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"Scout" wrote in message
... "Jeff Morris" wrote [snip] So take your pick, either explanation works, and I'm sure there are others. However, I hope you can appreciate that explanations like "gravity creates the inner bulge, centrifugal force creates the outer bulge" makes physicists wince! Yes, I can, as I've watched my physics teaching partner wince quite a bit this week as we discussed this thread. He was quick to cover our whiteboard with formulas and drawings. It's an interesting thread though, and notwithstanding my oversimplified analogies, I've learned a lot from it. By the way, I saw that same wince from a black history professor when I suggested that the Civil War was fought to free the slaves, and then again when I suggested to an ancient lit professor that The Odyssey has all the earmarks of an Arnold Schwarzenegger movie. Probably explains why I like a good fart joke. Sort of like the wince I got from an African-American/Cherokee friend when I asked him how he was going to celebrate Columbus Day? jeff ps So how does your partner rate my explanations? |
"Jeff Morris" wrote
[snip] Sort of like the wince I got from an African-American/Cherokee friend when I asked him how he was going to celebrate Columbus Day? Ouch! ps So how does your partner rate my explanations? The great mediator saw truth in both models. He was a bit more forgiving of my "impellor in a great centrifugal pump" analogy, but slapped my wrist for saying this about centrifugal force: if it feels real, mustn't it be real? By the time he was done, my head was spinning and yet somehow my brain seemed to be bulging (quite appropriately) out of both sides of my head. In the end he called me an English teacher, which is his way of slandering me, and told me my paltry general science achievements were no match for his superior physics and math skills. I told him he could forget about me taking him sailing again and he took it all back. He's never done the newsgroups though, and was quite impressed with the ease with which like minded folks could debate a worthy topic. Scout |
Well just to confuse things a bit mo
Even if we only focus on the tide generating potential, there is a cupple of things that we haven't discussed yet, and one of them has to do with rotation: "The Coriolis freqency". The other thing one could include is the "parallax". I mention this just to make clear that the two models discussed above both are incomplete. Peter S/Y Anicula "Jeff Morris" skrev i en meddelelse ... "Scout" wrote in message ... Jeff, Remember that I first posted that very same sentiment, and even provided a graphic. I still believe that to be true, but have modified my internal model, giving allowance for the centrifugal force. I'm not a physicist, but the way I'm seeing it, there is a middle ground in this discussion. I'm curious to know if you're discounting centrifugal force as a contributor to the far bulge. Scout I've always said that Centrifugal Force can be used as part of the explanation, as long as you end up with the same answer. There are several different ways of looking at this, all valid. (I hope I can get through this without mangling the terms too badly ...) The problem with Centrifugal Force is that it is a "fictional force." It is only needed if you work in a non-inertial, or accelerating reference frame. If you are in a car going around a curve, your reference frame is accelerating towards the center of the curve, and thus you feel a Centrifugal Force in the opposite direction. To an outside observer, the CF doesn't exist, the only force is the car pulling the passenger around the turn. The outside observer can analyze the situation completely without invoking CF. (The passenger feels CF push him outward, the observer sees the car pull the passenger inward.) In the Earth-Moon system there is gravity pulling both the Earth and Moon around curves. Because the gravity acts on all objects, we don't notice ourselves being pulled around. The magnitude of the Centrifugal force is to small to notice, but in that reference frame it exists. To the outside observer, we're just in freefall, being pulled inward by gravity. The problem with CF arises when you look carefully at the math. One pitfall Nav fell into was trying to calculate CF as a function that varies with the distance to the barycenter. However, all points on the Earth do not rotate around the barycenter, only the center does. Other points describe the same circle around nearby points, so that all points on Earth feel the same Centrifugal Force. (This is a tough concept to explain in words; its easier to do it graphically. Consider a plate wobbling around a point but with no rotation - each point on the plate describes the same circle.) BTW, Nav provided two commonly used formulas, one for gravity and the other for CF. Although they look quite different, you should appreciate that they are the same, since the angular velocity is determined by the gravitational force. The CF will be the same (with the opposite sign) as the gravitational pull at the Earth's center. Since the CF is a constant force, it can't describe the two bulges in opposite directions. It is gravity itself that varies with distance. The differential force can be derived either by subtracting the average gravitational force which causes the freefall at the center of the Earth, or it can be derived by adding the centrifugal force. Since the two are the same, except for the sign, the math is identical. So take your pick, either explanation works, and I'm sure there are others. However, I hope you can appreciate that explanations like "gravity creates the inner bulge, centrifugal force creates the outer bulge" makes physicists wince! |
mission accomplished! lol
Scout "Peter S/Y Anicula" wrote Well just to confuse things a bit mo Even if we only focus on the tide generating potential, there is a cupple of things that we haven't discussed yet, and one of them has to do with rotation: "The Coriolis freqency". The other thing one could include is the "parallax". I mention this just to make clear that the two models discussed above both are incomplete. |
Scout,
I was determined not to re-enter this discussion, except to needle Donal about the 1/4 point. Your post about your physic teacher gave me enough enjoyment to venture another post. Your experience brought back memoirs of mine own days in High School with my own Physic Teacher about Tides and a Commercial Clammer who help me learn sailing. By the time I got finished, I had more faith in the Clammer. He lived in a shed on a float in the middle of the harbor. He was fond of the booze an when he know enough about any subject to satisfy himself, then he was satisfied. His explanation of the Tide, given to me willingly. was; and I quote. The Moon causes the Tides. It cause high tide because of its pull on earth, which screws up the pull between the earth and the Sun. Since the Tides are made up of water, the higher water, under the Moon creates less water on the other side of the Earth or low Tide. Since the Tide are water and the pull is less the farther away from the Moon they are not as high on the side of the earth facing the moon but higher than the water on the side of the Earth facing away away from the Moon. People call this difference 1/2 tide. The height of High Tide and Low Tide along with 1/2 Tides are affected by the Phase of the Moon. The difference of the location and of the time of tides are caused by the differences of the rotation of the Earth and the time of revolution and direction of the Moon This is explanation has served me well for over 60 years. Ole Thom |
Scout,
I forgot to mention my old friend. Frank, also told me he had Tide Tables and Almanics for the heigth and times of the tides and the position on the Moon. Ole Thom |
You're absolutely correct. There are numerous effects we're not considering. We've
only attempted to understand the primary cause of two tides a day. Even then, the math is a bit more complex than the simple formulas we've used. The parallax effects are certainly significant - they are caused non-circular orbits. And then there's Lunar declination to fold in. Of course, spring and neap must be considered - does everyone know when Syzygy is? And these are just the global effect - there's a whole litany of local effects to consider. Or you can keep a copy of Eldridge or Reed's handy. "Peter S/Y Anicula" wrote in message ... Well just to confuse things a bit mo Even if we only focus on the tide generating potential, there is a cupple of things that we haven't discussed yet, and one of them has to do with rotation: "The Coriolis freqency". The other thing one could include is the "parallax". I mention this just to make clear that the two models discussed above both are incomplete. Peter S/Y Anicula "Jeff Morris" skrev i en meddelelse ... "Scout" wrote in message ... Jeff, Remember that I first posted that very same sentiment, and even provided a graphic. I still believe that to be true, but have modified my internal model, giving allowance for the centrifugal force. I'm not a physicist, but the way I'm seeing it, there is a middle ground in this discussion. I'm curious to know if you're discounting centrifugal force as a contributor to the far bulge. Scout I've always said that Centrifugal Force can be used as part of the explanation, as long as you end up with the same answer. There are several different ways of looking at this, all valid. (I hope I can get through this without mangling the terms too badly ...) The problem with Centrifugal Force is that it is a "fictional force." It is only needed if you work in a non-inertial, or accelerating reference frame. If you are in a car going around a curve, your reference frame is accelerating towards the center of the curve, and thus you feel a Centrifugal Force in the opposite direction. To an outside observer, the CF doesn't exist, the only force is the car pulling the passenger around the turn. The outside observer can analyze the situation completely without invoking CF. (The passenger feels CF push him outward, the observer sees the car pull the passenger inward.) In the Earth-Moon system there is gravity pulling both the Earth and Moon around curves. Because the gravity acts on all objects, we don't notice ourselves being pulled around. The magnitude of the Centrifugal force is to small to notice, but in that reference frame it exists. To the outside observer, we're just in freefall, being pulled inward by gravity. The problem with CF arises when you look carefully at the math. One pitfall Nav fell into was trying to calculate CF as a function that varies with the distance to the barycenter. However, all points on the Earth do not rotate around the barycenter, only the center does. Other points describe the same circle around nearby points, so that all points on Earth feel the same Centrifugal Force. (This is a tough concept to explain in words; its easier to do it graphically. Consider a plate wobbling around a point but with no rotation - each point on the plate describes the same circle.) BTW, Nav provided two commonly used formulas, one for gravity and the other for CF. Although they look quite different, you should appreciate that they are the same, since the angular velocity is determined by the gravitational force. The CF will be the same (with the opposite sign) as the gravitational pull at the Earth's center. Since the CF is a constant force, it can't describe the two bulges in opposite directions. It is gravity itself that varies with distance. The differential force can be derived either by subtracting the average gravitational force which causes the freefall at the center of the Earth, or it can be derived by adding the centrifugal force. Since the two are the same, except for the sign, the math is identical. So take your pick, either explanation works, and I'm sure there are others. However, I hope you can appreciate that explanations like "gravity creates the inner bulge, centrifugal force creates the outer bulge" makes physicists wince! |
Thanks Thom,
thank God for those ol' salty guys ~ they always manage to keep it real! Scout "Thom Stewart" wrote [snip] Your post about your physic teacher gave me enough enjoyment to venture another post. Your experience brought back memoirs of mine own days in High School with my own Physic Teacher about Tides and a Commercial Clammer who help me learn sailing. By the time I got finished, I had more faith in the Clammer. He lived in a shed on a float in the middle of the harbor. He was fond of the booze an when he know enough about any subject to satisfy himself, then he was satisfied. |
"Donal" wrote in message
... It doesn't "know" anything. Because the Earth and Moon are an "orbiting pair," as you say, they are falling towards each other. Because the gravitational field varies, the near side falls faster than the middle; and the far side falls slower. Very neat! However, your view seems to be a little bit simplistic. It is simple. That's because there really isn't that much going on (at this level). Just the pull of gravity, which varies with distance. Everything else is red herring. Why should a solid fall more slowly than a fluid in a gravitational field? Why is there any difference? They both feel the same force. And, the land surfaces are distorted by the tides, roughly a meter, IIRC. To be honest, I could never figure out if the water is distorted more for some reason (its lighter?), or is in simply free to move, and thus get involved in the local shoreline effects. (That is, is the tide in the middle of the ocean the same as in the middle of a continent?) If your theory was correct, then there wouldn't be any tide at all. No, the force distorts both the land and the water. These distortions are the two bulges. In fact, because there is a difference in force, there must be some distortion - how much is a detail for the engineers! You seem to be ignoring momentum. Nope. If you use the "free fall" approach, momentum isn't really a factor in computing the force, though I suppose it gets involved when you calculate the actual motion. You sort of consider momentum with the centrifugal force approach, but you don't calculate it because the CF gets cancelled out. Consider an astronaut space walking outside a space station. They both float together, feeling no force, although they are both in freefall in their orbit. If the astronaut moves to a lower orbit, he will feel a stronger pull and be drawn in, unless he speeds up to compensate. If the astronaut moves to a higher orbit, the force is reduced. As I said, the force can be calculated without consideration of momentum. A purist might say momentum is considered because the mass and velocity of the every object in the system is folded together. And, the pure way force is defined is by how it changes momentum. But I don't think this is what you're talking about. |
"Jeff Morris" wrote in message ... "Donal" wrote in message ... It doesn't "know" anything. Because the Earth and Moon are an "orbiting pair," as you say, they are falling towards each other. Because the gravitational field varies, the near side falls faster than the middle; and the far side falls slower. Very neat! However, your view seems to be a little bit simplistic. It is simple. That's because there really isn't that much going on (at this level). Just the pull of gravity, which varies with distance. Everything else is red herring. Why should a solid fall more slowly than a fluid in a gravitational field? Why is there any difference? They both feel the same force. And, the land surfaces are distorted by the tides, roughly a meter, IIRC. To be honest, I could never figure out if the water is distorted more for some reason (its lighter?), or is in simply free to move, and thus get involved in the local shoreline effects. (That is, is the tide in the middle of the ocean the same as in the middle of a continent?) If your theory was correct, then there wouldn't be any tide at all. No, the force distorts both the land and the water. These distortions are the two bulges. In fact, because there is a difference in force, there must be some distortion - how much is a detail for the engineers! You seem to be ignoring momentum. Nope. If you use the "free fall" approach, momentum isn't really a factor in computing the force, though I suppose it gets involved when you calculate the actual motion. You sort of consider momentum with the centrifugal force approach, but you don't calculate it because the CF gets cancelled out. Consider an astronaut space walking outside a space station. They both float together, feeling no force, although they are both in freefall in their orbit. If the astronaut moves to a lower orbit, he will feel a stronger pull and be drawn in, unless he speeds up to compensate. If the astronaut moves to a higher orbit, the force is reduced. As I said, the force can be calculated without consideration of momentum. I don't understant this. In orbit, momentum is the force that balances the effect of gravity. Without momentum, your astronaut wouldn't "float" - he would crash straight into the Earth. In fact, I think that your use of the word "float" reveals that you don't understand the situation at all. Your astronaut wouldn't feel any difference between a free fall orbit and a headlong race into deepest space, - would he? Furthermore, if he slowed down, then he would still feel like he was floating -- apart from the temperature, and perhaps the braking effect of the atmosphere. This makes me think that the orbiting "free-fall" astronaut doesn't feel that he is floating at all. He must feel a constant force as his direction of travel changes. I wonder if this has been documented on the Internet? What does your physics friend say about this? A purist might say momentum is considered because the mass and velocity of the every object in the system is folded together. And, the pure way force is defined is by how it changes momentum. But I don't think this is what you're talking about. I'm not sure. I'm certainly *not* a purist. Regards Donal -- |
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