2 point question
 

yes I know, that is the point (no pun intended)
Scout

"JAXAshby" wrote in message
...
a dot is not a vector.

that's what I was thinking but didn't want to assume anything : )
Scout

"Remco Moedt" wrote in message
.. .
On Sun, 04 Jul 2004 04:53:15 GMT, "Bart Senior"
wrote:

You sail directly East for 14 hours,
then South for 14 hours,
and then West for 14 hours,
and then North again for 14 hours.

Now if you draw a vector between your starting
position and your final position. What would you
call that vector?

A dot. :-)


Cheers!


Remco

2 point question
 

Bart Senior wrote:

Now if you draw a vector between your starting
position and your final position. What would you
call that vector?

Track made good.


--
Wally
www.artbywally.com
www.wally.myby.co.uk

2 point question
 

Capt. Mooron wrote:

To be accurate you would need the start and end coordinates. The
vector between the 2 if any could be calculated.... but the point is
moot. If all speeds and bearings [no leeway] were constant you would
be at your starting point.

Speeds haven't been stated, so they can't be assumed to be constant.


I believe Bart is having some fun! ;-)

The spanner in the works is idea that it's a round trip.


--
Wally
www.artbywally.com
www.wally.myby.co.uk

2 point question
 

"Wally" wrote in message
...
| Capt. Mooron wrote:
|
| To be accurate you would need the start and end coordinates. The
| vector between the 2 if any could be calculated.... but the point is
| moot. If all speeds and bearings [no leeway] were constant you would
| be at your starting point.
|
| Speeds haven't been stated, so they can't be assumed to be constant.

Without the speeds you have no position to calc a vector... thus constant
speed must be assumed.

|
|
| I believe Bart is having some fun! ;-)
|
| The spanner in the works is idea that it's a round trip.

Without the speeds that determination can neither be assumed nor denied.

Of course the vector could be 0 degrees T. ;-)

CM

2 point question
 

Capt. Mooron wrote:

Speeds haven't been stated, so they can't be assumed to be constant.

Without the speeds you have no position to calc a vector... thus
constant speed must be assumed.

ISTM that speed is unknown, so no assumption can be made.


I believe Bart is having some fun! ;-)
The spanner in the works is idea that it's a round trip.

Without the speeds that determination can neither be assumed nor
denied.

I meant that the wording of the question is such that the unwary might
assume that it is a round trip - which it could be - but it might not be.
The vector can be anything, IOW, so I think he's looking for the name of the
resultant vector, and not its magnitude.


--
Wally
www.artbywally.com
www.wally.myby.co.uk

2 point question
 

our physics professor used to smack our knuckles for saying speed and not
velocity. What a grump.
Scout

"Capt. Mooron" wrote in message
...

"Wally" wrote in message
...
| Capt. Mooron wrote:
|
| To be accurate you would need the start and end coordinates. The
| vector between the 2 if any could be calculated.... but the point is
| moot. If all speeds and bearings [no leeway] were constant you would
| be at your starting point.
|
| Speeds haven't been stated, so they can't be assumed to be constant.

Without the speeds you have no position to calc a vector... thus constant
speed must be assumed.

|
|
| I believe Bart is having some fun! ;-)
|
| The spanner in the works is idea that it's a round trip.

Without the speeds that determination can neither be assumed nor denied.

Of course the vector could be 0 degrees T. ;-)

CM

2 point question
 

"Wally" wrote in message

| I meant that the wording of the question is such that the unwary might
| assume that it is a round trip - which it could be - but it might not be.
| The vector can be anything, IOW, so I think he's looking for the name of
the
| resultant vector, and not its magnitude.


Astute.... but COG has been deprived of SOG and my ETA is now as dubious as
my DR ... now I need a drink of Rhumb! :-)

CM

2 point question
 

btw - I've used my saved sailing gps tracks in the classroom - the physics
teacher projected them onto the board and had the students work out vectors
and so forth.
Scout

"Bart Senior" wrote in message
. ..
You sail directly East for 14 hours,
then South for 14 hours,
and then West for 14 hours,
and then North again for 14 hours.

Now if you draw a vector between your starting
position and your final position. What would you
call that vector?

2 point question
 

So what did your Prof refer to the vector between your departure coordinates
and your arrival coordinates?

CM

"Scout" wrote in message
...
| btw - I've used my saved sailing gps tracks in the classroom - the physics
| teacher projected them onto the board and had the students work out
vectors
| and so forth.
| Scout
|
| "Bart Senior" wrote in message
| . ..
| You sail directly East for 14 hours,
| then South for 14 hours,
| and then West for 14 hours,
| and then North again for 14 hours.
|
| Now if you draw a vector between your starting
| position and your final position. What would you
| call that vector?
|
|
|
|

2 point question
 

Capt. Mooron wrote:

Astute.... but COG has been deprived of SOG and my ETA is now as
dubious as my DR ... now I need a drink of Rhumb! :-)

I now realise that the whole journey is a red herring - he never said
anything about the final position being worked out as a DR. It could just as
easly be observed or GPS. He might as well have said...

You start at X, sail about for a bit, and finish at Y.
What's the vector from X to Y called?


--
Wally
www.artbywally.com
www.wally.myby.co.uk