It would appear that Shen is replacing the prop of a boat with a
paddle wheel and locating it aft of the transom, as a follow up to
someone else's post, using the paddlewheel. However, in his example a
side-wheeler would work as long as you submerge the entire wheel.
Can you explain why the force exerted by the blades at those angles
would be equal....though opposite?

otn

Scott Vernon wrote:
"Shen44" wrote

hmmm let me try and draw a pitcher fer ya.
Your looking at this here paddle wheel just beneath the surface of the

water

(totally submerged), from the side, which is rotating clockwise through

360

deg.
It is being driven by a shaft coming out the stern of a boat,

longitudinally,

and the whole paddlewheel is located just aft of the transom. (kinda like

a RH

paddlewheel).
Now, are you trying to tell me that the amount of "push" that these

paddles

develope against the boat, is the same between 090 and 180 deg. rotation

as it

is between 270 and 360 deg ?


I would guess yes. But I don't know. And I was picturing a side wheeler.

Sv