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Hi.
Could anyone advise please 1 led drawing 10mA off a 12volt car battery,how long would take to use up 1amp of the battery. Thanks. ..Baz -- Don't Thieve. The government doesn't like competition. |
Led
"ForeverArsenal" wrote in message et... Hi. Could anyone advise please 1 led drawing 10mA off a 12volt car battery,how long would take to use up 1amp of the battery. Thanks. .Baz Am I right in saying it would take 100hrs,could someone confirm please. |
Led
On Mon, 29 Dec 2008 20:38:07 -0000, "ForeverArsenal"
wrote in : "ForeverArsenal" wrote in message net... Hi. Could anyone advise please 1 led drawing 10mA off a 12volt car battery,how long would take to use up 1amp of the battery. Am I right in saying it would take 100hrs,could someone confirm please. Amp is current, not battery capacity. That's amp hours (current over time). Wikipedia: The battery capacity that battery manufacturers print on a battery is the product of 20 hours multiplied by the maximum constant current that a new battery can supply for 20 hours at 68 F° (20 C°), down to a predetermined terminal voltage per cell. A battery rated at 100 A·h will deliver 5 A over a 20 hour period at room temperature. Your LED is drawing 1/100 amp, so it would draw the same power in 100 hours as a 1 amp load would draw in one hour, or 1 amp hours of capacity. -- Very best wishes for the holiday season and for the coming new year, John |
Led
On Mon, 29 Dec 2008 20:38:07 -0000, "ForeverArsenal"
wrote: "ForeverArsenal" wrote in message net... Hi. Could anyone advise please 1 led drawing 10mA off a 12volt car battery,how long would take to use up 1amp of the battery. Thanks. .Baz Am I right in saying it would take 100hrs,could someone confirm please. I assume you mean "use 1 ampere-hour". 10 mA is 0.01 Amp (1/100 Amp), so it would take 100 hours for the 10 mA LED to consume 1 AH. -- Peter Bennett, VE7CEI peterbb4 (at) interchange.ubc.ca GPS and NMEA info: http://vancouver-webpages.com/peter Vancouver Power Squadron: http://vancouver.powersquadron.ca |
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"Peter Bennett" wrote in message news.com... On Mon, 29 Dec 2008 20:38:07 -0000, "ForeverArsenal" wrote: "ForeverArsenal" wrote in message snet... Hi. Could anyone advise please I assume you mean "use 1 ampere-hour". 10 mA is 0.01 Amp (1/100 Amp), so it would take 100 hours for the 10 mA LED to consume 1 AH. '''''''''''''''''''''''''''''''''''''''''''''''''' '''''''''''''''''''''''''''''''''''''''' Many thanks Peter Bennett and John Navas for your replies and infomation,appreciated. Best wishes to you both for the new year. Barry |
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ForeverArsenal wrote:
Hi. Could anyone advise please 1 led drawing 10mA off a 12volt car battery,how long would take to use up 1amp of the battery. Thanks. .Baz 100 hours. |
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Sjouke Burry" wrote in message
... ForeverArsenal wrote: Hi. Could anyone advise please 1 led drawing 10mA off a 12volt car battery,how long would take to use up 1amp of the battery. Thanks. .Baz 100 hours. Thanks. Baz -- Don't Thieve. The government doesn't like competition. " |
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On Mon, 29 Dec 2008 12:46:01 -0800, John Navas
wrote: On Mon, 29 Dec 2008 20:38:07 -0000, "ForeverArsenal" wrote in : "ForeverArsenal" wrote in message snet... Hi. Could anyone advise please 1 led drawing 10mA off a 12volt car battery,how long would take to use up 1amp of the battery. Am I right in saying it would take 100hrs,could someone confirm please. Amp is current, not battery capacity. That's amp hours (current over time). Wikipedia: The battery capacity that battery manufacturers print on a battery is the product of 20 hours multiplied by the maximum constant current that a new battery can supply for 20 hours at 68 F° (20 C°), down to a predetermined terminal voltage per cell. A battery rated at 100 A·h will deliver 5 A over a 20 hour period at room temperature. Your LED is drawing 1/100 amp, so it would draw the same power in 100 hours as a 1 amp load would draw in one hour, or 1 amp hours of capacity. Just shows that you cannot trust Wickipedia! That should read .. The battery capacity that battery manufacturers print on a battery is the product of "The hour rating" in hours multiplied by the maximum constant current that a new battery can supply for "The hour rating" at 68 F° (20 C°), down to a predetermined terminal voltage per cell. A battery rated at 100 A·h will deliver 100/(The hour rating) over "The hour rating" period at room temperature. "The hour rating" may be 20 it may be 5 depending upon the manufacturer and the area of the world that the battery is sold in. The Peukert exponent will mean that the 20 hour rating is NOT 4 times the 5 hour rating. The answer to the original question is therefore (because of Peukert). Based on a 20 hour rated battery a drain of 10ma will reduce the battery capacity by 1 Ampere Hour in a time that is a hell of a lot greater than 100 hours. Just for example based upon a 100Ah battery at a 20 hour rate with a Peukert of 1.3, a drain of .050A will actually look like .010A. Therefor a drain of .05A will pull 1Ah in 100 hours. Richard |
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In article , Richard Edwards wrote:
On Mon, 29 Dec 2008 12:46:01 -0800, John Navas wrote: On Mon, 29 Dec 2008 20:38:07 -0000, "ForeverArsenal" wrote in : "ForeverArsenal" wrote in message usnet... Hi. Could anyone advise please 1 led drawing 10mA off a 12volt car battery,how long would take to use up 1amp of the battery. Am I right in saying it would take 100hrs,could someone confirm please. Amp is current, not battery capacity. That's amp hours (current over time). Wikipedia: The battery capacity that battery manufacturers print on a battery is the product of 20 hours multiplied by the maximum constant current that a new battery can supply for 20 hours at 68 F° (20 C°), down to a predetermined terminal voltage per cell. A battery rated at 100 A·h will deliver 5 A over a 20 hour period at room temperature. Your LED is drawing 1/100 amp, so it would draw the same power in 100 hours as a 1 amp load would draw in one hour, or 1 amp hours of capacity. Just shows that you cannot trust Wickipedia! That should read .. Did you fix it ? Thats what edit is for. The battery capacity that battery manufacturers print on a battery is the product of "The hour rating" in hours multiplied by the maximum constant current that a new battery can supply for "The hour rating" at 68 F° (20 C°), down to a predetermined terminal voltage per cell. A battery rated at 100 A·h will deliver 100/(The hour rating) over "The hour rating" period at room temperature. "The hour rating" may be 20 it may be 5 depending upon the manufacturer and the area of the world that the battery is sold in. The Peukert exponent will mean that the 20 hour rating is NOT 4 times the 5 hour rating. The answer to the original question is therefore (because of Peukert). Based on a 20 hour rated battery a drain of 10ma will reduce the battery capacity by 1 Ampere Hour in a time that is a hell of a lot greater than 100 hours. Just for example based upon a 100Ah battery at a 20 hour rate with a Peukert of 1.3, a drain of .050A will actually look like .010A. Therefor a drain of .05A will pull 1Ah in 100 hours. Richard |
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