"Earl Haase" wrote in message
...
I think we're getting into some number errors here folks.

10 sq mm broken back into wire diameter would be 10 / pi or 10 / 3.14.
If I'm thinking this through right in round figures that would give us
3.18 and the square root of that would be a wire with a diameter of 1.78
mm. Way too small for a starter wire. So something is wrong with our
numbers.


Earl
Area of circle = pi x Dia squared /4

therefore Dia = SQRT(Area x 4 / pi)

So your calcs should read:

Dia = SQRT(10 x 4/pi) = 3.6

As you say "Way too small for a starter wire".

Regards,
Brian