** quickly. Even worse, is that the weight in the middle (or chain) has momentum as the boat rocks, so the "natural" position of the weight overshoots and makes for seriously high g-loads. There is no weight "in the middle" (other than the weight of the rode) .... so you put two anchors on the same rode? Odd. Using that concept, most people use kellets and think it is a good and useful idea. http://www.johnsboatstuff.com/Articles/anchor.htm " Having a lot of sag in the rode reduces shock loads " Isn't that what started this whole argument? Anchor chain introduces sag in the rode. Sag in the rode reduces shock loads. So I guess I was right when I said that anchor chain acts as a shock absorber, eh jaxie? |
no.
Where is the catenary on a yo-yo hanging from a finger? It is a line between 2 points. "JAXAshby" wrote in message ... clown, check the meaning of the word. Gene Kearns Date: 9/18/2004 7:22 PM Eastern Daylight Time Message-id: On 18 Sep 2004 20:49:57 GMT, (JAXAshby) wrote: spell it any way you want, you still do not have any idea what it is. yo-yo, a string strung between two points has, and always has, a catenary. go look it up. And a yo-yo is about the depth of your comprehension, here.... -- Grady-White Gulfstream, out of Southport, NC. http://myworkshop.idleplay.net/cavern/ Homepage http://www.southharbourvillageinn.com/directions.asp Where Southport,NC is located. http://www.thebayguide.com/rec.boats Rec.boats at Lee Yeaton's Bayguide |
hoary, when you were 18 you had no career plans greater than becoming the night
shift manager at the gas station. btw, hoary, a whole lot of 18 year old boys are well past learning one handed bra removal, and are practising panty removal using the toes. catenaires, and they strains imposed on the end points, is a freshman physics discussion understood by tens of millions of 18 year old boys every year. Times sure have change...when I was an 18-year-old boy, my interests focused on the one-handed removal of bras. Chains came much later. -- Not dead, in jail, or a slave? Thank a liberal! And don't forget to pay your taxes so the rich don't have to! |
No kidding. With no sag, the anchor pulls loose...something even *you*
agreed with. Since anybody with a boat can tell you that anchors actually work and don't pull loose most of the time, it stands to reason that there must be a lot of sag in the line under most conditions. With me so far? If there's a lot of sag in the line, then the sag provides absorption of shock loads...just as I stated. "JAXAshby" wrote in message ... yo-yo, the shock absorbing capability is dependent on how much sag is in the (inelastic) chain. lots of sag, lots of shock absorbtion. less sag, a hell of a lot less absorbtion. little sag, almost no shock absorbtion. "NOYB" Date: 9/18/2004 10:11 PM Eastern Daylight Time Message-id: "JAXAshby" wrote in message ... genie, shut up. Subject: Why need anchor chain? From: Gene Kearns Date: 9/18/2004 7:46 PM Eastern Daylight Time Message-id: On 18 Sep 2004 21:15:33 GMT, (JAXAshby) wrote: What happens during the interaction of forces on the rode would be most fascinating. a way to simplified look at it is to consider the chain/rode/line to have zero weight pulled between two points (say 100 feet apart), then hang a 1# weight in the center point and check how much strain it put on the end points when the weight hangs 20 feet, then 10 feet, then 5 feet, then 1 foot, then 1 inch, then 1/10th inch. Just use trig to figure the forces. So.... we just used intuitive trig to figure out why (1) we use scope with an anchor and (2) why we don't tie boats to the dock with chain. Now *that* is some real science...... And your "simplified look" does not apply.... an anchor rode does not employ both ends at the same "Y" value.... therefore assumptions of Y=Y'=0 do not obtain and is, therefore, the root cause of your lack of understanding in this area. There isn't *anything* *attached* to the middle. the forces get out of hand ********VERY******** quickly. Even worse, is that the weight in the middle (or chain) has momentum as the boat rocks, so the "natural" position of the weight overshoots and makes for seriously high g-loads. There is no weight "in the middle" (other than the weight of the rode) .... so you put two anchors on the same rode? Odd. Using that concept, most people use kellets and think it is a good and useful idea. http://www.johnsboatstuff.com/Articles/anchor.htm " Having a lot of sag in the rode reduces shock loads " Isn't that what started this whole argument? Anchor chain introduces sag in the rode. Sag in the rode reduces shock loads. So I guess I was right when I said that anchor chain acts as a shock absorber, eh jaxie? |
yo-yo, IF you had some ham you could have some ham and eggs IF you had some
eggs. let us look at your useless statement. No kidding. With no sag, there is ALWAYS some sag, even with all nylon the anchor pulls loose...something even *you* agreed with. Since anybody with a boat can tell you that anchors actually work and don't pull loose ------------------ most of the time ------------------- , it stands to reason that there must be a lot of sag in the line ---------------------- under most conditions ----------------------. With me so far? If there's a lot of sag in the line, as stated above, there is ALWAYS some sag then the sag provides absorption of shock loads...just as I stated. but ------------------ how much --------------------------- absorbtion? 20 G's is more than the boat can take. In fact, on a 20,000# boat, 2 G's is more than most anchor chain can begin to hold. How much is 2 G's? it is stopping short in 4 inches when moving 8 feet per second. Think of the wave action needed to make a boat move 8 feet in a second. On a 20,000# pound boat that would be a 40,000# strain on the chain, anchor, deck chocks. "JAXAshby" wrote in message ... yo-yo, the shock absorbing capability is dependent on how much sag is in the (inelastic) chain. lots of sag, lots of shock absorbtion. less sag, a hell of a lot less absorbtion. little sag, almost no shock absorbtion. "NOYB" Date: 9/18/2004 10:11 PM Eastern Daylight Time Message-id: "JAXAshby" wrote in message ... genie, shut up. Subject: Why need anchor chain? From: Gene Kearns Date: 9/18/2004 7:46 PM Eastern Daylight Time Message-id: On 18 Sep 2004 21:15:33 GMT, (JAXAshby) wrote: What happens during the interaction of forces on the rode would be most fascinating. a way to simplified look at it is to consider the chain/rode/line to have zero weight pulled between two points (say 100 feet apart), then hang a 1# weight in the center point and check how much strain it put on the end points when the weight hangs 20 feet, then 10 feet, then 5 feet, then 1 foot, then 1 inch, then 1/10th inch. Just use trig to figure the forces. So.... we just used intuitive trig to figure out why (1) we use scope with an anchor and (2) why we don't tie boats to the dock with chain. Now *that* is some real science...... And your "simplified look" does not apply.... an anchor rode does not employ both ends at the same "Y" value.... therefore assumptions of Y=Y'=0 do not obtain and is, therefore, the root cause of your lack of understanding in this area. There isn't *anything* *attached* to the middle. the forces get out of hand ********VERY******** quickly. Even worse, is that the weight in the middle (or chain) has momentum as the boat rocks, so the "natural" position of the weight overshoots and makes for seriously high g-loads. There is no weight "in the middle" (other than the weight of the rode) .... so you put two anchors on the same rode? Odd. Using that concept, most people use kellets and think it is a good and useful idea. http://www.johnsboatstuff.com/Articles/anchor.htm " Having a lot of sag in the rode reduces shock loads " Isn't that what started this whole argument? Anchor chain introduces sag in the rode. Sag in the rode reduces shock loads. So I guess I was right when I said that anchor chain acts as a shock absorber, eh jaxie? |
btw, hoary, a whole lot of 18 year old boys are well past learning one handed
bra removal, and are practising panty removal using the toes. Good grief, Jax. Reigning internet disruptive smartass troll and a circus performer too? How *do* you get your toes up high enough to snag your panties? |
jaxashby :
-Diego Garcia, according to widespread reports, is leased to the US Navy.- Bilge- Leased is the word, chap, leased. It's still under UK flag, British Indian Ocean Territory. Their laws still apply. They decide who comes and who doesn't. But what would I know? I've only been there in 1989, 1996, and 2001&2002. -I understand the indigents removed to Mosambique (?) are still ****ed even after several decades. Perhaps you can enlighten us?-jaxashby Bilge- They were dumped off in Mauritius, and yes, many are still upset. There is litigation that has been moving through the courts of the UK and the US for quite a few years on their behalf. If you'd looked around the website I linked you, you'd see that it is covered at some length... -nah, you are a dum squat.-jaxashby Bilge- Okay....pal. Sail yer little cruiser out to Dodge for a visit...I'll make sure to catch a job back out there and hoist a few brewskis when they seize your "hazard to navigation" and turn it into a "fish habitat" ...assuming you can even make it out that far. GFY Mutiny is a Management Tool Select Your Tattoo while Sober |
btw, hoary, a whole lot of 18 year old boys are well past learning one
handed bra removal, and are practising panty removal using the toes. Good grief, Jax. Reigning internet disruptive smartass troll and a circus performer too? How *do* you get your toes up high enough to snag your panties? _her_ panties. |
|
Subject: Why need anchor chain?
From: (JAXAshby) Date: 09/19/2004 10:07 Pacific Standard Time Message-id: so, how come with all that knowledge, bilge rat, you didn't know of the US Naval presence there? LOL Sounds like another one of your faulty assumptions, based on scanty information, Doodles. Shen |
"JAXAshby" wrote in message ... yo-yo, IF you had some ham you could have some ham and eggs IF you had some eggs. let us look at your useless statement. No kidding. With no sag, there is ALWAYS some sag, even with all nylon Once again...NO KIDDING. I already said that. the anchor pulls loose...something even *you* agreed with. Since anybody with a boat can tell you that anchors actually work and don't pull loose ------------------ most of the time ------------------- , it stands to reason that there must be a lot of sag in the line ---------------------- under most conditions ----------------------. With me so far? If there's a lot of sag in the line, as stated above, there is ALWAYS some sag Correct...just as I stated. then the sag provides absorption of shock loads...just as I stated. but ------------------ how much --------------------------- absorbtion? 20 G's is more than the boat can take. In fact, on a 20,000# boat, 2 G's is more than most anchor chain can begin to hold. It doesn't matter. The fact of the matter is that the anchor rode provides shock absorption...just as I stated. How much is 2 G's? it is stopping short in 4 inches when moving 8 feet per second. Think of the wave action needed to make a boat move 8 feet in a second. On a 20,000# pound boat that would be a 40,000# strain on the chain, anchor, deck chocks. Your math is wrong. |
It doesn't matter. The fact of the matter is that the anchor rode provides
shock absorption...just as I stated. bull****. as you stated. |
"Bilgeman" wrote in message ... Which of us has been there, you half-witted dip****? Comparing jackassby to a half-wit is unfair to half-wits. |
On a 20,000# pound boat that would be a 40,000# strain on the chain, anchor, deck chocks. Your math is wrong. tell it to your phsyicists at at any local college, yo-yo. |
on the other hand, facing criminal manslaughter charges for killing an innocent
bystander is a piece of cake, right? "NOYB" Date: 9/19/2004 9:12 PM Eastern Daylight Time Message-id: "Bilgeman" wrote in message ... Which of us has been there, you half-witted dip****? Comparing jackassby to a half-wit is unfair to half-wits. |
"JAXAshby" wrote in message ... on the other hand, facing criminal manslaughter charges for killing an innocent bystander is a piece of cake, right? Because my anchor rode provided shock absorption? |
******************* failed ******************** to provide. as any idiot would
expect. on the other hand, facing criminal manslaughter charges for killing an innocent bystander is a piece of cake, right? Because my anchor rode provided shock absorption? |
"JAXAshby" wrote in message ... yo-yo, IF you had some ham you could have some ham and eggs IF you had some eggs. let us look at your useless statement. No kidding. With no sag, there is ALWAYS some sag, even with all nylon And if this is true as you say there is always shock absorption available according to your reasoning. |
no as in you do not know. Where is the catenary you say in this quote:
"yo-yo, a string strung between two points has, and always has, a catenary. " "JAXAshby" wrote in message ... no. Where is the catenary on a yo-yo hanging from a finger? It is a line between 2 points. "JAXAshby" wrote in message ... clown, check the meaning of the word. Gene Kearns Date: 9/18/2004 7:22 PM Eastern Daylight Time Message-id: On 18 Sep 2004 20:49:57 GMT, (JAXAshby) wrote: spell it any way you want, you still do not have any idea what it is. yo-yo, a string strung between two points has, and always has, a catenary. go look it up. And a yo-yo is about the depth of your comprehension, here.... -- Grady-White Gulfstream, out of Southport, NC. http://myworkshop.idleplay.net/cavern/ Homepage http://www.southharbourvillageinn.com/directions.asp Where Southport,NC is located. http://www.thebayguide.com/rec.boats Rec.boats at Lee Yeaton's Bayguide |
tomf123 quips:
-Yep - it's Monday, sure as heck. :)- Bilge-Yep, all freakin' day. Say, chum, you seem to have an IQ above room temperature, and to know the difference between a bow pulpit and a saloon urinal... What the hell's the deal with this newsgroup...is there a computer terminal in the day room of some looney bin somewhere? A lot of the posters in this group seem to sorely lacking in heavy meds and long term, probing bouts of intensive therapy. It was those damned movies, right? Too many booger-eaters saw "The Perfect Storm" and "Pirates of the Carribean" and decided to "run off to sea" and be Depp, Clooney, and Wahlberg, right? I swear to Almighty, some of these drooling half-wits should have a mast riveted to their foreheads and be flying 4 black balls from it. I wouldn't trust some of these clowns to captain a rubber duck in a sitz bath, let alone a motor or sailing vessel on the high seas. WTF? Mutiny is a Management Tool Select Your Tattoo while Sober |
to those who don't know who the scum bag Bilge Rat is, he makes a living --
such as it is -- crawling around the lowest spots in a filthy cargo ships to replace worn electrical wiring. this, of course, makes him an expert in recreational boats and how they are used. (Bilgeman) Date: 9/20/2004 7:16 AM Eastern Daylight Time Message-id: tomf123 quips: -Yep - it's Monday, sure as heck. :)- Bilge-Yep, all freakin' day. Say, chum, you seem to have an IQ above room temperature, and to know the difference between a bow pulpit and a saloon urinal... What the hell's the deal with this newsgroup...is there a computer terminal in the day room of some looney bin somewhere? A lot of the posters in this group seem to sorely lacking in heavy meds and long term, probing bouts of intensive therapy. It was those damned movies, right? Too many booger-eaters saw "The Perfect Storm" and "Pirates of the Carribean" and decided to "run off to sea" and be Depp, Clooney, and Wahlberg, right? I swear to Almighty, some of these drooling half-wits should have a mast riveted to their foreheads and be flying 4 black balls from it. I wouldn't trust some of these clowns to captain a rubber duck in a sitz bath, let alone a motor or sailing vessel on the high seas. WTF? Mutiny is a Management Tool Select Your Tattoo while Sober |
**some** is a pedant use of the word. particularly in the context of multi-G
shock loads. i.e. "reducing" by "some" measure from 4.898 G's to 4.89799983 G's. which word don't you understand, billei? Date: 9/20/2004 1:18 AM Eastern Daylight Time Message-id: . net "JAXAshby" wrote in message ... yo-yo, IF you had some ham you could have some ham and eggs IF you had some eggs. let us look at your useless statement. No kidding. With no sag, there is ALWAYS some sag, even with all nylon And if this is true as you say there is always shock absorption available according to your reasoning. |
mathematically, when then two points are one above the other you have, to use a
mathematical term, the trivial case. It is not an interesting case in this discussion, but you are welcome to deal with the trivial case as long as you want. the rest of us will deal the infinity of useful cases. Date: 9/20/2004 1:21 AM Eastern Daylight Time Message-id: . net no as in you do not know. Where is the catenary you say in this quote: "yo-yo, a string strung between two points has, and always has, a catenary. " "JAXAshby" wrote in message ... no. Where is the catenary on a yo-yo hanging from a finger? It is a line between 2 points. "JAXAshby" wrote in message ... clown, check the meaning of the word. Gene Kearns Date: 9/18/2004 7:22 PM Eastern Daylight Time Message-id: On 18 Sep 2004 20:49:57 GMT, (JAXAshby) wrote: spell it any way you want, you still do not have any idea what it is. yo-yo, a string strung between two points has, and always has, a catenary. go look it up. And a yo-yo is about the depth of your comprehension, here.... -- Grady-White Gulfstream, out of Southport, NC. http://myworkshop.idleplay.net/cavern/ Homepage http://www.southharbourvillageinn.com/directions.asp Where Southport,NC is located. http://www.thebayguide.com/rec.boats Rec.boats at Lee Yeaton's Bayguide |
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