Yes I know you "think" you answered the question, just like you "think" you're a
member of Mensa, and you "think" you graduated high school.

But saying that the answer is something that has a collection of components is
NOT showing that you actually know how to compute such a collection. The fact
that you keep insisting you solved it proves you don't really know how to do it.
And being able to guess within 15% isn't bad, but doesn't show you know how to
navigate.



"JAXAshby" wrote in message
...
I know that *you* don't understand, jeffies, but the problem really was
answered comprehensively within a few minutes of the question being posted.

jeffie, rational discussion with you is near to impossible, for you are not
only much lacking in mental candlepower you are also so lacking in such you
are
not even capable of understanding just how lacking.

don't buy an EPIRB, jeffie. Let Darwin help you sail, if you ever do decide
to
sail in lieu motoring.

I think I gave the answer to the "math problem."

As to whether this current can exist in the Gulf Stream or an Eddy, I'm
skeptical. However, I really don't know, and there are certainly many cases
of
current running substantially higher than what is "advertised."

Since Jax claims to have only been making 3 knots, and doesn't specify the
final
SOG, its actually possible that they were not in an eddy, but in the Gulf
Stream
itself. Given the obviously poor navigational skill onboard, I wouldn't
doubt
it!


"SkitchNYC" wrote in message
...
You've only answered one part of the question.

Since no one seems willing to do this probably, here are the answers:
Starting with heading of 190 and speed through water 5, to have a COG of
90
and
SOG of 5,
current must be 50 degrees, speed of 7.66

Starting with heading of 190 and speed through water 5, to have a COG of
90
and
SOG of 2.5,
current must be 34.37 degrees, speed of 5.96



For any oblique triangle with angles A, B, and C, and opposite sides a,b,
and, c
then:
the law of sines says:

a/ sinA = b / sinB = c / sinC = diameter of circumscribed circle

and the law of cosines says:
c^2 = a^2 + b^2 - 2*a*b* cos C



"SkitchNYC" wrote in message
...
Say you are sailing a course of 190 and making 5 kn. An adverse current
suddenly gets you and you are now making a COG of 90. Assume the new
COG
is
at
the same speed (5kn) and again at 2.5 kn. What direction and speed must
the
current be to produce either of these results? Can such a current exist
in
a
Gulf Stream eddie?

"Jeff Morris" wrote in message
...
Since no one seems willing to do this probably, here are the answers:

Excuse me???

Define "properly"! I worked it out using a Breton plotter. That *is* the
proper way to do it.




Regards


Donal
--

donny, jeffies, you guys are arguing a case-specific, tightly defined issue.
Stand back a couple feet and deal with the concept. Gotta remember that the
original assumptions were nothing more than assumptions, therefore while
precision can be obtained accuracy can not.

Since no one seems willing to do this probably, here are the answers:

Excuse me???

Define "properly"! I worked it out using a Breton plotter. That *is* the
proper way to do it.




Regards


Donal
--

This was not a vague question, it was a well posed mathematical problem. You
ignored the complicating issue and solved a simpler case. You were 10% off in
the speed and 5 degrees off in the current direction. You the ignored the
second part because it required some actual math. Donal solved both problems
using a proper navigational method, though I think his accuracy could have been
better.

I simply provided the proper mathematical solution. I sorry if a bit of trig is
beyond you.

BTW, given the numbers you provided, why do you think this was "an eddy" and not
the Gulf Stream itself?





"JAXAshby" wrote in message
...
donny, jeffies, you guys are arguing a case-specific, tightly defined issue.
Stand back a couple feet and deal with the concept. Gotta remember that the
original assumptions were nothing more than assumptions, therefore while
precision can be obtained accuracy can not.

Since no one seems willing to do this probably, here are the answers:

Excuse me???

Define "properly"! I worked it out using a Breton plotter. That *is* the
proper way to do it.




Regards


Donal
--

And Donal did it blindfolded.

SV

"Jeff Morris" wrote in message
...
This was not a vague question, it was a well posed mathematical problem.
You
ignored the complicating issue and solved a simpler case. You were 10%
off in
the speed and 5 degrees off in the current direction. You the ignored
the
second part because it required some actual math. Donal solved both
problems
using a proper navigational method, though I think his accuracy could have
been
better.

I simply provided the proper mathematical solution. I sorry if a bit of
trig is
beyond you.

BTW, given the numbers you provided, why do you think this was "an eddy"
and not
the Gulf Stream itself?





"JAXAshby" wrote in message
...
donny, jeffies, you guys are arguing a case-specific, tightly defined
issue.
Stand back a couple feet and deal with the concept. Gotta remember that
the
original assumptions were nothing more than assumptions, therefore while
precision can be obtained accuracy can not.

Since no one seems willing to do this probably, here are the answers:

Excuse me???

Define "properly"! I worked it out using a Breton plotter. That
*is* the
proper way to do it.




Regards


Donal
--

it was a well posed mathematical problem.

jeffie, the assumptions were just assumptions, therefore the answer can be no
more accurate than the product of the least accurate assumptions.

You
ignored the complicating issue and solved a simpler case.

There was no complicating issue. It was nothing but assumptions to start with.
I dealt with the simpler case of a 90* shift in course rather than a 100*
shift because while the concept was unchanged, the math became more simple and
thus did not stand out from its rightful place in the background.

You were 10% off in
the speed and 5 degrees off in the current direction.

there was no speed and no direction. It was just a question as to "how could
it happen?". you solved precisely to arrive at a vagueness.

You the ignored the
second part because it required some actual math.

I left the second part because it came to the same conclusion.


Donal solved both problems
using a proper navigational method,

there is no "proper navigational method", for the question was "how could it
happen?"

though I think his accuracy could have been
better.

you mean his *precision* could have been better. His accuracy could not
improve because the problem started with inaccurate data.

I simply provided the proper mathematical solution.

there is not "proper mathematical solution" to assumptions.

I sorry if a bit of trig is
beyond you.

beyond me? *you* were the one who didn't notice the trig was still there, but
presented in a fashion to keep it in the background where it belonged.

BTW, given the numbers you provided, why do you think this was "an eddy" and
not
the Gulf Stream itself?

because, the shift to an eastward course happened quickly enough so that the
"averaging" algarithm on two gps's -- each from a different manufacturer --
caught the course change at the nearly the very same instant. I looked up to
say my gps went idiotic maybe a half second before the other guy looked to say
the same thing of his gps. the Gulf Stream would have to very dramatically
change course in a very short period of time. Eddies, on the other hand, do
form quickly and are much smaller so it is easier to sail in or out of one in a
short distance. Keep in mind that we did not change our heading, nor did we
notice a change in cloud position relative to the mast/sails.

Your accuracy was only slightly better than jaxie's guess. I would think you'd
aspire to better than that. Actually, that would probably not be good enough to
pass the USCG chartwork test.



"Donal" wrote in message
...

"Jeff Morris" wrote in message
...
Since no one seems willing to do this probably, here are the answers:

Excuse me???

Define "properly"! I worked it out using a Breton plotter. That *is* the
proper way to do it.




Regards


Donal
--

Your accuracy was only slightly better than jaxie's guess.

what guess? 5^2 + 5^2 = 50 and the square root of 50 is just a little over 7.
you can do that one in your head in less than a second or two.

"Jeff Morris" wrote in message
...
Your accuracy was only slightly better than jaxie's guess. I would think
you'd
aspire to better than that. Actually, that would probably not be good
enough to
pass the USCG chartwork test.

I'd make sure that I was sober if I were taking a test.


Regards


Donal
--

You are finaly showing some intelligence Jax. keep it up.

Regards

Donal

"JAXAshby" wrote in message ...
kates, I didn't even see "joe's" post, probably because I blocked the id
address of the clown who has been posting as everyone else. Cut the number of
posts I do see by half.