"James Gemmill" gemmilljim@hotmail,com wrote in message
...
make a tripod bridge with the scale as one foott of of the tripod.
Multipy the weight shown by three. Use two by sixes and two by fours
for the tripod.


Why a tripod?

My concern is that it over constrains the problem, and you could end up with
a major error it the weight was not distributed evenly between the three
legs. I suggest using a lever approach instead:

|______| - object being weighed
V=====^================V - lever
ground |scale|

| a | b | - the
distances between


Multiply the reading on the scale by the ratio of b/a. For best results,
make the points of contact (ground, scale and weigh point) as small as
possible so that there is less ambiguity on the distance measurements.

Rod