Jeff Morris wrote:



In other words, this site actually agrees with what I have been saying.
Frankly I owe an apology to the site's author, since I maligned it without
reading carefully. In fact, although it leads with a provocative line about a
"little known aspect of the moon's orbital motion," and has a rather confusing
diagram, its basic approach is correct and in full agreement with my claim.
Apparently the site was actually changed at some point about two years ago
because of complaints on another board.


The site certainly agrees with me. Don't confuse rotation of the earth
with rotation about the system center. Here is the exact quote and it's
concurrance with my view is as clear as day:

"1. The Effect of Centrifugal Force. It is this little known aspect of
the moon's orbital motion which is responsible for one of the two force
components creating the tides. As the earth and moon whirl around this
common center-of-mass, the centrifugal force produced is always directed
away from the center of revolution. All points in or on the surface of
the earth acting as a coherent body acquire this component of
centrifugal force. And, since the center-of-mass of the earth is always
on the opposite side of this common center of revolution from the
position of the moon, the centrifugal force produced at any point in or
on the earth will always be directed away from the moon. This fact is
indicated by the common direction of the arrows (representing the
centrifugal force Fc) at points A, C, and B in Fig. 1, and the thin
arrows at these same points in Fig. 2."

Note the "one of the two forces".

Cheers

Holy Back Pedal!!! Now you're claiming you agreed with me all along??? Just
22 hours ago we had this exchange:

Actually, applying it in this context is your problem. Centrifugal
acceleration
is constant, it doesn't vary across the surface of the Earth as you claim.
Remember, it doesn't even exist, its actually a reference frame shift.

It is a much larger force than differential gravity but you want to
ignore it? You are wrong Jeff, it does vary across the surface of the
earth Jeff -the Barycenter is at ~3/4 r! On the moon side it's ~1/7 as
large. Finally, (repeating yet again) it is the ____DIFFERENCE______
between inertial and gravity forces that make the tides. To say it's
only "differential gravity" (I shudder at that term) is clearly wrong -
this was a simple proof.


You actually provided the math that "proves" centrifugal force varies, and thus
causes tides much larger predicted by the accepted formula. Now you're
claiming you never meant that at all?


Right, Navie. Its the Constellation all over again.



"Nav" wrote in message
...


Jeff Morris wrote:



In other words, this site actually agrees with what I have been saying.
Frankly I owe an apology to the site's author, since I maligned it without
reading carefully. In fact, although it leads with a provocative line
about a
"little known aspect of the moon's orbital motion," and has a rather
confusing
diagram, its basic approach is correct and in full agreement with my claim.
Apparently the site was actually changed at some point about two years ago
because of complaints on another board.


The site certainly agrees with me. Don't confuse rotation of the earth
with rotation about the system center. Here is the exact quote and it's
concurrance with my view is as clear as day:

"1. The Effect of Centrifugal Force. It is this little known aspect of
the moon's orbital motion which is responsible for one of the two force
components creating the tides. As the earth and moon whirl around this
common center-of-mass, the centrifugal force produced is always directed
away from the center of revolution. All points in or on the surface of
the earth acting as a coherent body acquire this component of
centrifugal force. And, since the center-of-mass of the earth is always
on the opposite side of this common center of revolution from the
position of the moon, the centrifugal force produced at any point in or
on the earth will always be directed away from the moon. This fact is
indicated by the common direction of the arrows (representing the
centrifugal force Fc) at points A, C, and B in Fig. 1, and the thin
arrows at these same points in Fig. 2."

Note the "one of the two forces".

Cheers