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Peter Scott August 11th 04 11:36 PM

More anchor questions
 
I have an anchor and chain and line.
Is this how to calculate the length of the line
Chart reads 5' add 3' to the deck add local tide data 9.7' total of 17.7
multiply by 5 gives 88'. This seems like a lot and will make a very large
circle if the wind changes.
Thanks Peter




Jeff Morris August 12th 04 12:13 AM

More anchor questions
 
That's about what you need. You're using 5 to 1 scope, which many would
consider the minimum for security. 3 to 1 is the absolute minimum for most
anchors to hold at all; most texts say 7 to 1 or 10 to 1 is better for heavy
weather.

Using more chain reduces the need for a lot scope, but you also need some nylon
line as a shock absorber, so even if you go to all chain, you need a nylon
"snubber."

FWIW, I use 50 feet of chain, and always let that all out, plus a fair amount of
nylon. I almost always have at least 100 feet of rode out. While that seems
like a lot, its only 3 boat lengths. Think of how much larger it would be if
the anchor dragged.


"Peter Scott" wrote in message
. ..
I have an anchor and chain and line.
Is this how to calculate the length of the line
Chart reads 5' add 3' to the deck add local tide data 9.7' total of 17.7
multiply by 5 gives 88'. This seems like a lot and will make a very large
circle if the wind changes.
Thanks Peter






Capt. Mooron August 12th 04 12:13 AM

More anchor questions
 
No! It's not the way.

Five feet of depth and a tide of 9.7 feet???!!!! what are you .... a
Looney?

300 feet of 1/2" line attached with a swivel shackle to at least 30 feet of
chain. Anchor at 5:1 scope to 7:1 scope is rule of thumb.

In 20 feet of water you should have 100 feet of rode out from the anchor
roller to the anchor. The anchor needs to be set... but that's another
chapter.

Good Grief!!

CM




"Peter Scott" wrote in message
. ..
| I have an anchor and chain and line.
| Is this how to calculate the length of the line
| Chart reads 5' add 3' to the deck add local tide data 9.7' total of 17.7
| multiply by 5 gives 88'. This seems like a lot and will make a very large
| circle if the wind changes.
| Thanks Peter
|
|
|



Jeff Morris August 12th 04 12:31 AM

More anchor questions
 
"Capt. Mooron" wrote in message
...
No! It's not the way.

Five feet of depth and a tide of 9.7 feet???!!!! what are you .... a
Looney?


What's the problem? I'll admit it doesn't often work out this way, but there's
nothing wrong with it, assuming you draw less than 5 feet, and check for drain
tides.




300 feet of 1/2" line attached with a swivel shackle to at least 30 feet of
chain. Anchor at 5:1 scope to 7:1 scope is rule of thumb.

In 20 feet of water you should have 100 feet of rode out from the anchor
roller to the anchor. The anchor needs to be set... but that's another
chapter.

Good Grief!!

CM




"Peter Scott" wrote in message
. ..
| I have an anchor and chain and line.
| Is this how to calculate the length of the line
| Chart reads 5' add 3' to the deck add local tide data 9.7' total of 17.7
| multiply by 5 gives 88'. This seems like a lot and will make a very large
| circle if the wind changes.
| Thanks Peter
|
|
|





Jonathan Ganz August 12th 04 12:41 AM

More anchor questions
 
"Peter Scott" wrote in message
...
I have an anchor and chain and line.
Is this how to calculate the length of the line
Chart reads 5' add 3' to the deck add local tide data 9.7' total of 17.7
multiply by 5 gives 88'. This seems like a lot and will make a very large
circle if the wind changes.
Thanks Peter


Sounds about right... what's wrong with making a change if the wind
does indeed change? Nothing is going to remain constant except change.
--
Jonathan Ganz (j gan z @ $ail no w.c=o=m)
http://www.sailnow.com
"If there's no wind, row."



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