Home |
Search |
Today's Posts |
|
#1
![]()
posted to rec.boats.building
|
|||
|
|||
![]()
Ive been reading up a bit on pumps, but some of the math is beyond me. i do
know that its possilb eo hook must pumps up either in series, or in parallel. in parallel you quite logically get a doubling of flow in gallons per hour or whatever, while in series you combine the 'heads' whatever that means. i think it means head pressure? i know a lot of the losses in small pumps are from pumping 'up'. most small pumps are rated by how high they can pump water, and the rating for flow goes down as the height increases. installed in a boat, i would try to keep the whole thing on the level with the shortest hose runs possible. on a beach cat, i would have a thru hull on the side of the hull with maybe 6 inches of hose going to the pump, then another foot of hose going to the outlet. i think youd have to start with two pumps in each hull, both running off a common larger diameter inlest, and through a Y joiner to a common outlet. this would give you some options. you could run the pumps in parallel, or in series. then you would have to experiement with various reductions in the outlet to see what the smallest diameter nozzle you could use without losing flow would be. this is probably how you would use 'gearing'. if you used too large of a diameter nozzle, you really wouldnt get any force at all. Shaun Keith, I think you're missing a factor here. "Displaced" implies a DISTANCE per unit time. That's where horsepower (Or any other POWER unit) matters. 550 FOOT - (Pounds-Force) (Per SECOND) means that you could "Gear Down" (or use other force multiplication arrangements) and lift 550 pounds at 1 foot per second, or instead lift 55 pounds at 10 feet per second. Right? A large diameter 4-blade prop on a 60 foot boat with a small pitch and a 20 HP diesel with a reduction gear can put a (lot) of FORCE on that boat and move it at 5 or 6 knots. I've seen an old 20 Hp Mercury outboard push a 3-point Hydro at over 40 MPH. We don't know enough here (yet) to say what the efficiency of an inboard pump would be in moving a small boat against it's frictional resistance at a certain speed. We all know, from experience, that moving a small boat like the Hobie mentioned at the beginning of this thread takes VERY little force at very small speeds. A gentle push by hand moves it right away from the dock. Most of us have moved a 10 meter or larger boat a few feet by leaning a little on a dockline. What we're missing is some approximation of the efficiency of a well- designed pump in converting electrical power to mechanical power to move a boat. I think we'd have to do some research and talk to some mechanical engineers who understand pumps! I have a friend who recently built a small Hydroelectric plant in New York, who did his own calculations and is using a large (Thing formerly sold as a pump) as a turbine, with excellent efficiency. He's running 2 typical homes on it.. It's a BIG pump and he's at the bottom of a 85 foot waterfall... Someone somewhere knows a lot more about propelling a boat with an inboard pump than I do! |
#2
![]()
posted to rec.boats.building
|
|||
|
|||
![]()
Hi Shaun,
Ive been reading up a bit on pumps, but some of the math is beyond me. i do know that its possilb eo hook must pumps up either in series, or in parallel. in parallel you quite logically get a doubling of flow in gallons per hour or whatever, while in series you combine the 'heads' whatever that means. i think it means head pressure? Yep, head is pressure. Basically, you have one pound/sq.inch for each 27.68" of water column (height). i know a lot of the losses in small pumps are from pumping 'up'. That's kind of a misconception regarding 'head'. Pumping up, down, or horizontal, the flowrate is dependent on the total backpressure on the discharge line (but of course, 10' of vertical pipe does have more total backpressure than 10' of horizontal pipe - of the same size). most small pumps are rated by how high they can pump water, and the rating for flow goes down as the height increases. installed in a boat, i would try to keep the whole thing on the level with the shortest hose runs possible. on a beach cat, i would have a thru hull on the side of the hull with maybe 6 inches of hose going to the pump, then another foot of hose going to the outlet. Keeping the tubing runs as short as possible is certainly the right approach to reduce frictional losses. One problem with the inlet on the side of the hull (or any hull surface tangential to the water flow) is that you get Bernoulli effects as the boat speed increases, that tends to create a vacuum in the suction line (the same concept that makes paint sprayers - the kind that use air hoses - or end-of-hose garden sprayers work. The high speed stream across the diptube end creates suction to raise the paint/roundup into the discharge stream). i think youd have to start with two pumps in each hull, both running off a common larger diameter inlest, and through a Y joiner to a common outlet. this would give you some options. you could run the pumps in parallel, or in series. then you would have to experiement with various reductions in the outlet to see what the smallest diameter nozzle you could use without losing flow would be. this is probably how you would use 'gearing'. if you used too large of a diameter nozzle, you really wouldnt get any force at all. Don't confuse "velocity" with "Force". Just like with a garden hose where you have, say 80psig, you can pinch the end to get a higher velocity stream, but you get less flow (i.e. less mass). Since the force = mass x acceleration, the force however is the same (you only have 80psig to start with). The same is true for pumps, as you note above, when you create more backpressure (pinching the hose), the flowrate goes down. If you move 100gpm of water through the system, the force is the same whether the discharge is 1" or 3", only the velocity of the dischage changes. Remember, PSI is pounds per square inch (i.e. force per unit area), so the 1" discharge stream may be at 10 times the pressure of the 3" stream, but the 3" stream has 10 times the cross-sectional area of the 1" stream. Keith Hughes |
#3
![]()
posted to rec.boats.building
|
|||
|
|||
![]()
The following was posted by Cliff on the psubs.org group. Personal
submarine and ROV builders consider bilge pumps frequently. They are often used in ROV's because they are easy, but bilge pumps or jet propulsion is rarely used in Subs because they are inefficient. If you do go with a pump, be sure to place the discharge just above the water line to increase the efficiently. --Doug www.submarineboat.com Below is a derivation of thrust that can be developed from a axial flow pump in terms of volumetric flowrate. The thrust due to accelerating fluid through a pump can be written as F=M(V1-V0) Where M is the mass flow rate, V0 is the free stream velocity upstream of the pump and V1 is the velocity exiting the pump. But the mass flow rate M can be related to the volumetric flow rate Q as M=Density*Q Substituting, the thrust in terms of volumetric flow rate is F=Density*Q(V1-V0) But the volumetric flow rate Q is related to velocity in the pump duct ID as Q=V1*A=V1*Pi*D^2/4 Where D is the duct ID. Solving for V1, and substituting, the thrust can be written as F=Density*Q(Q/(Pi*D^2)-V0) For a thruster oriented approximately normal to the direction of flow, the inlet velocity can be assumed to be zero. The thrust then reduces to F = 4*Density*Q^2/(Pi*D^2) Or F= 0.001766*(q/d)^2 for freshwater where, F = Thrust, lbf q = pump volumetric flow rate in gpm d = pump outlet duct inside diameter in inches As an example, a pump with a capacity of 200 gpm flowing through a 2" duct would develop 17.7 lbf of thrust. |
#4
![]()
posted to rec.boats.building
|
|||
|
|||
![]()
Doug,
Thanks for the derivation - I was too lazy to look up the volumetric flow/velocity relationship. Looking at the RULE site, their largest bilge pump is 8000gph, or 133gpm. That calculates to 7.8 Lbf thrust, with a 31 amp draw at 12VDC. Comparing that to a Minn Kota Endura 30, with 30 Lbf thrust, at 30A/12VDC gives a good comparison of the relative efficiencies. Nice site, BTW. Looks like someone's got a lot of time on their hands...or a buttload more motivation than I have :-) Keith Hughes Doug J wrote: The following was posted by Cliff on the psubs.org group. Personal submarine and ROV builders consider bilge pumps frequently. They are often used in ROV's because they are easy, but bilge pumps or jet propulsion is rarely used in Subs because they are inefficient. If you do go with a pump, be sure to place the discharge just above the water line to increase the efficiently. --Doug www.submarineboat.com Below is a derivation of thrust that can be developed from a axial flow pump in terms of volumetric flowrate. The thrust due to accelerating fluid through a pump can be written as F=M(V1-V0) Where M is the mass flow rate, V0 is the free stream velocity upstream of the pump and V1 is the velocity exiting the pump. But the mass flow rate M can be related to the volumetric flow rate Q as M=Density*Q Substituting, the thrust in terms of volumetric flow rate is F=Density*Q(V1-V0) But the volumetric flow rate Q is related to velocity in the pump duct ID as Q=V1*A=V1*Pi*D^2/4 Where D is the duct ID. Solving for V1, and substituting, the thrust can be written as F=Density*Q(Q/(Pi*D^2)-V0) For a thruster oriented approximately normal to the direction of flow, the inlet velocity can be assumed to be zero. The thrust then reduces to F = 4*Density*Q^2/(Pi*D^2) Or F= 0.001766*(q/d)^2 for freshwater where, F = Thrust, lbf q = pump volumetric flow rate in gpm d = pump outlet duct inside diameter in inches As an example, a pump with a capacity of 200 gpm flowing through a 2" duct would develop 17.7 lbf of thrust. |
#5
![]()
posted to rec.boats.building
|
|||
|
|||
![]()
On Feb 16, 1:24 pm, Keith Hughes wrote:
Doug, Thanks for the derivation - I was too lazy to look up the volumetric flow/velocity relationship. Looking at the RULE site, their largest bilge pump is 8000gph, or 133gpm. That calculates to 7.8 Lbf thrust, with a 31 amp draw at 12VDC. Comparing that to a Minn Kota Endura 30, with 30 Lbf thrust, at 30A/12VDC gives a good comparison of the relative efficiencies. Nice site, BTW. Looks like someone's got a lot of time on their hands...or a buttload more motivation than I have :-) Keith Hughes Doug J wrote: The following was posted by Cliff on the psubs.org group. Personal submarine and ROV builders consider bilge pumps frequently. They are often used in ROV's because they are easy, but bilge pumps or jet propulsion is rarely used in Subs because they are inefficient. If you do go with a pump, be sure to place the discharge just above the water line to increase the efficiently. --Doug www.submarineboat.com Below is a derivation of thrust that can be developed from a axial flow pump in terms of volumetric flowrate. The thrust due to accelerating fluid through a pump can be written as F=M(V1-V0) Where M is the mass flow rate, V0 is the free stream velocity upstream of the pump and V1 is the velocity exiting the pump. But the mass flow rate M can be related to the volumetric flow rate Q as M=Density*Q Substituting, the thrust in terms of volumetric flow rate is F=Density*Q(V1-V0) But the volumetric flow rate Q is related to velocity in the pump duct ID as Q=V1*A=V1*Pi*D^2/4 Where D is the duct ID. Solving for V1, and substituting, the thrust can be written as F=Density*Q(Q/(Pi*D^2)-V0) For a thruster oriented approximately normal to the direction of flow, the inlet velocity can be assumed to be zero. The thrust then reduces to F = 4*Density*Q^2/(Pi*D^2) Or F= 0.001766*(q/d)^2 for freshwater where, F = Thrust, lbf q = pump volumetric flow rate in gpm d = pump outlet duct inside diameter in inches As an example, a pump with a capacity of 200 gpm flowing through a 2" duct would develop 17.7 lbf of thrust. I actually saw this being done once: Get a large cordless electric drill, mount a long shaft in it and put a trolling prop on the shaft. I saw a guy pushing an 18' canoe once this way and I nearly fell overboard watching it. For that matter, you could attach leads to power it from your 12V battery. |
#6
![]()
posted to rec.boats.building
|
|||
|
|||
![]()
does having the outlet above the water line really increase the efficiency?
All the jet boats I''ve seen have the outlet below the waterline, but i could be wrong... is this what all the RC boat builders do? Ill have to have a beer or two before i try to get my head around the numbers, but thanks for the information! Shaun "Doug J" wrote in message ups.com... The following was posted by Cliff on the psubs.org group. Personal submarine and ROV builders consider bilge pumps frequently. They are often used in ROV's because they are easy, but bilge pumps or jet propulsion is rarely used in Subs because they are inefficient. If you do go with a pump, be sure to place the discharge just above the water line to increase the efficiently. --Doug www.submarineboat.com Below is a derivation of thrust that can be developed from a axial flow pump in terms of volumetric flowrate. The thrust due to accelerating fluid through a pump can be written as F=M(V1-V0) Where M is the mass flow rate, V0 is the free stream velocity upstream of the pump and V1 is the velocity exiting the pump. But the mass flow rate M can be related to the volumetric flow rate Q as M=Density*Q Substituting, the thrust in terms of volumetric flow rate is F=Density*Q(V1-V0) But the volumetric flow rate Q is related to velocity in the pump duct ID as Q=V1*A=V1*Pi*D^2/4 Where D is the duct ID. Solving for V1, and substituting, the thrust can be written as F=Density*Q(Q/(Pi*D^2)-V0) For a thruster oriented approximately normal to the direction of flow, the inlet velocity can be assumed to be zero. The thrust then reduces to F = 4*Density*Q^2/(Pi*D^2) Or F= 0.001766*(q/d)^2 for freshwater where, F = Thrust, lbf q = pump volumetric flow rate in gpm d = pump outlet duct inside diameter in inches As an example, a pump with a capacity of 200 gpm flowing through a 2" duct would develop 17.7 lbf of thrust. |
#7
![]()
posted to rec.boats.building
|
|||
|
|||
![]()
On Feb 16, 2:43 pm, "Shaun Van Poecke"
wrote: does having the outlet above the water line really increase the efficiency? All the jet boats I''ve seen have the outlet below the waterline, but i could be wrong... is this what all the RC boat builders do? I was afraid someone would ask that. ![]() on what I have been told by jet boat and jet ski people. If anyone knows better about jet pumps, please correct me. The efficiency of the jet pump is based on the mass of water it discharges. Any back pressure and turbulence at the outlet only reduces the velocity of the flow and therefor the rate of the flow. The discharge ports are below the water line but only when the craft is not yet up to speed. I think there is a benefit to having a higher outlet pressure during start up or the "hole shot". Jet pumps also depend on the design of their intake ports, because at top speed the forward motion of the craft and the shape of the intake actually assist in directing the water flow into the pump, much like an air intake scoop on a dragster. You might milk another 2 or 3 oz of thrust from that bilge pump if you put a scoop on it. ![]() that would really jack with the drag on a sail boat hull. I'd go with an old used cheep trolling motor with a busted speed controller. Clean it, replace the brushes and mount it on one of the transoms with a hinge that lets it flip down into the water and then steer with the rudders. Add a simple on/off switch and avoid the variable speed controller or any other electronics that will just present other points of potential failure. Best Regards Doug www.submarineboat.com |
#8
![]()
posted to rec.boats.building
|
|||
|
|||
![]()
"Doug J" wrote in message
ups.com... On Feb 16, 2:43 pm, "Shaun Van Poecke" I'd go with an old used cheep trolling motor with a busted speed controller. Clean it, replace the brushes and mount it on one of the transoms with a hinge that lets it flip down into the water and then steer with the rudders. Add a simple on/off switch and avoid the variable speed controller or any other electronics that will just present other points of potential failure. Best Regards Doug www.submarineboat.com im with you there doug, that would suit my budget and my temperament perfectly. even used trolling motors on ebay in australia attract quite a premium... Ive seen second hand 40lb motors going for up to AU$250! since ill probably chop it anyway, buying new is not a big concern of mine, and ill only want full speed, so drect wiring seems the way to go. what is the general thought on the life of a trolling motor? are replacement bushes readily available? Shaun |
#9
![]()
posted to rec.boats.building
|
|||
|
|||
![]()
Doug J wrote:
On Feb 16, 2:43 pm, "Shaun Van Poecke" wrote: does having the outlet above the water line really increase the efficiency? All the jet boats I''ve seen have the outlet below the waterline, but i could be wrong... is this what all the RC boat builders do? I was afraid someone would ask that. ![]() on what I have been told by jet boat and jet ski people. If anyone knows better about jet pumps, please correct me. The efficiency of the jet pump is based on the mass of water it discharges. Any back pressure and turbulence at the outlet only reduces the velocity of the flow and therefor the rate of the flow. Yep, the discharge stream has to displace water already behind the boat, and that requires work (seen as higher backpressure at the discharge nozzle, reducing the mass flow rate). Where you could gain efficiency would be in having a directionally adjustable discharge nozzle (primarily with a planing hull) so you could optimize the discharge vector, for maximum thrust in the direction of boat travel, for different bow angles. For e.g., as the bow rises, the discharge angle, for a fixed nozzle, rotates downward. The thrust is now a vector addition of the upward + forward thrusts, with the upward thrust component being wasted energy. Seems that angling the stream back to horizontal (and letting the hull do the lifting) would increase the forward thrust. The discharge ports are below the water line but only when the craft is not yet up to speed. I think there is a benefit to having a higher outlet pressure during start up or the "hole shot". Jet pumps also depend on the design of their intake ports, because at top speed the forward motion of the craft and the shape of the intake actually assist in directing the water flow into the pump, much like an air intake scoop on a dragster. You might milk another 2 or 3 oz of thrust from that bilge pump if you put a scoop on it. ![]() that would really jack with the drag on a sail boat hull. Details, details... :-) I'd go with an old used cheep trolling motor with a busted speed controller. Clean it, replace the brushes and mount it on one of the transoms with a hinge that lets it flip down into the water and then steer with the rudders. Add a simple on/off switch and avoid the variable speed controller or any other electronics that will just present other points of potential failure. Sounds like the best plan to me. Keith Hughes |
#10
![]()
posted to rec.boats.building
|
|||
|
|||
![]() "Keith Hughes" wrote in message ... Hi Shaun, Ive been reading up a bit on pumps, but some of the math is beyond me. i do know that its possilb eo hook must pumps up either in series, or in parallel. in parallel you quite logically get a doubling of flow in gallons per hour or whatever, while in series you combine the 'heads' whatever that means. i think it means head pressure? Yep, head is pressure. Basically, you have one pound/sq.inch for each 27.68" of water column (height). i know a lot of the losses in small pumps are from pumping 'up'. That's kind of a misconception regarding 'head'. Pumping up, down, or horizontal, the flowrate is dependent on the total backpressure on the discharge line (but of course, 10' of vertical pipe does have more total backpressure than 10' of horizontal pipe - of the same size). most small pumps are rated by how high they can pump water, and the rating for flow goes down as the height increases. installed in a boat, i would try to keep the whole thing on the level with the shortest hose runs possible. on a beach cat, i would have a thru hull on the side of the hull with maybe 6 inches of hose going to the pump, then another foot of hose going to the outlet. Keeping the tubing runs as short as possible is certainly the right approach to reduce frictional losses. One problem with the inlet on the side of the hull (or any hull surface tangential to the water flow) is that you get Bernoulli effects as the boat speed increases, that tends to create a vacuum in the suction line (the same concept that makes paint sprayers - the kind that use air hoses - or end-of-hose garden sprayers work. The high speed stream across the diptube end creates suction to raise the paint/roundup into the discharge stream). i think youd have to start with two pumps in each hull, both running off a common larger diameter inlest, and through a Y joiner to a common outlet. this would give you some options. you could run the pumps in parallel, or in series. then you would have to experiement with various reductions in the outlet to see what the smallest diameter nozzle you could use without losing flow would be. this is probably how you would use 'gearing'. if you used too large of a diameter nozzle, you really wouldnt get any force at all. Don't confuse "velocity" with "Force". Just like with a garden hose where you have, say 80psig, you can pinch the end to get a higher velocity stream, but you get less flow (i.e. less mass). Since the force = mass x acceleration, the force however is the same (you only have 80psig to start with). The same is true for pumps, as you note above, when you create more backpressure (pinching the hose), the flowrate goes down. If you move 100gpm of water through the system, the force is the same whether the discharge is 1" or 3", only the velocity of the dischage changes. Remember, PSI is pounds per square inch (i.e. force per unit area), so the 1" discharge stream may be at 10 times the pressure of the 3" stream, but the 3" stream has 10 times the cross-sectional area of the 1" stream. Keith Hughes in the very simples sense though, if i had the same volume of water flowing through both a very large and a very small outlet, the speed would be much greater for the smaller outlet right? this seems like a way to achieve some sort of gearing to me, despite whatever losses are incurred from backpressure. runing pumps in series would allow you to have a smaller outlet and still maintain the same volume of flow right? While there would obviously be a sweet spot for any given pump, having more velocity at the outlet seems like it would probably result in more real world 'thrust'. I was reading a page by an RC boat builder who use a bilge pump for drive on his boat. he used a fishing scale to measure the trust produced by the boat, and found that making the nozzle on the outlet increased thust, but only to a certain point. Shaun |
Reply |
|
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Help with bilge pump installation | General | |||
Bilge Pump Upgrade | Boat Building | |||
Propane Sniffer Meltdown | Cruising | |||
Bilge Pump Switch | Cruising | |||
Bilge Pump Switch | Electronics |