yeah, sure.

I, on the other hand prefer a visual
memory method.

Shen

LOL We always knew all those hours walking the bridgewings weren't
wasted!!

otn

Shen44 wrote:
Subject: uffda.
From: (JAXAshby)
Date: 03/12/2004 16:41 Pacific Standard Time
Message-id:

answer is: 65024

literally, done in my head that fast.

no smoke, no mirrors.

however, there was a "trick", two actually.



ewwww , tricky...you needed to use tricks. I, on the other hand prefer a visual
memory method.

Shen

Subject: uffda.
From: (JAXAshby)

Gee, Jax, I'm sorry your "visual memory" capabilities aren't exactly up to
mine.... we do have our individual crosses to bear, don't we. (statement, not
question)

Shen


yeah, sure.

I, on the other hand prefer a visual
memory method.

Shen

bject: uffda.
From: otnmbrd
Date: 03/12/2004 17:34 Pacific Standard Time
Message-id: .net

LOL We always knew all those hours walking the bridgewings weren't
wasted!!

otn

Yup. I started with double digits and worked up from there.

Shen

Subject: uffda.
From: (JAXAshby)
Date: 03/12/2004 17:28 Pacific Standard Time
Message-id:

bull. there is no intuitive way to calculate the product of those numbers in
that way, any more than you can calc a 4th root of a number algabraicly with
a
pencil and paper.

Sorry Jax, but "intuitive" has nothing to do with it. As stated, it's a visual
memory thing that I do that has nothing to do with tricks of multiplication
..... it's very straight forward and simple (but probably beyond your limited
reasoning and visualization skills)

There ARE ways to calc that product in one's head, but not in the fashion you
claimed. None.

sorry, dude.

Hey, don't apologize. As stated, my method is beyond your abilities and
probable comprehension .... actually, I can't explain it to myself, other than
to say it's a visual memory thingy.

Shen

bull. not even remotely possible. there is no relationship between the
numbers and the product as you claim.

Or ...

.... would you like to make mention of the relationship?

We will wait no more than a few hours.

bull. there is no intuitive way to calculate the product of those numbers
in
that way, any more than you can calc a 4th root of a number algabraicly with
a
pencil and paper.

Sorry Jax, but "intuitive" has nothing to do with it. As stated, it's a
visual
memory thing that I do that has nothing to do with tricks of multiplication
.... it's very straight forward and simple (but probably beyond your limited
reasoning and visualization skills)

There ARE ways to calc that product in one's head, but not in the fashion
you
claimed. None.

sorry, dude.

Hey, don't apologize. As stated, my method is beyond your abilities and
probable comprehension .... actually, I can't explain it to myself, other
than
to say it's a visual memory thingy.

Shen

What's so hard about doing 4th roots with pencil and paper?



"JAXAshby" wrote in message
...
bull. there is no intuitive way to calculate the product of those numbers in
that way, any more than you can calc a 4th root of a number algabraicly with a
pencil and paper.

wanna show us how?

]okay group, watch now how jeffies blathers on for days telling us that what
with his degree in physics and all that he can do it easily. if I say he can
not he will get all snippy. he couldn't tell us how RDF worked how is he going
to tell us how to do 4th roots with pencil and paper.]

jeffies? do note the word algebraicly was there. in other words, SWAGing is
not the answer.

What's so hard about doing 4th roots with pencil and paper?



"JAXAshby" wrote in message
...
bull. there is no intuitive way to calculate the product of those numbers
in
that way, any more than you can calc a 4th root of a number algabraicly
with a
pencil and paper.

Well, I wouldn't say its so easy that jaxie can follow, but there are all sorts
of techniques that have been developed over the years. Computers don't use
"magic" to calculate complex functions, there are often just programmed to
follow algorithms developed many years ago by people like Newton. Jaxie forgets
that this is what I did for a living.

To compute a 4th root, using Newton's method:

Assume you want to compute x = a^(1/4)
Make a guess at the answer, call it x1. Then compute the next guess, x2, as
follows:
x2 = x1 - (x1^4 - a)/(4 * x1^3)
iterate again as
x3 = x2 - (x2^4 - a)/(4 * x2^3)

When the results get sufficiently close, you have an answer. Often only 3 or 4
iterations are needed. Similar techniques can be used to calculate the roots of
polynomials.

I used the square root version of this a number of times. In the days before
"Floating Point Units" in computers considerable time savings (a factor of 10 or
more) could be had by adjusting the algorithms to match the input data and
desired accuracy.




"JAXAshby" wrote in message
...
wanna show us how?

]okay group, watch now how jeffies blathers on for days telling us that what
with his degree in physics and all that he can do it easily. if I say he can
not he will get all snippy. he couldn't tell us how RDF worked how is he
going
to tell us how to do 4th roots with pencil and paper.]

jeffies? do note the word algebraicly was there. in other words, SWAGing is
not the answer.

What's so hard about doing 4th roots with pencil and paper?



"JAXAshby" wrote in message
...
bull. there is no intuitive way to calculate the product of those numbers
in
that way, any more than you can calc a 4th root of a number algabraicly
with a
pencil and paper.

jeffies, that is NOT algebraic. Ask your wife to explain the term to you.

a bit of a hint for you jeffies. algebraic would give you precision to as many
decimals was you might wish to calc with accuracy to the next to last digit
calc'd.

go ahead. tell us how to do that with a pencil and paper. Tell you what.
Tell us how to do square roots *algebraically* with a pencil and paper.

ask your wife to explain square roots.

Well, I wouldn't say its so easy that jaxie can follow, but there are all
sorts
of techniques that have been developed over the years. Computers don't use
"magic" to calculate complex functions, there are often just programmed to
follow algorithms developed many years ago by people like Newton. Jaxie
forgets
that this is what I did for a living.

To compute a 4th root, using Newton's method:

Assume you want to compute x = a^(1/4)
Make a guess at the answer, call it x1. Then compute the next guess, x2, as
follows:
x2 = x1 - (x1^4 - a)/(4 * x1^3)
iterate again as
x3 = x2 - (x2^4 - a)/(4 * x2^3)

When the results get sufficiently close, you have an answer. Often only 3 or
4
iterations are needed. Similar techniques can be used to calculate the roots
of
polynomials.

I used the square root version of this a number of times. In the days before
"Floating Point Units" in computers considerable time savings (a factor of 10
or
more) could be had by adjusting the algorithms to match the input data and
desired accuracy.




"JAXAshby" wrote in message
...
wanna show us how?

]okay group, watch now how jeffies blathers on for days telling us that
what
with his degree in physics and all that he can do it easily. if I say he
can
not he will get all snippy. he couldn't tell us how RDF worked how is he
going
to tell us how to do 4th roots with pencil and paper.]

jeffies? do note the word algebraicly was there. in other words, SWAGing
is
not the answer.

What's so hard about doing 4th roots with pencil and paper?



"JAXAshby" wrote in message
...
bull. there is no intuitive way to calculate the product of those
numbers
in
that way, any more than you can calc a 4th root of a number algabraicly
with a
pencil and paper.