Subject: Which way does a boat turn?
From: (JAXAshby)


sherr, ever hear "For each action there is an equal and opposite reaction"?

Yup. I think it's basic physics ....larn't it in gramma school.

if you have, why do you seem to think it doesn't apply underwater?

hmmm let me try and draw a pitcher fer ya.
Your looking at this here paddle wheel just beneath the surface of the water
(totally submerged), from the side, which is rotating clockwise through 360
deg.
It is being driven by a shaft coming out the stern of a boat, longitudinally,
and the whole paddlewheel is located just aft of the transom. (kinda like a RH
paddlewheel).
Now, are you trying to tell me that the amount of "push" that these paddles
develope against the boat, is the same between 090 and 180 deg. rotation as it
is between 270 and 360 deg ?

Shen

Subject: Which way does a boat turn?
From: (JAXAshby)


sherr, ever hear "For each action there is an equal and opposite reaction"?

Yup. I think it's basic physics ....larn't it in gramma school.

if you have, why do you seem to think it doesn't apply underwater?

hmmm let me try and draw a pitcher fer ya.
Your looking at this here paddle wheel just beneath the surface of the water
(totally submerged), from the side, which is rotating clockwise through 360
deg.
It is being driven by a shaft coming out the stern of a boat, longitudinally,
and the whole paddlewheel is located just aft of the transom. (kinda like a RH
paddlewheel).
Now, are you trying to tell me that the amount of "push" that these paddles
develope against the boat, is the same between 090 and 180 deg. rotation as it
is between 270 and 360 deg ?

Shen

"Shen44" wrote

hmmm let me try and draw a pitcher fer ya.
Your looking at this here paddle wheel just beneath the surface of the
water
(totally submerged), from the side, which is rotating clockwise through
360
deg.
It is being driven by a shaft coming out the stern of a boat,
longitudinally,
and the whole paddlewheel is located just aft of the transom. (kinda like
a RH
paddlewheel).
Now, are you trying to tell me that the amount of "push" that these
paddles
develope against the boat, is the same between 090 and 180 deg. rotation
as it
is between 270 and 360 deg ?

I would guess yes. But I don't know. And I was picturing a side wheeler.

Sv

"Shen44" wrote

hmmm let me try and draw a pitcher fer ya.
Your looking at this here paddle wheel just beneath the surface of the
water
(totally submerged), from the side, which is rotating clockwise through
360
deg.
It is being driven by a shaft coming out the stern of a boat,
longitudinally,
and the whole paddlewheel is located just aft of the transom. (kinda like
a RH
paddlewheel).
Now, are you trying to tell me that the amount of "push" that these
paddles
develope against the boat, is the same between 090 and 180 deg. rotation
as it
is between 270 and 360 deg ?

I would guess yes. But I don't know. And I was picturing a side wheeler.

Sv

It would appear that Shen is replacing the prop of a boat with a
paddle wheel and locating it aft of the transom, as a follow up to
someone else's post, using the paddlewheel. However, in his example a
side-wheeler would work as long as you submerge the entire wheel.
Can you explain why the force exerted by the blades at those angles
would be equal....though opposite?

otn

Scott Vernon wrote:
"Shen44" wrote

hmmm let me try and draw a pitcher fer ya.
Your looking at this here paddle wheel just beneath the surface of the

water

(totally submerged), from the side, which is rotating clockwise through

360

deg.
It is being driven by a shaft coming out the stern of a boat,

longitudinally,

and the whole paddlewheel is located just aft of the transom. (kinda like

a RH

paddlewheel).
Now, are you trying to tell me that the amount of "push" that these

paddles

develope against the boat, is the same between 090 and 180 deg. rotation

as it

is between 270 and 360 deg ?


I would guess yes. But I don't know. And I was picturing a side wheeler.

Sv

It would appear that Shen is replacing the prop of a boat with a
paddle wheel and locating it aft of the transom, as a follow up to
someone else's post, using the paddlewheel. However, in his example a
side-wheeler would work as long as you submerge the entire wheel.
Can you explain why the force exerted by the blades at those angles
would be equal....though opposite?

otn

Scott Vernon wrote:
"Shen44" wrote

hmmm let me try and draw a pitcher fer ya.
Your looking at this here paddle wheel just beneath the surface of the

water

(totally submerged), from the side, which is rotating clockwise through

360

deg.
It is being driven by a shaft coming out the stern of a boat,

longitudinally,

and the whole paddlewheel is located just aft of the transom. (kinda like

a RH

paddlewheel).
Now, are you trying to tell me that the amount of "push" that these

paddles

develope against the boat, is the same between 090 and 180 deg. rotation

as it

is between 270 and 360 deg ?


I would guess yes. But I don't know. And I was picturing a side wheeler.

Sv

Subject: Which way does a boat turn?
From: "Scott Vernon"

I would guess yes. But I don't know. And I was picturing a side wheeler.

Sv

Ok, continue to picture a sidewheeler.
Now, in hopes of further clarifying what I'm trying to describe, the
paddlewheel is 6' in diameter and you totally submerge it to a point, say, 6"
beneath the water.
Your boat is floating in 200' of water with no land in sight (i.e., you've just
got water with the earth beneath it and water with air, 6" above it).
Looking at the "wheel" from the side and starting at a rotation angle of 090,
as the blade of the wheel rotates clockwise to 180 deg, it is pushing down and
to the left, against a solid non compressible column of water, 200ish feet deep
(it's working as efficiently as it can) and pulling the boat to your right.
Now look at the blades in the opposite quadrant (270 - 360). Starting at 270
and rotating towards 360, the blades are pushing up and to the right, against
........ a 3' 6" column of water with nothing but good old compressible air
above. What happens?
Basically the blades lift that column of water and throw it away into the air,
losing a high percentage of their efficiency to pull down and to the left,
compared to their opposite quadrant.
If you look at 000 - 090, compared to 180 -270, you will see a different set of
comparisons, but I'd bet the net result would still be a greater pull/push to
the right.
Finally, go to a boatyard and look at a power boat on the "hard". Stand in
front of the propellor and pick one blade. Assuming RH, rotate the blade
counter clockwise and as you do, sight 90 deg to the blade pitch and visualize
the direction that the blade will "push" the water. I think you notice that the
blade will be pushing water up, on it's upward swing (into the air), thus
losing efficiency and the net effect will be a pull to the right (your left
standing in front of the prop) .......propwalk.
I don't doubt there are some possible flaws in this description, but it's how I
visualize the overall effect and cause of propwalk.
BTW, propwalk is just as important with twin screw. It's why a twin screw with
inboard turning props handles so much differently as one with outboard turning
props.

Shen

Subject: Which way does a boat turn?
From: "Scott Vernon"

I would guess yes. But I don't know. And I was picturing a side wheeler.

Sv

Ok, continue to picture a sidewheeler.
Now, in hopes of further clarifying what I'm trying to describe, the
paddlewheel is 6' in diameter and you totally submerge it to a point, say, 6"
beneath the water.
Your boat is floating in 200' of water with no land in sight (i.e., you've just
got water with the earth beneath it and water with air, 6" above it).
Looking at the "wheel" from the side and starting at a rotation angle of 090,
as the blade of the wheel rotates clockwise to 180 deg, it is pushing down and
to the left, against a solid non compressible column of water, 200ish feet deep
(it's working as efficiently as it can) and pulling the boat to your right.
Now look at the blades in the opposite quadrant (270 - 360). Starting at 270
and rotating towards 360, the blades are pushing up and to the right, against
........ a 3' 6" column of water with nothing but good old compressible air
above. What happens?
Basically the blades lift that column of water and throw it away into the air,
losing a high percentage of their efficiency to pull down and to the left,
compared to their opposite quadrant.
If you look at 000 - 090, compared to 180 -270, you will see a different set of
comparisons, but I'd bet the net result would still be a greater pull/push to
the right.
Finally, go to a boatyard and look at a power boat on the "hard". Stand in
front of the propellor and pick one blade. Assuming RH, rotate the blade
counter clockwise and as you do, sight 90 deg to the blade pitch and visualize
the direction that the blade will "push" the water. I think you notice that the
blade will be pushing water up, on it's upward swing (into the air), thus
losing efficiency and the net effect will be a pull to the right (your left
standing in front of the prop) .......propwalk.
I don't doubt there are some possible flaws in this description, but it's how I
visualize the overall effect and cause of propwalk.
BTW, propwalk is just as important with twin screw. It's why a twin screw with
inboard turning props handles so much differently as one with outboard turning
props.

Shen

Yes, I understood where you were going with this. I agree, with the paddle
wheel slightly out of the water, to a little (6'') below, but what about a
sailboat prop, 1' below the water with a boat sitting on top of it. And with
the smaller dia. blade on a S/V there isn't much depth difference between
top and bottom blade. Although even a miniscule difference could account for
prop walk given the RPMs of a small blade?

SV


"Shen44" wrote in message
...
Subject: Which way does a boat turn?
From: "Scott Vernon"

I would guess yes. But I don't know. And I was picturing a side
wheeler.

Sv

Ok, continue to picture a sidewheeler.
Now, in hopes of further clarifying what I'm trying to describe, the
paddlewheel is 6' in diameter and you totally submerge it to a point, say,
6"
beneath the water.
Your boat is floating in 200' of water with no land in sight (i.e., you've
just
got water with the earth beneath it and water with air, 6" above it).
Looking at the "wheel" from the side and starting at a rotation angle of
090,
as the blade of the wheel rotates clockwise to 180 deg, it is pushing down
and
to the left, against a solid non compressible column of water, 200ish feet
deep
(it's working as efficiently as it can) and pulling the boat to your
right.
Now look at the blades in the opposite quadrant (270 - 360). Starting at
270
and rotating towards 360, the blades are pushing up and to the right,
against
....... a 3' 6" column of water with nothing but good old compressible air
above. What happens?
Basically the blades lift that column of water and throw it away into the
air,
losing a high percentage of their efficiency to pull down and to the left,
compared to their opposite quadrant.
If you look at 000 - 090, compared to 180 -270, you will see a different
set of
comparisons, but I'd bet the net result would still be a greater pull/push
to
the right.
Finally, go to a boatyard and look at a power boat on the "hard". Stand in
front of the propellor and pick one blade. Assuming RH, rotate the blade
counter clockwise and as you do, sight 90 deg to the blade pitch and
visualize
the direction that the blade will "push" the water. I think you notice
that the
blade will be pushing water up, on it's upward swing (into the air), thus
losing efficiency and the net effect will be a pull to the right (your
left
standing in front of the prop) .......propwalk.
I don't doubt there are some possible flaws in this description, but it's
how I
visualize the overall effect and cause of propwalk.
BTW, propwalk is just as important with twin screw. It's why a twin screw
with
inboard turning props handles so much differently as one with outboard
turning
props.

Shen

Yes, I understood where you were going with this. I agree, with the paddle
wheel slightly out of the water, to a little (6'') below, but what about a
sailboat prop, 1' below the water with a boat sitting on top of it. And with
the smaller dia. blade on a S/V there isn't much depth difference between
top and bottom blade. Although even a miniscule difference could account for
prop walk given the RPMs of a small blade?

SV


"Shen44" wrote in message
...
Subject: Which way does a boat turn?
From: "Scott Vernon"

I would guess yes. But I don't know. And I was picturing a side
wheeler.

Sv

Ok, continue to picture a sidewheeler.
Now, in hopes of further clarifying what I'm trying to describe, the
paddlewheel is 6' in diameter and you totally submerge it to a point, say,
6"
beneath the water.
Your boat is floating in 200' of water with no land in sight (i.e., you've
just
got water with the earth beneath it and water with air, 6" above it).
Looking at the "wheel" from the side and starting at a rotation angle of
090,
as the blade of the wheel rotates clockwise to 180 deg, it is pushing down
and
to the left, against a solid non compressible column of water, 200ish feet
deep
(it's working as efficiently as it can) and pulling the boat to your
right.
Now look at the blades in the opposite quadrant (270 - 360). Starting at
270
and rotating towards 360, the blades are pushing up and to the right,
against
....... a 3' 6" column of water with nothing but good old compressible air
above. What happens?
Basically the blades lift that column of water and throw it away into the
air,
losing a high percentage of their efficiency to pull down and to the left,
compared to their opposite quadrant.
If you look at 000 - 090, compared to 180 -270, you will see a different
set of
comparisons, but I'd bet the net result would still be a greater pull/push
to
the right.
Finally, go to a boatyard and look at a power boat on the "hard". Stand in
front of the propellor and pick one blade. Assuming RH, rotate the blade
counter clockwise and as you do, sight 90 deg to the blade pitch and
visualize
the direction that the blade will "push" the water. I think you notice
that the
blade will be pushing water up, on it's upward swing (into the air), thus
losing efficiency and the net effect will be a pull to the right (your
left
standing in front of the prop) .......propwalk.
I don't doubt there are some possible flaws in this description, but it's
how I
visualize the overall effect and cause of propwalk.
BTW, propwalk is just as important with twin screw. It's why a twin screw
with
inboard turning props handles so much differently as one with outboard
turning
props.

Shen