Bart wrote:

A load on the line is 1000 lbs.

You have just lead a line through a block, around
an angle of 180 degrees. What is the load on the
sheave? [1 pt]

2000 lbs

For an angle of 90 degrees, what would be the load on
the sheave? [1 pt]

2000*sin(45)=1414 1bs @ 45 degrees.

At what angle does the sheave load match the line load?
[1 pt]

arcsin(1000/2000)=30 degrees (actual angle of line-block-line= 150
degrees)

Cheers
Marty