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JAXAshby
 
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Default push vs pull vis a vis rudders

schlackoff, you are using a constrained airflow? know what that means? know
how it is different from unconstrained.

get some sleep, schlackoff, and you will feel better by tomorrow afternoonn.

wtf are you talking about? it's awfully early in the day to be so

incoherant
from alcohol.


Bzzzt!!! Wrong answer jox. Try again. It's clear you don't understand
the sprinkler problem. While you're cogitating on why you're wrong in
applying feynman's sprinkler problem to this arena, here's another,
simpler question for you:

Say you have a wind tunnel with a rudder mounted at the test point.
First case is a blower at one end forcing air though the tunnel and past
the rudder at 1mph. You turn the rudder at a 45 degree angle to the
airflow. Is there a lateral force generated by the rudder?

Second case is a blower at the other end of the tunnel but now it's
sucking air through the tunnel past the rudder at 1mph. You turn the
rudder at a 45 degree angle to the airflow. Is there a lateral force
generated by the rudder?


Intuitively, most people sense that water "pulled" over a rudder will

cause
a
rudder to change direction of a boat in much the same way as water

"pushed"
over a rudder does. However, intuition misses some things along the way.
[...]
end) to port. However, the water drawn over the rudder's port side hits
that
side and is deflected towards port. Then the rudder would push the boat
(after end) to starboard. And equal and opposite reaction. Net, net, the
boat
does not turn. The pressure on each side of the rudder is equal. Nada.


Jox, since you're such an "expert" on Feynman inverse sprinkler problem
and how to misapply it to any situation, maybe you can answer a question
about it. While it's true that the sprinkler won't turn when water is
being sucked in, it's not true that no net force is generated by sucking
the water in. In fact, there is a net force generated. It's just not
in a direction that will turn the sprinkler.

In relation to your discussion about about equal and opposite, net net,
no net force, etc., how do you reconcile that with the fact that it's
not true for the inverse sprinkler problem?

Steve