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2 point question
In most of my posts on this subject I have mentioned a trip going east
north west and south. In this post I referred to the original question, and in the question the trip goes east south west and north, so in this post the destination would be east of the start-point. Sorry if anyone got confused. Peter S/Y Anicula "Peter S/Y Anicula" skrev i en meddelelse ... I was taught that: Speed is the forward motion through the water Leeway is the sideways movement of the boat through the water Current is the movement of the water over the ground Steered course is the way you point Sailed course is the direction that you move through the water Course over the ground (is that called course made good ?) is the direction you move over the ground etc. If one sails as you described in the question (on the northern hemisphere), one sails toward a destination B that is west of the starting-point A (if there were no current). The position after 56 hours is point C. So, If your teacher taught you that when you sail from A toward B and arrive at C then AC is the "current" then he must have been an electrician and not a sailor. You could justify to call BC for current, though the distance might be a result of more than just the surface-waters movement over the ground. Peter A/Y Anicula "Bart Senior" skrev i en meddelelse et... In most places where people are sailing, current would be the greater effect. Other factors, can all be lumped into something that for lack of a better word is called current. That is what I was taught. DSK wrote Yes it is, but a minute of longitude differs in length as you go north and/or south. |
2 point question
On the south pole, even if you insist on going only 14 nm on every
leg, you could reach the 28 nm that you mentioned in your earlier post, so you wouldn't have to admit that you have a really bad compass. You might have to bring an iceboat though. Peter S/Y Anicula "Wally" skrev i en meddelelse ... Peter S/Y Anicula wrote: 1.86nm is not far enough for me: For one thing, I can sail much faster than your 1 knot. If I can do 6 knots, the figure would be 11.16 nm, assuming your math is correct, but you can do better than that, even in your slow boat. The misapprehension of the question that led to this discourse was concerned with distances of 14nm. You might sail the course six times faster, but you'll still be 1.86nm from the start. Why don't you take a trip to the South Pole ? Because my ice-breaker would founder on the mountains. -- Wally www.artbywally.com www.wally.myby.co.uk |
2 point question
Peter S/Y Anicula wrote:
On the south pole, even if you insist on going only 14 nm on every leg, you could reach the 28 nm that you mentioned in your earlier post, ... How? -- Wally www.artbywally.com www.wally.myby.co.uk |
2 point question
You would start with the outer circle going east then go closer to the
pole moving south... If the inner circle has an arc of 180 degrees plus the arc of the outer circle, then the end-point should be opposite the start-point, and the distance over the pole would be 2 x length of legs plus diameter of inner circle: more than 28 nm in at 1 knot and more than 168 nm at 6 knot. Peter S/Y Anicula "Wally" skrev i en meddelelse ... Peter S/Y Anicula wrote: On the south pole, even if you insist on going only 14 nm on every leg, you could reach the 28 nm that you mentioned in your earlier post, ... How? -- Wally www.artbywally.com www.wally.myby.co.uk |
2 point question
The terminology is not quite right, substitute inner circle with the
leg along the inner circle... So it should be: You would start with the leg along the outer circle going east then go closer to the pole moving south... If the leg along the inner circle has an arc of 180 degrees plus the arc of the leg along the outer circle, then the end-point should be opposite the start-point, and the distance over the pole would be 2 x length of legs plus diameter of inner circle: more than 28 nm in at 1 knot and more than 168 nm at 6 knot. Peter S/Y Anicula "Peter S/Y Anicula" skrev i en meddelelse ... You would start with the outer circle going east then go closer to the pole moving south... If the inner circle has an arc of 180 degrees plus the arc of the outer circle, then the end-point should be opposite the start-point, and the distance over the pole would be 2 x length of legs plus diameter of inner circle: more than 28 nm in at 1 knot and more than 168 nm at 6 knot. Peter S/Y Anicula "Wally" skrev i en meddelelse ... Peter S/Y Anicula wrote: On the south pole, even if you insist on going only 14 nm on every leg, you could reach the 28 nm that you mentioned in your earlier post, ... How? -- Wally www.artbywally.com www.wally.myby.co.uk |
2 point question
Both Peter and Wally deserve 5 points for taking this
silly question so far. Bart Peter S/Y Anicula wrote The terminology is not quite right, substitute inner circle with the leg along the inner circle... So it should be: You would start with the leg along the outer circle going east then go closer to the pole moving south... If the leg along the inner circle has an arc of 180 degrees plus the arc of the leg along the outer circle, then the end-point should be opposite the start-point, and the distance over the pole would be 2 x length of legs plus diameter of inner circle: more than 28 nm in at 1 knot and more than 168 nm at 6 knot. Peter S/Y Anicula "Peter S/Y Anicula" skrev i en meddelelse ... You would start with the outer circle going east then go closer to the pole moving south... If the inner circle has an arc of 180 degrees plus the arc of the outer circle, then the end-point should be opposite the start-point, and the distance over the pole would be 2 x length of legs plus diameter of inner circle: more than 28 nm in at 1 knot and more than 168 nm at 6 knot. Peter S/Y Anicula "Wally" skrev i en meddelelse ... Peter S/Y Anicula wrote: On the south pole, even if you insist on going only 14 nm on every leg, you could reach the 28 nm that you mentioned in your earlier post, ... How? -- Wally www.artbywally.com www.wally.myby.co.uk |
2 point question
Peter S/Y Anicula wrote:
The terminology is not quite right, substitute inner circle with the leg along the inner circle... So it should be: You would start with the leg along the outer circle going east then go closer to the pole moving south... I hadn't realised it would work differently at the south pole... I'll do some numbers later and see what I come up with. If the leg along the inner circle has an arc of 180 degrees plus the arc of the leg along the outer circle, then the end-point should be opposite the start-point, That doesn't quite sound right - if the leg along the outer circle, plus the leg along the inner circle, add up to a total of 180 degrees longitude, then the end point would be opposite the start point. and the distance over the pole would be 2 x length of legs plus diameter of inner circle: more than 28 nm in at 1 knot and more than 168 nm at 6 knot. Yup. Proving that my compass does indeed work, in some places at least. -- Wally www.artbywally.com www.wally.myby.co.uk |
2 point question
Bart Senior wrote:
Both Peter and Wally deserve 5 points for taking this silly question so far. Ah, bonus points for waffling... (The apple's in the post, teach!) -- Wally www.artbywally.com www.wally.myby.co.uk |
2 point question
Wally wrote:
If one starts from 7nm N of the equator, and goes ESWN, one ends up at the start point. Right! I didn't think of that angle... ... Starting on the equator, I get 0.000116nm - 0.215m. Now that I have my referance library and a spreadsheet instead of a pocket calculator and faulty memory, I'll try again. It's a more interesting problem than I thought it'd be.... now I have another question, would the offset be constant as you move further north or south? No, it increases. And the change isn't linear. Yes, I realized this thinking about it on the drive home. So what is it proportional to, the arcsine? You and Peter deserve your points. Maybe one day Taddy will write a poem about you... now there's something to brag about to your grandkids... Fresh Breezes- Doug King |
2 point question
Wally wrote:
If the leg along the inner circle has an arc of 180 degrees plus the arc of the leg along the outer circle, then the end-point should be opposite the start-point, That doesn't quite sound right - if the leg along the outer circle, plus the leg along the inner circle, add up to a total of 180 degrees longitude, then the end point would be opposite the start point. If you count the arc with sign, whitch is probably the right thing to do, you are right. I just counted the size - independent of direction. Peter S/Y Anicula "Wally" skrev i en meddelelse ... Peter S/Y Anicula wrote: The terminology is not quite right, substitute inner circle with the leg along the inner circle... So it should be: You would start with the leg along the outer circle going east then go closer to the pole moving south... I hadn't realised it would work differently at the south pole... I'll do some numbers later and see what I come up with. If the leg along the inner circle has an arc of 180 degrees plus the arc of the leg along the outer circle, then the end-point should be opposite the start-point, That doesn't quite sound right - if the leg along the outer circle, plus the leg along the inner circle, add up to a total of 180 degrees longitude, then the end point would be opposite the start point. and the distance over the pole would be 2 x length of legs plus diameter of inner circle: more than 28 nm in at 1 knot and more than 168 nm at 6 knot. Yup. Proving that my compass does indeed work, in some places at least. -- Wally www.artbywally.com www.wally.myby.co.uk |
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