NORDHAVN Rewrites Physics Textbooks
 

On Mon, 15 Oct 2007 21:17:22 -0600, "Bill" wrote
this crap:


"Bloody Horvath" wrote in message
.. .

Uh... hot air rises. How can water vapor be less dense than air?

You ****ing assholes have no idea of science.




I'm Horvath and I approve of this post.



http://en.wikipedia.org/wiki/Density_of_air

"The addition of water vapor to air (making the air humid) reduces the
density of the air, which may at first appear contrary to logic.
This occurs because the molecular mass of water (18) is less than the
molecular mass of air (around 29). For any gas, at a given temperature and
pressure, the number of molecules present is constant for a particular
volume. So when water molecules (vapor) are introduced to the air, the
number of air molecules must reduce by the same number in a given volume,
without the pressure or temperature increasing. Hence the mass per unit
volume of the gas (its density) decreases."


Good point. The water vapor changes the density of air. BUT... water
vapor is not denser than air.





I'm Horvath and I approve of this post.

NORDHAVN Rewrites Physics Textbooks
 

"Bloody Horvath" wrote in message
...
On Mon, 15 Oct 2007 21:17:22 -0600, "Bill" wrote
this crap:


"Bloody Horvath" wrote in message
. ..

Uh... hot air rises. How can water vapor be less dense than air?

You ****ing assholes have no idea of science.




I'm Horvath and I approve of this post.



http://en.wikipedia.org/wiki/Density_of_air

"The addition of water vapor to air (making the air humid) reduces the
density of the air, which may at first appear contrary to logic.
This occurs because the molecular mass of water (18) is less than the
molecular mass of air (around 29). For any gas, at a given temperature and
pressure, the number of molecules present is constant for a particular
volume. So when water molecules (vapor) are introduced to the air, the
number of air molecules must reduce by the same number in a given volume,
without the pressure or temperature increasing. Hence the mass per unit
volume of the gas (its density) decreases."


Good point. The water vapor changes the density of air. BUT... water
vapor is not denser than air.

Water vapor is not denser than air is correct. Air is denser.






I'm Horvath and I approve of this post.

NORDHAVN Rewrites Physics Textbooks
 

"Me" wrote in message
...
In article , "Bill"
wrote:

I have a scheme for tapping into the power of the rotating earth. I even
built an apparatus that worked for several years. Michael Faraday built a
small scale device working on the same principle. It is not perpertual
motion or any crackpot scheme. It does slow down the rotation of the
earth a
little and causes local weather changes (on a very small scale).

Bill

If what you say is TRUE, then the rest of us should make it our business
to KILL you and everyone who KNOWS about your device.........

You have invented a GLOBAL Disaster, as if you pull energy from the
Earths Rotational Momentum, then the Earth will obviously STOP Spinning,
and Life as we know it will CEASE. Your Device is kill us ALL, and
therefore is actually WORSE, for humanity, than GLOBAL WARMING......

Let us all start the GLOBAL Angular Momentum Crisis Insitute to deal
with this MONUMENTAL Crisis, in the making. Maybe I can even win the
Nobel Peace Prize, for this idea......

Me who wonders just how stupid humanity really is......

You have compelled me to reveal the device!

The device uses the rotation of the earth through its own magnetic field to
generate electricity. Such devices fall into the class of unipolar, or as
Gaynz prefers, homopolar generators. Faradays early devices used a fixed
magnet and rotating disc. However, the magnet can rotate with the disc as
shown in this reference:

http://www.physics.umd.edu/lecdem/ou...18unipolar.pdf

The earth has been modelled as a homopolar generator in the following
references:

http://www.spacedaily.com/news/earth-magnetic-00a.html

http://www.phy6.org/earthmag/dynamos2.htm

http://www.phy6.org/earthmag/dynamos.htm

So it is obvious to those practised in the art that a vertical conductor on
the earth's surface will develop a potential between the top and bottom of
the conductor due to unipolar induction. A radio tower develops a potential
between the bottom and top. Now, if the bottom of the tower is grounded and
the top designed to extract/feed free electrons from/to the atmosphere,
current will flow through the tower. A tower, a kite with a conducting
string, sea water all work also.

"Now why hasn't this been done before?", many of you are skeptically asking.
But it has:

http://en.wikipedia.org/wiki/Oleg_D._Jefimenko

He has written a book on the subject:

http://www.amazon.com/Electrostatic-...2573363&sr=1-6

As well as many other fine books:

http://www.amazon.com/s?ie=UTF8&sear...fimenko&page=1

Unfortunately the source of the current is incorrectly assigned to
"atmospheric electricity" rather than the unipolar effects of the earth
rotating through its magnetic field. Using the correct principle one can
properly design a collector tower capable of producing many amperes of
current for as long as the earth turns through its magnetic field. I have
built such a device and it has operated without interruption for years.

Bill

NORDHAVN Rewrites Physics Textbooks
 

http://www.youtube.com/watch?v=3aPQq...elated&search=

NORDHAVN Rewrites Physics Textbooks
 

On 16 Oct, 23:27, "Bill" wrote:

Using the correct principle one can
properly design a collector tower capable of producing many amperes of
current for as long as the earth turns through its magnetic field. I have
built such a device and it has operated without interruption for years.

Really? Published much about it?

Let's have a little think, shall we? The earth's magnetic flux density
has a maximum of around 0.07 mT. The linear velocity of the earth at
the equator is 40,000km / 24 hrs = 462 m/s. The absolute best you can
therefore hope to achieve with a homopolar generator is 462 m/s * 0.07
mT = 0.03 V/m.

A 20m mast will therefore give you a whopping 0.6V (maximum) to play
with.

Ian

NORDHAVN Rewrites Physics Textbooks
 

On Wed, 17 Oct 2007 07:54:02 -0600, "Bill" wrote:

http://www.youtube.com/watch?v=3aPQq...elated&search=

I missed the part where this has something to do with Nordhaven, or
even boats.

Casady

NORDHAVN Rewrites Physics Textbooks
 

On Wed, 17 Oct 2007 07:54:09 -0700, Ian
wrote:

Let's have a little think, shall we? The earth's magnetic flux density
has a maximum of around 0.07 mT. The linear velocity of the earth at
the equator is 40,000km / 24 hrs = 462 m/s. The absolute best you can
therefore hope to achieve with a homopolar generator is 462 m/s * 0.07
mT = 0.03 V/m.

A 20m mast will therefore give you a whopping 0.6V (maximum) to play
with.

More like 12 000 volts.

The earth has an electrical field of, average, 200 volts per vertical
foot. You can be well zapped by the charge on tower that is insulated
from the ground. The object sucks electrons from the air, and although
you don't get much current, the juice accumulates, like static charges
do. This has **** all to do with the earths magnetic field, which
rotates with the earth.

Casady

NORDHAVN Rewrites Physics Textbooks
 

"Richard Casady" wrote in message
...
On Wed, 17 Oct 2007 07:54:02 -0600, "Bill" wrote:

http://www.youtube.com/watch?v=3aPQq...elated&search=

I missed the part where this has something to do with Nordhaven, or
even boats.

Casady

I'm getting to that part. Be patient please.

NORDHAVN Rewrites Physics Textbooks
 

"Richard Casady" wrote in message
...


.. This has **** all to do with the earths magnetic field, which
rotates with the earth.

Casady

The source of the field rotates with the earth. The field itself is
decoupled from the source once it leaves the source. An single flux line, as
it expands into space, does not rotate with the earth. (How would it know
the motion of its source after it left it? This would require some type of
messenger wave capable of superluminal velocities). Think of a brief flash
of light toward the heavens given off by a flashlight aimed skyward on the
surface of the earth. Is the light's path a straight or curved?(To the
observer on earth it appears curved opposite to the rotation of the earth).
But is it straight or curved in space? Does the light pulse continue to
rotate with the earth? Now think of a series of pulses, do any of them
rotate with the earth? If the earth were suddenly to reverse rotation would
all the pulses emitted before the rotation change suddenly change their
curvature?

So the earths magnetic field does not rotate with the earth. It expands out
into space at the speed of light based upon the location/orientation of its
magnetic source at the instant it was created. Once it moves out of the
source, the source has no influence upon it. Likewise with charge. A slowly
spinning charged sphere does not have curved lines of force.

So how are you going to get 200 V/m from a wire? You can't. The wire shorts
the field, the voltage at the ends and all over it are equal because it is a
conductor. That 200 V/m figure is a high impedance electrostatic field. One
way to develop voltage across a conductor is to cut magnetic lines of force,
which my method does.

Bill

NORDHAVN Rewrites Physics Textbooks
 

On Wed, 17 Oct 2007 07:54:09 -0700, Ian
wrote:

The linear velocity of the earth at
the equator is 40,000km / 24 hrs = 462 m/s. The absolute best you can
therefore hope to achieve with a homopolar generator is 462 m/s * 0.07
mT = 0.03 V/m.

A 20m mast will therefore give you a whopping 0.6V (maximum) to play

Unfortunately your calculation is more or less meaningless, and I can
only hope you had a good calculator and didn't waste a lot of time on
it. Since the earth and its magnetic field rotate together, the
maximum velocity relative to the magnetic field, is precisely zero. So
zero voltage is what you get that way.

Of course you actually would get about 12 000 volts, but another way.
Static electricity. A big tower will hold a lot, and it has been known
to kill. Scientific American had an article detailing how to make a
5000 volt motor a pinwheel that uses corona discharge from the tips of
the blades, and spins pretty fast for a little chunk of aluminum foil.
Powered by a vertical wire.

Incidently, orbiting objects do move fast with respect to the field,
and a long wire will stretch out vertically due to tides. This will
creat drag, and lower the orbit if you extract any juice this way. On
the other hand, if you feed in juice from solar cells you get a
current in a magnetic field and have a weak motor, which could,
gradually raise the altitude of the orbit. You would use no reaction
mass, the attraction of the idea. I have seen calculations, probably
in Analog.

This is perhaps a place to use your nice calculation.

Casady