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Shake and Break Part 13 - August 6 2015
On 9/14/2015 5:48 PM, Wayne.B wrote:
On Mon, 14 Sep 2015 05:37:09 -0600, Paul Cassel wrote: === It's basically simple vector algebra. Assume a speed through the water of 5 kts on a course of due east. Also assume a north flowing current of 5 kts. The resultant course made good would be north east at 7 kts. I see where we disagree. My logic was course to the destination and that's not enhanced by a current which is 90 degrees to the desired course. I guess until Skip checks in, we'll not know exactly what he was about. -paul --- This email has been checked for viruses by Avast antivirus software. https://www.avast.com/antivirus |
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