Jeff Morris wrote:




So, you you're claiming the lunar tidal forces are 65 times the accepted values.


No I'm not saying that. The tidal forces are what they are ("accepted
values?"). I can see you are very stubborn. The point is that the
outward component due to rotation is much larger than the apparent
outward force due to the change in distance and gravity. It's a fact
-you've calculated it for yourself!


Or is my equation for centrifugal acceleration wrong?



Actually, applying it in this context is your problem. Centrifugal acceleration
is constant, it doesn't vary across the surface of the Earth as you claim.
Remember, it doesn't even exist, its actually a reference frame shift.



It is a much larger force than differential gravity but you want to
ignore it? You are wrong Jeff, it does vary across the surface of the
earth Jeff -the Barycenter is at ~3/4 r! On the moon side it's ~1/7 as
large. Finally, (repeating yet again) it is the ____DIFFERENCE______
between inertial and gravity forces that make the tides. To say it's
only "differential gravity" (I shudder at that term) is clearly wrong -
this was a simple proof.

Cheers