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Aniculapeter
 
Posts: n/a
Default Dellenbaugh coefficient?

In metric The Dellenbaugh angel =

279 x SA x h
---------------
D x GM

279 x (Sailarea (triangular) x Heeling arm) / (Displacement x Metacentric
height)

It should illustrate the heeling angle at approximately 8 m/s.

I don't know what the Dellenbaugh coefficient it, but sounds as if it is
identical to the Dellenbaugh angle.

GM is metacentric height. Distance from G (gravitational center) to M
(metacenter).
h is heeling arm.
l is one ?


Peter S/Y Anicula



"William R. Watt" skrev i en meddelelse
...
its the angle of heel in a 16 mph wind (one pound per sq ft wind force).
the formula is ...

57.3 x SA x h x l
-----------------
D x GM

I know SA = sail area (sq ft)
D = displacement (pounds)

I don't know what h, l, and GM are.
Anybody know?

I think "h" is the height of the centre of effort of the sail. a note says
"from designed sail plan center to LWL plus 40% draft" it doesn't say if
the centerboard is up or down. I think it would be in feet.

"l" is "lpsf" in one location. I think that might be "lateral plane in sq

ft"
but not sure. Waterline plane?

Not a clue what GM might be. Some kind of moment?

Thanks.