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#1
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DSK wrote in message ...
To put this in perspective, this is roughly equivalent to stopping ten rounds from a .50 cal machine gun. Destructive, nyet? Your analogy is extremely misleading, since the area to which this force would be applied is hundreds of times smaller. This leads to hull-pressures that are hundreds of times larger That's not quite right, the force due to deceleration isn't linear. Comparing a braking distance of 2' to 4', the energy is less than half... about a third would be closer... Thats just plain wrong, the force (which is what Jordan was talking about) due to decelaration IS linear with breaking distance (given a certain initial velocity). The formula for force due to a constant deceleration (in terms of initial velocity and 'breaking distance') is: F = m*v^2/(2d) |
#2
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Bryan Glover wrote:
Your analogy is extremely misleading It may be misleading, but I dunno about "extremely misleading." ... since the area to which this force would be applied is hundreds of times smaller. This leads to hull-pressures that are hundreds of times larger A large part of that is also due to the energy transient. In any event, my point was to not underestimate the destructive power of the ocean, which certain types of cruisers are always doing. That's not quite right, the force due to deceleration isn't linear. Comparing a braking distance of 2' to 4', the energy is less than half... about a third would be closer... Thats just plain wrong Well, working with a not-infallible memory, it happens sometimes. I will go back to the old textbook and see what it says. DSK |
#3
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Dear DSK
The last post was answered by my son, who is a physicist and is protective of Don Jordan. We are continuing his research, with his help. The problem is, if one section is discredited, then a cloud of doubt settles on all his work. regards Bryan DSK wrote in message ... Bryan Glover wrote: Your analogy is extremely misleading It may be misleading, but I dunno about "extremely misleading." ... since the area to which this force would be applied is hundreds of times smaller. This leads to hull-pressures that are hundreds of times larger A large part of that is also due to the energy transient. In any event, my point was to not underestimate the destructive power of the ocean, which certain types of cruisers are always doing. That's not quite right, the force due to deceleration isn't linear. Comparing a braking distance of 2' to 4', the energy is less than half... about a third would be closer... Thats just plain wrong Well, working with a not-infallible memory, it happens sometimes. I will go back to the old textbook and see what it says. DSK |
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