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Submarines, Car Engines, and Displacement
I've had a few random questions rattling around the
brain for a while - figured I'd pose them there. When a sub dives to a certain depth, is that depth measured from the bottom of the sub, the middle, or the top. In other words, if it dives to 200 feet, does that mean there is 200 feet of water above it or that the bottom of it is 200 feet below the surface? On modern gas car engines and when it's cold outside, is it still better to let them warm up a bit and how warm (how long) is necessary? Anyone have a good way to find the total surface area of my boat hull while it's in the water? It's a 22' boat, not very deep V, "square" transom. I did some estimating, but wonder if there are any creative ways to get more accurate. Gary |
Submarines, Car Engines, and Displacement
On Tue, 6 Jan 2004 19:24:30 -0500, "Gary Warner"
wrote: I've had a few random questions rattling around the brain for a while - figured I'd pose them there. When a sub dives to a certain depth, is that depth measured from the bottom of the sub, the middle, or the top. In other words, if it dives to 200 feet, does that mean there is 200 feet of water above it or that the bottom of it is 200 feet below the surface? On modern gas car engines and when it's cold outside, is it still better to let them warm up a bit and how warm (how long) is necessary? Anyone have a good way to find the total surface area of my boat hull while it's in the water? It's a 22' boat, not very deep V, "square" transom. I did some estimating, but wonder if there are any creative ways to get more accurate. Gary Gary, I can tell you only that the surface area of your boat is the same both in and out of the water. John H On the 'Poco Loco' out of Deale, MD on the beautiful Chesapeake Bay! |
Submarines, Car Engines, and Displacement
Gary Warner wrote:
When a sub dives to a certain depth, is that depth measured from the bottom of the sub, the middle, or the top. In other words, if it dives to 200 feet, does that mean there is 200 feet of water above it or that the bottom of it is 200 feet below the surface? Normally "depth to keel." On modern gas car engines and when it's cold outside, is it still better to let them warm up a bit and how warm (how long) is necessary? RTFM Anyone have a good way to find the total surface area of my boat hull while it's in the water? It's a 22' boat, not very deep V, "square" transom. I did some estimating, but wonder if there are any creative ways to get more accurate. Assuming you are seeking the "wetted area" rent one of those laser thingys that scan a surface into a computer. Turn your boat on its side and scan. Read computer generated results. Rick |
Submarines, Car Engines, and Displacement
When a sub dives to a certain depth, is that depth
measured from the bottom of the sub, the middle, or the top. In other words, if it dives to 200 feet, does that mean there is 200 feet of water above it or that the bottom of it is 200 feet below the surface? Normally "depth to keel. I don't know squat diddly about submarines, but I think I can answer this question. *If* the dive indicator reads "zero" when the sub is on the surface, the submerged depth would be measured from the normally ballasted waterline to the surface. It wouldn't seem logical, otherwise. |
Submarines, Car Engines, and Displacement
On Tue, 6 Jan 2004 19:24:30 -0500, "Gary Warner"
wrote: I've had a few random questions rattling around the brain for a while - figured I'd pose them there. When a sub dives to a certain depth, is that depth measured from the bottom of the sub, the middle, or the top. In other words, if it dives to 200 feet, does that mean there is 200 feet of water above it or that the bottom of it is 200 feet below the surface? Interesting question but I have no idea. On modern gas car engines and when it's cold outside, is it still better to let them warm up a bit and how warm (how long) is necessary? Not necessary at all assuming everthing is in tune and the engine is running smoothly. Just don't over rev the engine until it's up to operating temperature, usually within a few miles. Anyone have a good way to find the total surface area of my boat hull while it's in the water? It's a 22' boat, not very deep V, "square" transom. I did some estimating, but wonder if there are any creative ways to get more accurate. If you piece it out into a rectangle and a triangle on each side, you can get pretty close with a deep V hull. Given the deadrise angle and length we could develop a trig formula that would be a good approximation, but it's easier to piece it out, and you'll have a better intuitive sense of the answer. (Length x Beam) + a small fudge factor will also get you pretty close. |
Submarines, Car Engines, and Displacement
"Gary Warner" wrote in message ... I've had a few random questions rattling around the brain for a while - figured I'd pose them there. When a sub dives to a certain depth, is that depth measured from the bottom of the sub, the middle, or the top. In other words, if it dives to 200 feet, does that mean there is 200 feet of water above it or that the bottom of it is 200 feet below the surface? 8 years on submarines and it is bottom of keel. Most subs read about 65 feet at periscope depth which has the sail about 5 to 10 feet below the surface. On modern gas car engines and when it's cold outside, is it still better to let them warm up a bit and how warm (how long) is necessary? Not an expert but, cold starts are a major cause of engine wear. The oil is too thick to get through all the passages quickly. Yes, let it warm at least a little before raising rpm's to drive. Anyone have a good way to find the total surface area of my boat hull while it's in the water? It's a 22' boat, not very deep V, "square" transom. I did some estimating, but wonder if there are any creative ways to get more accurate. No idea!! |
Submarines, Car Engines, and Displacement
8 years on submarines and it is bottom of keel. Most
subs read about 65 feet at periscope depth which has the sail about 5 to 10 feet below the surface. Fascinating. What does the depth indicator say when the sub is surfaced? Obviously it would not be zero. |
Submarines, Car Engines, and Displacement
The experts say in cold weather (below freezing) to warm the car up for a
couple of minutes and then drive away at a moderate pace. Apparently it's much easier on the engine.... very inefficient to let a car sit at idle...as oil not circulated as well as when on the move. Gary Warner wrote in message On modern gas car engines and when it's cold outside, is it still better to let them warm up a bit and how warm (how long) is necessary? |
Submarines, Car Engines, and Displacement
"Wayne.B" wrote in message ... On Tue, 6 Jan 2004 19:24:30 -0500, "Gary Warner" wrote: I've had a few random questions rattling around the brain for a while - figured I'd pose them there. When a sub dives to a certain depth, is that depth measured from the bottom of the sub, the middle, or the top. In other words, if it dives to 200 feet, does that mean there is 200 feet of water above it or that the bottom of it is 200 feet below the surface? Interesting question but I have no idea. On modern gas car engines and when it's cold outside, is it still better to let them warm up a bit and how warm (how long) is necessary? Not necessary at all assuming everthing is in tune and the engine is running smoothly. Just don't over rev the engine until it's up to operating temperature, usually within a few miles. Anyone have a good way to find the total surface area of my boat hull while it's in the water? It's a 22' boat, not very deep V, "square" transom. I did some estimating, but wonder if there are any creative ways to get more accurate. If you piece it out into a rectangle and a triangle on each side, you can get pretty close with a deep V hull. Given the deadrise angle and length we could develop a trig formula that would be a good approximation, but it's easier to piece it out, and you'll have a better intuitive sense of the answer. (Length x Beam) + a small fudge factor will also get you pretty close. When the boat is in the water, draw a line on the side a short distance above the water line, say 1 inch, with a grease pencil or sharpie marker. Then when the boat is out, use a 1 foot square of cardboard and trace around it to make a grid from the keel to the waterline. Only have to do half the boat, and so only will have maybe 50 or 60 squares. you could make smaller rectangles or triangles to fill in gaps if you are going for ultimate accuracy. Suggestion 2. Instead of the squares, cut black plastic and tape to exactly cover wetted surface. Weigh on accurate scale. Weigh a known area. divide. del cecchi |
Submarines, Car Engines, and Displacement
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Submarines, Car Engines, and Displacement
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Submarines, Car Engines, and Displacement
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Submarines, Car Engines, and Displacement
Gould 0738 wrote:
It wouldn't seem logical, otherwise. Posting an answer to something I know nothing about is illogical. Rick |
Submarines, Car Engines, and Displacement
Fascinating. What does the depth indicator say when the sub is surfaced?
Obviously it would not be zero. That would depend on how far it surfaced. Did it blow all ballast or is it just barely surfaced? Steve It can't blow enough ballast to put the keel on the surface. My point is merely that if the depth is measured between the surface and the keel, (and I have no reason to doubt that it is) there could never be a "zero" reading. |
Submarines, Car Engines, and Displacement
Posting an answer to something I know nothing about is illogical.
Rick I don't dispute that- ergo the disclaimer. But if the depth is measured from the keel and there is a depth indicator on the sub it will never read zero. Is that somehow incorrect? That was why I postulated *if* a depth guage read zero at the surface the reading would have to be from the normally ballasted waterline. Since it apparently does not read zero, that theory doesn't fly. Freely admitted. |
Submarines, Car Engines, and Displacemen
Gary Warner wrote:
I've had a few random questions rattling around the brain for a while - figured I'd pose them there. When a sub dives to a certain depth, is that depth measured from the bottom of the sub, the middle, or the top. In other words, if it dives to 200 feet, does that mean there is 200 feet of water above it or that the bottom of it is 200 feet below the surface? Depth below the surface, but pass on which part of the boat they measure from. It's really just a measure of pressure on the hull not "depth" as such, but the result is the same; unless it's in warm fresh water:-) On modern gas car engines and when it's cold outside, is it still better to let them warm up a bit and how warm (how long) is necessary? Modern?? with modern multigrade oils??? A little warmup while you fix the phone & belt up etc is OK but don't leave it just idling. The best thing is to get it up to thermostat temp as soon as possible & to do that it's best making some power (it takes forever if just left idling). On the other side don't jump in a cold engine & take it to max power, revs etc, that's not sensible either. Anyone have a good way to find the total surface area of my boat hull while it's in the water? It's a 22' boat, not very deep V, "square" transom. I did some estimating, but wonder if there are any creative ways to get more accurate. From your thread title I think you want the "volume" of the hull below the water line??? not the area??? Also your question seems to suggest "while it's in the water"?? you want to work this out without pulling the boat out?? For the surface area, most of the anitfoul paints, either on the tin or a pamphlet, have a simple method to work out how much paint you'll need. But they're not too accurate. To measure surface area accurately you'll need to measure 1/2 the bottom of the boat & that part of the sides (if a chine boat) below the waterline, where ever possible reduce it to oblongs or squares, then various right triangles when you run out of easy oblongs etc. Add them all together, double it & that's the total surface area. In boat design they use a planimeter to run over the lines. To calculate the "displacement" (volume of the boat below the waterline) you can actually get a pretty accurate measurement by using "simpson's formula" even as your question seems to suggest, with the boat still in the water by; (i) Boats are usually designed on 10 "sections" i.e. notionally the boat has 11 transverse stations/bulkheads across it equal distance apart from the waterline bow. Say a 30 ft WL boat they'd be 3ft apart?? These stations/bulkheads are not "real", although usually bulkheads are at a station point, but whatever but you can easily measure with a tape what the below waterline areas would be, even on a bigger boat. (ii) You need to measure the "area" of each of those notional stations/bulkheads, but just that area which is below the waterline. (again designers with plans drawings etc run around the 1/2 shape X3 div by 3 to average with a planimeter) (iii) Once you know the below the waterline only area in sq ft of each of the boat's 10 notional stations, you multiple each by simpson's multipliers 1,4,2,4,2,4,2,4,2,4,1 (11 notional below waterline stations/bulkheads gives 10 equal length sections of the boat) (iv) Add all the answers together so you now have the sum of functions. (v) Use simpson's formula to work out the boat or ship's current displacement per; 2 X 1/3 X sum of functions of 1/2 areas X (inverted scale)sq X the common interval X 64 = displacement in ponds of salt water, or for fresh water use 62.2 as the last figure. This is the formula as used in boat design, so it is a bit more yuk than you need, all you need is; (a) 2 is to account for only using 1/2 the below waterline station/bulkhead area, you can leave it out if you measured the full sq ft of each area before using his multipliers. (b) 1/3 is just part of the formula. (c) Sum of the functions is explained in (iv) above. (but designers tend to just use 1/2 then multiply by 2 see (a)) (d) Inverted scale squared doesn't bother you because you can use feet as a direct measure, whereas a designer might be using say 1/2" to the foot in their drawings. So make sure your notional below the waterline areas or 1/2 areas if you choose, are in sq ft. (e) Common interval is the length in feet of each section, again say it's waterline length of 30 ft the "common interval" is 3. (f) At this point the formula should have delivered you the boat's below the waterline volume in cubic feet, the 64 is just the weight in pounds of a cubic ft of salt water, or 62.2 for fresh water; to give you the displacement in lbs (weight of the boat). K Gary |
Submarines, Car Engines, and Displacement
On Tue, 06 Jan 2004 19:24:30 -0500, Gary Warner wrote:
Anyone have a good way to find the total surface area of my boat hull while it's in the water? It's a 22' boat, not very deep V, "square" transom. I did some estimating, but wonder if there are any creative ways to get more accurate. Total area of the boat hull, or just what's in the water i.e. waterplane area? You could use the pounds per inch immersion formula. http://dan.pfeiffer.net/boat/ratios.htm#lbsin |
Submarines, Car Engines, and Displacement
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Submarines, Car Engines, and Displacement
On Wed, 07 Jan 2004 00:20:29 -0500, Wayne.B
wrote: On 07 Jan 2004 02:52:36 GMT, (Gould 0738) wrote: Fascinating. What does the depth indicator say when the sub is surfaced? Obviously it would not be zero. We used to see subs on the surface all the time in eastern Long Island Sound (sub base at Groton, CT). Only the conning tower and maybe 6 to 8 feet of hull is exposed at most when they are surfaced. Estimating that the conning tower is submerged by 10 feet at periscope depth, the height of the tower at 20 feet, plus 8 feet of hull - that would put you about 38 feet above the periscope depth reading. If you motor up the Thames River from New London, CT, you can actually see partially assembled cross sections of subs on dry land. They look incredibly big, even from a distance. And you really don't want to take a lot of pictures or try to get closer. :-) It's even more fun out at The Race when those subs go by - it's quite a ride when they sneak up on you. I damn near got tossed out of my Ranger once fishing the rip halfway between Race Rock and LI. Damn subs. :) Later, Tom S. Woodstock, CT ---------- "My rod and my reel - they comfort me." St. Pete, 12 Lb. Test |
Submarines, Car Engines, and Displacement
"Gould 0738" wrote in message ... Fascinating. What does the depth indicator say when the sub is surfaced? Obviously it would not be zero. That would depend on how far it surfaced. Did it blow all ballast or is it just barely surfaced? Steve It can't blow enough ballast to put the keel on the surface. My point is merely that if the depth is measured between the surface and the keel, (and I have no reason to doubt that it is) there could never be a "zero" reading. There is never a "Zero" reading, when on the surface it is mid to high 30's depending on the type of sub. Also for safety sake we never surface a little bit, when we surface all ballast is blown. Terry |
Submarines, Car Engines, and Displacement
There is never a "Zero" reading, when on the surface it
is mid to high 30's depending on the type of sub. Also for safety sake we never surface a little bit, when we surface all ballast is blown. Terry Thanks! |
Submarines, Car Engines, and Displacement
"del cecchi" wrote Ahhh yes, there are the creative ideas I was thinking must be out there. Thanks to everyone that responded to these questions. |
Submarines, Car Engines, and Displacemen
"K Smith" From your thread title I think you want the "volume" of the hull below the water line??? not the area??? Also your question seems to suggest "while it's in the water"?? you want to work this out without pulling the boat out?? Sorry, not worded clearly on my part. I'm looking for the area. Reason is just for curiosity. Reason I want the area is to calculate the pressure per square inch. Example: Boat is 4000 lbs, area where it touches the water is X. So approximate pounds/square inch is Y. No, I don't need to do this IN the water. What I was trying to say is that I only want the area that TOUCHES the water. The remaining area of the hull would not be "supporting" the boat while in the water. It's just a winter month curiosity exercise. Thanks. |
Submarines, Car Engines, and Displacement
Again, thanks for all the answers.
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Submarines, Car Engines, and Displacement
Gould 0738 wrote: I don't dispute that- ergo the disclaimer. But if the depth is measured from the keel and there is a depth indicator on the sub it will never read zero. Is that somehow incorrect? That was why I postulated *if* a depth guage read zero at the surface the reading would have to be from the normally ballasted waterline. Since it apparently does not read zero, that theory doesn't fly. Freely admitted. It has never been part of submarine law that it must read zero on the surface. Why should it? The depth to keel is also an indication of freeboard. A submarine, after surfacing, will use a low pressure blower to push the last bit of water from the ballast tanks in order to increase the freeboard. The depth gauge shows when it is as high as it will go. Rick |
Submarines, Car Engines, and Displacement
"Rick" wrote: On modern gas car engines and when it's cold outside, is it still better to let them warm up a bit and how warm (how long) is necessary? RTFM I read the f'ing manual. It explains how to start it in the cold but not a word about warming it up or idling. |
Submarines, Car Engines, and Displacemen
"Gary Warner" wrote in message ... Sorry, not worded clearly on my part. I'm looking for the area. Reason is just for curiosity. Reason I want the area is to calculate the pressure per square inch. Example: Boat is 4000 lbs, area where it touches the water is X. So approximate pounds/square inch is Y. No, I don't need to do this IN the water. What I was trying to say is that I only want the area that TOUCHES the water. The remaining area of the hull would not be "supporting" the boat while in the water. It's just a winter month curiosity exercise. Thanks. Do not need the wetted area of the boat for those calculations. Just how far under water is the square inch. And take the average depth of the location and multiply by the pressure at depth. And the pressure is a little under 1/2 psi per inch of depth. Bill |
Submarines, Car Engines, and Displacemen
K Smith wrote:
This is a mea culpa. I've made a mistake!! (yes, yes I know; again!!) If there is anything I can say in mitigation, it's that I did realise it on my own, get it checked this time:-) & have now tried to belatedly correct it. To measure surface area accurately you'll need to measure 1/2 the bottom of the boat & that part of the sides (if a chine boat) below the waterline, where ever possible reduce it to oblongs or squares, then various right triangles when you run out of easy oblongs etc. Add them all together, double it & that's the total surface area. In boat design they use a planimeter to run over the lines. To calculate the "displacement" (volume of the boat below the waterline) you can actually get a pretty accurate measurement by using "simpson's formula" even as your question seems to suggest, with the boat still in the water by; (i) Boats are usually designed on 10 "sections" i.e. notionally the boat has 11 transverse stations/bulkheads across it equal distance apart from the waterline bow. Say a 30 ft WL boat they'd be 3ft apart?? These stations/bulkheads are not "real", although usually bulkheads are at a station point, but whatever but you can easily measure with a tape what the below waterline areas would be, even on a bigger boat. (ii) You need to measure the "area" of each of those notional stations/bulkheads, but just that area which is below the waterline. This is WRONG it's not the "area" it's the perimeter length or circumference!! Having made this error I carried it on through the rest of the description. (again designers with plans drawings etc run around the 1/2 shape X3 div by 3 to average with a planimeter) Damn!!! I even correctly described how designers measure the perimeter length of irregular shapes, but once I had a mindset of "area", well there ya go, I'm sorry again. (iii) Once you know the below the waterline only area in sq ft This should read "Once you know the below the waterline only perimeter length in inches" of each of the boat's 10 notional stations, you multiple each by simpson's multipliers 1,4,2,4,2,4,2,4,2,4,1 (11 notional below waterline stations/bulkheads gives 10 equal length sections of the boat) (iv) Add all the answers together so you now have the sum of functions. (v) Use simpson's formula to work out the boat or ship's current displacement per; 2 X 1/3 X sum of functions of 1/2 areas X (inverted scale)sq X the common interval X 64 = displacement in ponds of salt water, or for fresh water use 62.2 as the last figure. This is the formula as used in boat design, so it is a bit more yuk than you need, all you need is; (a) 2 is to account for only using 1/2 the below waterline station/bulkhead area, you can leave it out if you measured the full sq ft of each area before using his multipliers. (b) 1/3 is just part of the formula. (c) Sum of the functions is explained in (iv) above. (but designers tend to just use 1/2 then multiply by 2 see (a)) (d) Inverted scale squared doesn't bother you because you can use feet as a direct measure, whereas a designer might be using say 1/2" to the foot in their drawings. So make sure your notional below the waterline areas or 1/2 areas if you choose, are in sq ft. This whole paragraph needs correction because clearly if you have the sum of functions in inches then you don't need to adjust for scale. So you just use you answer from (iv) (e) Common interval is the length in feet of each section, again say it's waterline length of 30 ft the "common interval" is 3. (f) At this point the formula should have delivered you the boat's below the waterline volume in cubic feet, the 64 is just the weight in pounds of a cubic ft of salt water, or 62.2 for fresh water; to give you the displacement in lbs (weight of the boat). The rest looks pretty much OK, so I hope not too many of you have been working in vain on this:-) Of course I know I know I know nobody even read it:-) but so what?? it was wrong:-) I can't help but correct it for the record. Sincere apologies again. K K Gary |
Submarines, Car Engines, and Displacement
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Submarines, Car Engines, and Displacement
On Sat, 10 Jan 2004 01:44:51 +0000, James Johnson wrote:
If you do an emergency blow from test depth, the forward third of the boat will come completely out of the water when the boat reaches the surface. For those few seconds I think that would be a 'zero' reading. I think we have all seen pictures of that, quite impressive. I've always wondered what it would be like inside at the time. It must be a rather rough ride? |
Submarines, Car Engines, and Displacement
yes, a sub can read zero ! talking to my dad who worked on subs, actually
the gauge can be re-calibrated thus zero can be read. at any point they wish, when the bottom of the hull is still 20feet below the surface. Most of you, do not even know, nuclear bombs are also placed in special torpedoes, of which it would not take more than two to take out Cuba !!! "James Johnson" wrote in message ... On 07 Jan 2004 08:04:48 GMT, (Gould 0738) wrote: Fascinating. What does the depth indicator say when the sub is surfaced? Obviously it would not be zero. That would depend on how far it surfaced. Did it blow all ballast or is it just barely surfaced? Steve If you do an emergency blow from test depth, the forward third of the boat will come completely out of the water when the boat reaches the surface. For those few seconds I think that would be a 'zero' reading. JJ It can't blow enough ballast to put the keel on the surface. My point is merely that if the depth is measured between the surface and the keel, (and I have no reason to doubt that it is) there could never be a "zero" reading. James Johnson remove the "dot" from after sail in email address to reply |
Submarines, Car Engines, and Displacement
"Joseph Stachyra" wrote (snip ) Most of you, do not even know, nuclear bombs are also placed in special torpedoes, of which it would not take more than two to take out Cuba !!! Please, don't even think that about Cuba. It is a beautiful country and I am going boating there, in February, for my annual winter vaction!!!! Jim Carter "The Boat" Bayfield |
Submarines, Car Engines, and Displacement
Jim Carter wrote:
"Joseph Stachyra" wrote (snip ) Most of you, do not even know, nuclear bombs are also placed in special torpedoes, of which it would not take more than two to take out Cuba !!! Please, don't even think that about Cuba. It is a beautiful country and I am going boating there, in February, for my annual winter vaction!!!! Jim Carter "The Boat" Bayfield Good grief. Cuba. Why are we still at war with Cuba? If there is a dumber American foreign policy than what we've done with Cuba for the last half-century, I'm unaware of it. Even today, Bush is kissing the ass of the PRC and horrific dictatorships all over the world, but is kicking Cuba in the ass. Ker-ripes. -- Email sent to is never read. |
Submarines, Car Engines, and Displacement
On Sat, 10 Jan 2004 16:03:06 GMT, "Joseph Stachyra"
wrote: yes, a sub can read zero ! talking to my dad who worked on subs, actually the gauge can be re-calibrated thus zero can be read. at any point they wish, when the bottom of the hull is still 20feet below the surface. Most of you, do not even know, nuclear bombs are also placed in special torpedoes, of which it would not take more than two to take out Cuba !!! There are also nuclear bombs on depth charges, of which it would not take more than one to take out a submarine.:) Steve |
Submarines, Car Engines, and Displacement
On Sat, 10 Jan 2004 11:26:24 -0500, Harry Krause
wrote: Jim Carter wrote: "Joseph Stachyra" wrote (snip ) Most of you, do not even know, nuclear bombs are also placed in special torpedoes, of which it would not take more than two to take out Cuba !!! Please, don't even think that about Cuba. It is a beautiful country and I am going boating there, in February, for my annual winter vaction!!!! Jim Carter "The Boat" Bayfield Good grief. Cuba. Why are we still at war with Cuba? If there is a dumber American foreign policy than what we've done with Cuba for the last half-century, I'm unaware of it. We're at war with Cuba? That I was unaware of. Even today, Bush is kissing the ass of the PRC and horrific dictatorships all over the world, but is kicking Cuba in the ass. We just need to strip the Cuban exiles in this country of their right to vote and then we can all visit Cuba and spend our money there legally. Steve |
Submarines, Car Engines, and Displacement
Steven Shelikoff wrote:
On Sat, 10 Jan 2004 11:26:24 -0500, Harry Krause wrote: Jim Carter wrote: "Joseph Stachyra" wrote (snip ) Most of you, do not even know, nuclear bombs are also placed in special torpedoes, of which it would not take more than two to take out Cuba !!! Please, don't even think that about Cuba. It is a beautiful country and I am going boating there, in February, for my annual winter vaction!!!! Jim Carter "The Boat" Bayfield Good grief. Cuba. Why are we still at war with Cuba? If there is a dumber American foreign policy than what we've done with Cuba for the last half-century, I'm unaware of it. We're at war with Cuba? That I was unaware of. Don't be so literal, Steve. It doesn't become you. Even today, Bush is kissing the ass of the PRC and horrific dictatorships all over the world, but is kicking Cuba in the ass. We just need to strip the Cuban exiles in this country of their right to vote and then we can all visit Cuba and spend our money there legally. Steve Well, we do need to ensure that after Castro, the exiles don't go back and try to assert some "rights" they think they have. -- Email sent to is never read. |
Submarines, Car Engines, and Displacement
On Fri, 09 Jan 2004 23:01:53 -0500, thunder wrote:
On Sat, 10 Jan 2004 01:44:51 +0000, James Johnson wrote: If you do an emergency blow from test depth, the forward third of the boat will come completely out of the water when the boat reaches the surface. For those few seconds I think that would be a 'zero' reading. I think we have all seen pictures of that, quite impressive. I've always wondered what it would be like inside at the time. It must be a rather Everything is rattling, shaking and vibrating on the way up. When you break the surface it suddenly gets a lot quieter, and the fall back down is surprisingly gentle compared to the ride up. JJ rough ride? James Johnson remove the "dot" from after sail in email address to reply |
Submarines, Car Engines, and Displacement
On Sat, 10 Jan 2004 16:21:30 GMT, "Jim Carter" wrote: "Joseph Stachyra" wrote (snip ) Most of you, do not even know, nuclear bombs are also placed in special torpedoes, of which it would not take more than two to take out Cuba !!! I don't think the Mark45 has been deployed in decades. They were not very practical, for even at maximum range and the boat pointed either directly towards or directly away from the target there was a surprisingly large chance that you would not survive the shock waves. Cruise missiles made them obsolete. JJ Please, don't even think that about Cuba. It is a beautiful country and I am going boating there, in February, for my annual winter vaction!!!! Jim Carter "The Boat" Bayfield James Johnson remove the "dot" from after sail in email address to reply |
Submarines, Car Engines, and Displacement
snip
Well, we do need to ensure that after Castro, the exiles don't go back and try to assert some "rights" they think they have. I heard from someone who had been to Cuba often that the Cubans aren't going to have somebody in power who fled to the US and missed the "Hard Times" under Castro. Maybe it was on one of the boat groups, now that I think about it. Mark E. Williams |
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