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Mr. Luddite Mr. Luddite is offline
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First recorded activity by BoatBanter: Aug 2013
Posts: 6,972
Default ??? upgrading shore power to 50A 220V

On 3/18/2014 2:12 PM, F*O*A*D wrote:
On 3/18/14, 1:50 PM, wrote:
On Tue, 18 Mar 2014 08:18:15 -0400, "Mr. Luddite"
wrote:

BTW, the answer to the question I asked is because the two "hot" legs
are 180 degrees out of phase relative to each other, so the net
current
flowing through the neutral leg adds algebraically. The current
through
the neutral leg can never exceed 200 amperes.


Algebra! Holy smoked salmon!


and heavy duty algebra at that.


You don't really get to algebra until you start talking about 3 phase
and it is actually more like geometry. (vectors)

The answer is usually the Sq/Rt of 3 tho. (where "208" comes from)



I thought the square root of 3 was 1.7 something or other, though maybe
you mean something different, because I don't recall an abbreviation of
"Sq/Rt." I do recall sq.rt and sq rt.



In three phase power circuits the total wattage is the average voltage
of each leg x the average current of each leg x a power factor x the
sq.rt of 3 (1.73)